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Title: Matrix inverse by cofactors and Cramer's rule
Description: Linear algebra course

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Matrix Inverse by Cofactors
and Cramer's Rule

5
...
Determinant calculations are generally much longer than
row reduction
...
However, it is useful in some theoretical applications
because it provides a formula for A-1 in terms of the entries of A
...

[False Expansion Theorem]

Theorem l

If A is an n

x

n matrix and i t= k, then

Proof: Let B be the matrix obtained from A by replacing (not swapping) the k-th row
of A by the i-th row of A
...
2
...
Since the cofactors c;j of B are equal to the cofactors

CkJ of A, and the coefficients bkJ of the k-th row of B are equal to the coefficients aiJ

of the i-th row of A, we get

as required
...
We define the cofactor matrix of A, denoted cof A, by

(cof A)iJ

=

CiJ

EXAMPLE 1
Let A=

2[0 4 -1 1
-2

1
...

5

3

6
Solution: The nine cofactors of A are

=Cl)1-� �I 17 12 I� �I=
1
1
2
C21 14_2 1= -18 C22= 1 1=
-11=7 C32=(-1)012 -11 =-2
=

ell

= (-1)

5

c

= c-1)
( 1)

C13=(1)I� _;1= -18
C23= I� -�I= 28
C33 (1)1� �I

6

5

6

1

(-1)

16

=

l

=6

Hence,

= [-1

EXERCISE 1

Calculate the cofactor matrix of A

�n

Observe that the cofactors of the i-th row of A form the i-th row of cofA, so they
form the i-th column of (cof Al
...
Moreover, by the False Expansion
Theorem, the dot product of the i-th row of A and the }-th column of cof A equals
if i * j
...

/

[c1

c,!]

-+T
a

i11 ·en

n

=

a11



C1

detA

0
=
0

where I is the identity matrix
...
en

detA

(detA)/

detA

(de;A) (cofAl= I, and, therefore,

A-1

=( � )
de A

ccofA)7

If detA

=

0, then, by Theorem 5
...
4, A is not invertible
...
(Some people refer to the trans­
pose of the cofactor matrix as the adjugate matrix and therefore call this the adjugate
method)
...


i

2

4

-1

0

3

1

0

-14

8

2(24 + 14)

=

=

76

Thus, A is invertible
...
This is manageable, but it is more work than would be required by the
row reduction method
...


Cramer's Rule
Consider the system of

n

linear equations in

n

variables, Ax

=

that A is invertible, then the solution may be written in the form

x

=

A

-

1

b

X1

X;

Xn

=

detA

1
=

detA

(cof A)

7

b

C11

C 21

C111

b1

C1;

C2;

c,li

b;

C111

C211

Cnn

bn

b
...
+bn C)
Ill
I

I

detA

·

multiplied by the dot product of the vector

b with the i-th row of (cof Af
...
So

x; is the dot product of the vector

b with the i-th column of cof A divided by detA
...


Then the cofactors of the i-th column of N; will equal the cofactors of the i-th column
of A, and hence we get
det N;

=

b1Ci;+b2C2;+

· ·

·

+b11C11;

Therefore, the i-th component of 1 in the solution of Ax
x· -

=

b is

det N;

--

- detA

1

This is called Cramer's Rule (or Method)
...


EXAMPLE3

Use Cramer's Rule to solve the system of equations
...
s A

...


detA
Hence,
Xi

x
2

=

3
-X2
5
1
-x2
3

+

-

=

-

=

r-22/315

=

1
5
1
2

-

- · - - -·
-2 -1
3
3

3 2
5 5

1
1

1
1

_

3/5
11 3
=

-

]

, so

-4
225

-

165
-225
...
93 93
-2/3 1/5
-4/225 2/5 1/2
4
4
4
=

To solve a system of

n

equations in

n

_

=

=

variables by using Cramer's Rule would

require the evaluation of the determinant of

n +

1

matrices, each of which is

n x n
...
However, like the cofactor method above, Cramer's Rule is sometimes used
to write a formula for the solution of a problem
...
3
Practice Problems
Al Determine the inverse of each of the following ma­
trices by using the cofactor method
...

(a)
(b)

(c)

[! l�]
[; =�1

U -� Il

(d)

[�
-2

A2 Let A

=

-

� �

2 -1

i

[-; -� �]·
-

3

1

1

(a) Determine the cofactor matrix cof A
...

(a) x
2 1-x
3 2=6

(c)

7x1+
x2 - x
4 3 =3
-x
6 1 - 4x2+
x3 =0

3x1 +x
5 2=7

4x1 -x2 - x
2 3 =6

(b) x
3 1+x
3 2=2

(d)

x
2 1-x
3 2=5

x
2 1+3x2 - 5x3 =2
3x1 -x2 +2x3 =1
5x1+4x2 - x
6 3 =3

Homework Problems

[ � � �1
...
Verify your
answer by using multiplication
...

(b) Calculate A(cof A)7 and determine
and A-1•
-2

2

-2

-

B3 Use Cramer's Rule to solve the following systems
...


(a) Verify by Cramer's Rule that the system of
equations Ax=a1 has the unique solution
x=ej (the }-th standard basis vector)
...


D2 Let A =

2

-1

0

0

-1

3

0
0

2

1

2
0

0

0

3


...
(If you calcu­
late more than these two entries of A-1, you have
missed the point
Title: Matrix inverse by cofactors and Cramer's rule
Description: Linear algebra course