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Title: A child sits on a merry-go-round that has a diameter of 6.00 m
Description: exam questions with solutions and explanation
Description: exam questions with solutions and explanation
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Answer
1
...
a = 0
...
Ø= 39
...
Vmax = 10
...
xaf = 7
...
A
...
78 rad/s
The initial angular velocity is 0, wi=0 ;
wf=wi +at
1
...
0405 rad/s2
B
...
0405)(442)
= 39
...
Let r = 6m
Vmax = maximum tangential speed
Vmax = wfr
= 1
...
68 m/s
2
...
8-1
...
6 = 4 + 2a
a = 2
...
3 m/s2
Then solve for xaf ;
Δxa = vit + 1/2at2
xaf - 1 = 2*2 + 1/2(1
...
6+1
xaf = 7
Title: A child sits on a merry-go-round that has a diameter of 6.00 m
Description: exam questions with solutions and explanation
Description: exam questions with solutions and explanation