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Title: Linear Algebra
Description: This paper provides 45 solved Multiple Choice Questions on Vector Spaces topic for purpose of preparation of exams and tests.

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Linear Algebra
Topic:

Vector Spaces

Multiple Choice Questions for Exam Preparation

1
...
The set of complex numbers ā„‚ = {š‘Ž + š‘šœ„|š‘Ž, š‘ ∈ š¹} is a vector space over š¹ =
?
a) ā„‚
b) ā„
c) ā„š
d) All of above
3
...

a)
b)
c)
d)

d) Both (b) and (c)

Which statement is true?
If F is a subfield of E, then E is a vector space over F
The set š‘† = {(1,0), (2,0)} serves as basis of ā„2
š‘€š‘šĆ—š‘› (ā„) is a vector space over ā„ only if š‘š ≠ š‘›
ā„‚ is not a vector space over ā„š

5
...


d) Y-axis

Let š‘‰ be a vector space over š¹, then any summand of the form
š‘Ž1 š‘£1 + š‘Ž2 š‘£2 + ⋯ + š‘Žš‘› š‘£š‘› is called Linear Combination of š‘£1 , š‘£2 , … , š‘£š‘› ∈ š‘‰, š‘Žš‘– , š‘  ∈ š¹ where?
a) š‘£1 , š‘£2 , … , š‘£š‘› are linearly dependent vectors
b) š‘£1 , š‘£2 , … , š‘£š‘› are unique vectors
c) š‘£1 , š‘£2 , … , š‘£š‘› are linearly independent vectors
d) Both (a) and (c)
7
...
If V = ā„, š¹ = ā„š, then span(√5) is equal to?
a) ā„š
b) ā„šā€²
c) ā„

d) None of these

9
...

The basis of a vector space š‘‰ over a field š¹ contains:
a) Every independent vector of š‘‰
b) Dependent and independent vectors
c) Finite number of vectors
d) Vectors which span the vector space š‘½
11
...


If š‘Š = {[

13
...

If š‘Š = {(š‘Ž, š‘, š‘)|š‘Ž = š‘ = š‘; š‘Ž, š‘, š‘ ∈ ā„} is a subspace of vector space š‘‰ = ā„3 , then what will be
geometrical representation of W ?
a) Points in Space
b) Line passing through origin in space
c) Plane passing through origin in space
d) Surface passing through origin in space
15
...

Let V is a vector space over field F and for any subset S of V where š‘† = āˆ… ,then
a) span(š‘†) = š‘‰
b) span(š‘ŗ) = {šŸŽ}
c) span(š‘†) = {0} ∩ š‘‰
d) span(š‘†) = {0} ∪ š‘‰
17
...

Two vectors š‘¢ and š‘£ in ā„3 are linearly dependent iff:
a) They lie on same line through the origin
b) One is scalar multiple of other
c) Both vectors are equal

d) All of above
19
...

Consider a system š“š‘‹ = 0 of linear equations, where š“ = š‘€2Ɨ2 (š¾), then which one is true?
a) š‘æ ∈ š‘²šŸ , where K is any field
b) Zero vector does not belong to its solution set
c) The Solution set W of given system is subspace of ā„š‘›
d) Given system is non-homogeneous system
21
...

a) 3

1
What will be the rank of matrix š“ = [ 3
āˆ’1
3
b) 2

āˆ’2
1
āˆ’5
8

0 4
1 0 ]?
āˆ’1 8
2 āˆ’12
c) 1

d) 4

23
...

a) 1

If š‘ˆ = {(š‘Ž, 2š‘Ž): š‘Ž ∈ ā„} and š‘‰ = {(š‘, 3š‘): š‘ ∈ ā„}, then dim(š‘ˆāØš‘‰) =?
b) 3
c) 2

d) 4

25
...

If š‘‰ = š‘ƒ2 (š‘”) and š‘† = {(š‘” + 2), (š‘” āˆ’ 7), (š‘” 2 + 2š‘” + 1)}, then what will be the coordinate vector [š‘£]š‘ 
of š‘£ = š‘” 2 āˆ’ 6š‘” + 10 relative to š‘†?
a) [3, āˆ’4,2]
c) [āˆ’2,7
...
2]
d) [āˆ’šŸ“
...

If š‘‰ = ā„3 and coordinate vector of š‘£ = (5,2,7) is [š‘£]š‘  = [5,2,7], then what is basis relative to š‘£?
a) š‘†1 = {(1, āˆ’1,0), (1,1,0), (0,1,1)}
c) š‘ŗšŸ = {(šŸ, šŸŽ, šŸŽ), (šŸŽ, šŸ, šŸŽ), (šŸŽ, šŸŽ, šŸ)}
b) š‘†3 = {(āˆ’1,0,1), (0,0,1), (1,1,0)}
d) š‘†4 = {(0,0,0), (1,1,0), (1,0,1)}
28
...


What will be the dimension of subspace spanned by coordinate vectors:
[š“] = [1,2,6,0,0,0], [šµ] = [2,3,4,1, āˆ’1, āˆ’3], [š¶ ] = [2,0,7,3,4, āˆ’2]
a) 1
b) 2
c) 3
30
...
Then which mapping is determined by š“?
a) š‘­š‘Ø : š‘²š’ Ɨ š‘²š’Ž
b) š¹š“ : š¾ š‘› Ɨ ā„
c) š¹š“ : ā„ Ɨ š¾ š‘š
31
...

Which one of the following statements is true?
a) Every linear mapping takes zero vector into the zero vector
b) In linear mapping š¹: š‘‰ → š‘ˆ, both V and U are vector spaces over same field K
c) š¹ (š‘„ ) = š‘„ š‘› is linear mapping if š‘› = 1
d) A linear mapping of the form š‘­: š‘½ → ā„š’ is called Linear Transformation
33
...

Let š¹: š‘‰ → š‘ˆ be a Linear Mapping then which one is true?
a) š¾š‘’š‘Ÿš¹ = {š‘£šœ–š‘ˆ: š¹ (š‘£) = 0}
c) Kernal of š¹ is a subspace of š‘ˆ
b) Image of š¹ is a subspace of š‘‰
d) None of these
35
...

Which one of the following integers can be dimension of an algebra š“(š‘‰) of linear map?
a) 32
c) 49
b) 28
d) 88
37
...

Which one of the following linear operators is not invertible?
a) š¹: ā„2 → ā„2 š‘‘š‘’š‘“š‘–š‘›š‘’š‘‘ š‘š‘¦ š¹ (š‘„, š‘¦) = (2š‘„ + š‘¦, 3š‘„ + 2š‘¦)
b) š‘®: ā„šŸ → ā„šŸ š’…š’†š’‡š’Šš’š’†š’… š’ƒš’š š‘®(š’™, š’š) = (š’™ + š’š, š’™ āˆ’ šŸš’š, šŸ‘š’™ + š’š)
c) š»: ā„2 → ā„2 š‘‘š‘’š‘“š‘–š‘›š‘’š‘‘ š‘š‘¦ š» (š‘„, š‘¦) = (š‘¦, š‘„)
d) Both (a) and (b)
Which one of the following 2 Ɨ 2 matrix maps (1,3)š‘‡ and (1,4)š‘‡ into (āˆ’2,5)š‘‡ and (3, āˆ’1)š‘‡ ?
13 āˆ’2
āˆ’šŸšŸ• šŸ“
a) š‘Ø = [
]
c) š¶ = [
]
21 7
šŸšŸ‘ āˆ’šŸ”
1 āˆ’1
23 āˆ’9
b) šµ = [
]
d) š· = [
]
11 4
0 2

39
...


Consider two basis of ā„3 :
š‘† = {(1,2), (0,1)} & š‘† ′ = {(2,1), (āˆ’1,3)}, then what will be transition matrix from S to

S’?
āˆ’1 2
a) š‘ƒ = [
]
0 āˆ’3
21 11
b) š‘ƒ = [
]
8
4

1 2
]
4 āˆ’6
šŸ āˆ’šŸ
d) š‘· = [
]
āˆ’šŸ‘ šŸ“
c) š‘ƒ = [

41
...

Consider šæ: ā„2 → ā„2 defined by as L is reflection of ā„2 about š‘¦ = š‘„
...

Let š¹ (š‘„, š‘¦) = (2š‘„ + š‘¦, š‘„ āˆ’ 3š‘¦) and š‘† = {(1, āˆ’2), (2, āˆ’5)}, then for š‘£ = (5, āˆ’7) which one is
[š¹(š‘£)]š‘  ?
a) (āˆ’55,33)š‘‡
c) (šŸ‘, šŸšŸ”)š‘»
b) (8, āˆ’6)š‘‡
d) (āˆ’7, āˆ’5)š‘‡
44
...

Consider a linear mapping : ā„š‘› → ā„š‘š , then which statement is true?
a) š‘›š‘¢š‘™š‘™š‘ š‘(š“) = (š‘Ÿš‘œš‘¤š‘ š‘(š“))⊄
b) For š‘¤ ∈ š‘Ÿš‘œš‘¤š‘ š‘(š“) and š‘£ ∈ š‘›š‘¢š‘™š‘™š‘ š‘(š“), we get š‘¤
Title: Linear Algebra
Description: This paper provides 45 solved Multiple Choice Questions on Vector Spaces topic for purpose of preparation of exams and tests.