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Continue Practice Exam Test
Questions Part 2 of the Series

Problem 55

Choose the letter of the best answer
in each questions
...
p + q

Change 0
...


B
...
2/10

C
...
2/9

D
...
2/13

Problem 56 (ECE March 1996)

D
...
2272722… to a common fraction
...
7/44
B
...
5/22
D
...
2974
B
...
2174
D
...
320

A
...
2

B
...
180

C
...
90

D
...
(2x – y)2

A
...
50

B
...
20

C
...
0
...
–(2x – y)2

D
...
05

Problem 59

Factor x4 – y2 + y – x2 as completely as
possible
...
(x2 + y)(x2 + y -1)
B
...
(x2 – y)(x2 – y -1)
D
...


A
...
3x(x – 2)(x + 3)
C
...
(3x2 – 6x)(x – 1)
Problem 64 (ME April 1998)
Factor the expression 16 – 10x + x2
...
(x + 8)(x – 2)
B
...
(x + 8)(x – 2)

C
...
(x + 4)(x + 2)

D
...
(x + 4)(x – 2)

Problem 65

D
...


Problem 61 (ME October 1997)
Factor the expression x3 + 8
...
(x – 2)(x2 + 2x + 4)
B
...
(-x + 2)(-x2 + 2x + 2)
D
...

A
...
(x2 + y2)(x2 – y2)
C
...
(1 + x2)(1 + y)(1 – y2)
Problem 63 (ME October 1997)
Factor the expression 3x3 + 3x2 – 18x as
completely as possible
...
(x + 1)(x – 1)(x4 + x2 – 1)
B
...
(x + 1)(x – 1)(x4 – x2 + 1)
D
...
4 and -2 only
B
...
-2 and 4 only
D
...
0
B
...
2x

C
...
3

D
...
(x – 1)2 = x2 – 2x + 1

3x – 2y + w = 11

B
...
x2 – (x – 1)2 = 2x – 1

2x + y – 3w = -6

D
...
1

Problem 69 (ME October 1997)

B
...


C
...
-18 = -18
B
...
4
Problem 73

C
...
Find the value of k
...
-27 = -27 or 0 = 0

A
...
2 or -4

Solve the simultaneous equations: 3x – y
= 6; 9x – y = 12
...
4 or -2

A
...
x = 1; y = -3

D
...
x = 2; y = 2

Find k in the equation 4x2 + kx + 1 = 0 so
that it will only have one real root
...
x = 4; y = 2

A
...
2

Solve algebraically:

C
...
4

11y2 – 3x2 = 41

Problem 75

A
...
y = +2, x = ±1 and y = -2, x = ±1

A
...
281

B
...
812

C
...
218

D
...
182

Problem 76 (CE November 1997)

Problem 80

If 3x3 – 4x2y + 5xy2 + 6y3 is divided by
(x2 – 2xy + 3y2), the remainder is

Find the quotient of 3x5 – 4x3 + 2x2 +
36x + 48 divided by x3 – 2x2 + 6
...
0

A
...
1

B
...
2

C
...
3

D
...
10
B
...
12
D
...

Find k
...
2
B
...
4
D
...
What is the remainder?

If 1/x = a + b and 1/y = a – b, then x – y
is equal to:
A
...
1/2b
C
...
2b/(a2 – b2)
Problem 82
If x-1/x = 1, find the value of x3 – 1/x3
...
1
B
...
3
D
...
Then
x is equal to:
A
...
2/3

D
...
¾

Problem 88 (ME April 1996)

D
...


y + x2/y = 24/y

A
...
(x – 3)/5

B
...
(x + 3)/(x – 1)

y = (-2 + 6√14)/5 or (-2 – 6√15)/5

D
...
x = (6 + 2√14)/5 or (6 – 2√14)/5

Problem 85

y = (-2 + 6√14)/5 or (-2 – 6√14)/5

If 3x = 4y then ((3x2)/(4y2)) is equal to:

D
...
¾

y = (-6+ 2√14)/5 or (-6 + 2√14)/5

B
...
2/3
D
...
((x2 =
4x + 10)/(x3 + 2x2 + 5x)) = A/x + ((B(2x
+ 2))/(x2 + 2x + 5)) + (C/(x2 + 2x + 5))

Problem 86

A
...


B
...
-4

C
...
0

D
...
4

Problem 90

D
...
x4 – x3 + 8
B
...
x4 – 2x3 + 4x2 – 8x + 16

A
...
A = -3; B = 2
B
...
A = 3; B = 2
D
...
16:1

Resolve ((x + 2)/(x2 – 7x + 12) into
partial fraction
...
(6/(x – 4)) – (2/(x – 3))

If 1/a :1/b : 1/c = 2 : 3 : 4, then (a + b +
c) : (b + c) is equal to:

B
...
13:7

C
...
15:6

D
...
10:3

Problem 92 (ECE April 1998)

D
...

If two numbers namely 250 and 850 are
removed what is the arithmetic mean of
the remaining numbers?

Problem 96

A
...
31
B
...
12
C
...
38
...

If two numbers are added to the
progression, the new set of number will
have an arithmetic mean of 19
...

A
...
10
C
...
14
Problem 97
Find the fourth proportional of 7, 12, and
21
...
36
B
...
21, 29

C
...
23, 27

D
...
24, 26

Problem 98 (ECE November 1997)

D
...
1

If 2x – 3y = x + y, then x2 : y2 =

B
...
1:4

C
...
4:1

D
...
1:16

Problem 99

Solve for x: -4 < 3x – 1 < 11
...
D
...
1 < x < -4

66
...
4 and -2 only

B
...
C
...
1 < x < 4

68
...
2(x-1)+3(x+1) = 5x+4

D
...
C
...
B
...


71
...
y = +2, x = ±1 and y = -2, x =
±1

A
...
6 > x > -2
C
...
6 > x > 2
Below are the answers key for the Multiple
Choice Questions in Fundamentals in
Algebra Part 2
...
B
...
C
...
A
...
D
...
05
55
...
pq
56
...
1994
57
...
2
58
...
–(2x-y)2
59
...
(x2 -y)(x2 + y -1)
60
...
(x+4)(x+2)
61
...
(x+2)(x2-2x+4)
62
...
(x2+y2)(x+y)(x-y)
63
...
3x(x+2)(x-3)
64
...
(x-8)(x-2)

72
...
3
73
...
4 or -2
74
...
4
75
...
731
76
...
0
77
...
11
78
...
4
79
...
218
80
...
3×2 + 6x + 8
81
...
2b/(a2 – b2)
82
...
4
83
...
¾
84
...
4/(x+3)
85
...
4/3
86
...
4
87
...
x4 – 2×3 + 4×2 – 8x + 16
88
...
x = (6 + 2√14)/5 or (6 – 2√14)/5
y = (-2 + 6√14)/5 or (-2 – 6√14)/5
89
...
2

90
...
A = 3; B = 2
91
...
(6/(x – 4)) – (5/(x – 3))
92
...
42
...
B
...
D
...
A
...
B
...
A
...
C
...
B
...
A

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