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Title: Cell respiration
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture
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Cell respiration
Topic 8
...
2
Results in a compound with lower
Biology HL
Results in a compound with higher
potential energy
potential energy
➢ The reduced form of a molecule always has more potential energy than the oxidized
form of the molecule
➢ Redox reactions play a key role in the flow of energy through living systems
○
Because the electrons that are flowing from one molecule to the next are
carrying energy with them
Example:
C6H12O6 + 6O2 ⇒ 6CO2 + 6H2O + energy
○
○
C6H12O6 was oxidized since it lost hydrogen atoms to form carbon dioxide
6O2 was reduced since it gained hydrogen atoms to form water
Glycolysis
➢ Uses no oxygen and occurs in the cytoplasm
○
No organelles are required
○
It proceeds efficiently in both aerobic and anaerobic environments
➢ Occurs in both prokaryotic and eukaryotic cells
➢ Steps:
○
Two molecules of ATP are used to begin glycolysis
■
The phosphates from the ATPs are added to glucose to form another
sugar
○
Less stable molecule
●
The process is called phosphorylation
The less stable 6-carbon sugar is split into two 3-carbon sugars
■
○
●
This splitting process is known as lysis
These sugars enter an oxidation phase involving ATP formation and the
production of the reduced coenzyme NAD
■
Each of those phosphate molecules undergoes oxidation to form a
+
reduced NAD which becomes NADH
●
Energy is released and it is used to add an inorganic
phosphate to the 3-carbon compound
○
Enzymes remove the phosphate groups so that they can be added to ADP to
produce ATP
2
Cell respiration
Topic 8
...
2
Biology HL
➢ Steps:
○
Acetyl CoA combines with a 4-carbon compound called oxaloacetate
...
■
The lost carbon is combined with oxygen and leaves the cell as
carbon dioxide
...
4 CO2 are
released during the Krebs cycle
○
These account for all 6 carbon atoms that were present in the initial glucose
■
Glucose is completely catabolized and its original energy is now
carried by NADH and FADH2 or ATP
➢ Until now, a net gain of 4 ATPs has been produced by substrate-level
phosphorylation
○
We obtain the remaining 32 ATPs through oxidative phosphorylation
4
Cell respiration
Topic 8
...
2
Biology HL
Chemiosmosis is an oxidative phosphorylation, as it utilizes an ETC
➢ The protons will try to move back across the membrane to level out the
concentration gradient, but they are stopped by the membrane
○
Because of the hydrophilic region of the membrane, protons can only pass
through the ATP synthase
➢ ATP synthase is a protein that harness the energy of moving protons to
phosphorylate an ADP to ATP
○
ATP synthase lies on the inner membrane
➢ When protons enter the matrix again, they will react with a newly formed oxygen
ion to form water maintaining the gradient
Production of ATP - summary
Process
ATP used
ATP produced
Net ATP gain
Glycolysis
2
4
2
Krebs cycle
0
2
2
ETC +
0
32
32
2
38
36
chemiosmosis
Total
➢ In reality the number is closer to 30, because:
○
Some protons move back to the matrix without going through the ATP
synthase channel
○
Some of the energy of the proton movement is used to transport pyruvate
into the mitochondria
➢ The 30 ATPs account for approximately 30% of the energy present in the chemical
bonds of glucose
6
Title: Cell respiration
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture
Description: International Baccalaureate Biology HL Topic 8.2 2017 Clear and detailed notes of topic 8.2 from the book and lecture