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Title: Cell respiration
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture

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Cell respiration

Topic 8
...
2

Results in a compound with lower

Biology HL

Results in a compound with higher

potential energy

potential energy

➢ The reduced form of a molecule always has more potential energy than the oxidized
form of the molecule
➢ Redox reactions play a key role in the flow of energy through living systems


Because the electrons that are flowing from one molecule to the next are
carrying energy with them

Example:

C6H12O6 + 6O2 ⇒ 6CO2 + 6H2O + energy



C6H12O6 was oxidized since it lost hydrogen atoms to form carbon dioxide
6O2 was reduced since it gained hydrogen atoms to form water

Glycolysis
➢ Uses no oxygen and occurs in the cytoplasm


No organelles are required



It proceeds efficiently in both aerobic and anaerobic environments

➢ Occurs in both prokaryotic and eukaryotic cells
➢ Steps:


Two molecules of ATP are used to begin glycolysis


The phosphates from the ATPs are added to glucose to form another
sugar



Less stable molecule



The process is called phosphorylation

The less stable 6-carbon sugar is split into two 3-carbon sugars






This splitting process is known as lysis

These sugars enter an oxidation phase involving ATP formation and the
production of the reduced coenzyme NAD


Each of those phosphate molecules undergoes oxidation to form a
+

reduced NAD which becomes NADH


Energy is released and it is used to add an inorganic
phosphate to the 3-carbon compound



Enzymes remove the phosphate groups so that they can be added to ADP to
produce ATP

2

Cell respiration

Topic 8
...
2

Biology HL

➢ Steps:


Acetyl CoA combines with a 4-carbon compound called oxaloacetate
...



The lost carbon is combined with oxygen and leaves the cell as
carbon dioxide
...
4 CO2 are
released during the Krebs cycle


These account for all 6 carbon atoms that were present in the initial glucose


Glucose is completely catabolized and its original energy is now
carried by NADH and FADH2 or ATP

➢ Until now, a net gain of 4 ATPs has been produced by substrate-level
phosphorylation


We obtain the remaining 32 ATPs through oxidative phosphorylation
4

Cell respiration

Topic 8
...
2

Biology HL

Chemiosmosis is an oxidative phosphorylation, as it utilizes an ETC

➢ The protons will try to move back across the membrane to level out the
concentration gradient, but they are stopped by the membrane


Because of the hydrophilic region of the membrane, protons can only pass
through the ATP synthase

➢ ATP synthase is a protein that harness the energy of moving protons to
phosphorylate an ADP to ATP


ATP synthase lies on the inner membrane

➢ When protons enter the matrix again, they will react with a newly formed oxygen
ion to form water maintaining the gradient
Production of ATP - summary

Process

ATP used

ATP produced

Net ATP gain

Glycolysis

2

4

2

Krebs cycle

0

2

2

ETC +

0

32

32

2

38

36

chemiosmosis
Total

➢ In reality the number is closer to 30, because:


Some protons move back to the matrix without going through the ATP
synthase channel



Some of the energy of the proton movement is used to transport pyruvate
into the mitochondria

➢ The 30 ATPs account for approximately 30% of the energy present in the chemical
bonds of glucose

6


Title: Cell respiration
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture