Search for notes by fellow students, in your own course and all over the country.
Browse our notes for titles which look like what you need, you can preview any of the notes via a sample of the contents. After you're happy these are the notes you're after simply pop them into your shopping cart.
My Basket
Havisham Themes Essay£0.50
Daily learning plan£9.20
DFD£1.50
FRACCIONES£18.75
8085 Instruction Set By Er. Swapnil V. Kaware£6.25
Total£36.20
Or: Edit My Basket
Document Preview
Extracts from the notes are below, to see the PDF you'll receive please use the links above
Must Know Concepts
Percentages:
1
1
1
...
Percentage change =
πΉππππ ππππ’πβπΌπππ‘πππ ππππ’π
πΌπππ‘πππ ππππ’π
x 100 (If positive then itβs an increase and if negative
then itβs a decrease
...
If final value becomes βkβ times the initial then thereβs an increase of [(k-1) x 100]%
1
b
...
To increase a value βXβ by r% = X x (
Short-cut: X x
π+π
π
100+π
)
100
π
where, r% = π (in fraction)
100βπ
)
100
4
...
Reverse percentage change:
Short-cut:
π
π
a
...
πβ1
x
π
100)%
(The same can be used if βAβ is increased by r% to find by how much % it should be decreased to get
the original value
...
67%
...
By what percentage should they
reduce the price now?
Ans: 14
...
If βAβ is π th less than βBβ, then βBβ is πβπth more than βAβ
...
)
6
...
C) = a + b + 100
(Here, keep a note to use negative sign for decrease
...
Example: Area of a rectangle = Length x Breadth; Expenditure = Price x Consumption;
Distance = Speed x Time
Application of successive percentage change:
a
...
C & to find b% (or a%) (If R
...
)
Quick Check-2: If the price of the petrol is decreased by 11
...
By how much should you increase
your consumption to keep the expenses constant?
Ans: 12
...
By how much should you reduce your
consumption so that the expenses increases by 10%?
Ans: -12%
b
...
C=0 & to
find the absolute value for which absolute change is given
...
Ans: 28
Profit & Loss:
Cost Price (C
...
Add all expenses while purchasing to get the
final C
...
Selling Price (S
...
Any commission paid to agent for selling an article
will be deducted from the S
...
Marked Price/List Price (M
...
Case-I: C
...
P then Profit
1
...
P β C
...
Profit% =
ππππππ‘
πΆ
...
S
...
P x
(100 + ππππππ‘%)
100
(Use fractions conversion of percentages as and when possible)
4
...
P = S
...
Margin =
ππππππ‘
π
...
P > S
...
Loss = C
...
P
2
...
π
x 100
3
...
P = C
...
C
...
P x
100
(100 β πΏππ π %)
(Use reverse percentage change as and when possible)
Case-III: Discount
1
...
P β S
...
Discount% =
π·ππ πππ’ππ‘
π
...
Mark Up Price = M
...
P
4
...
π
x 100
5
...
P = M
...
M
...
P x
100
(Use reverse percentage change
(100 β π·ππ πππ’ππ‘%)
fractions conversion of percentages as and when possible)
as and when possible)
Short-Cut:
1
...
P of two articles is same and on one thereβs a profit of βk%β and on the other thereβs a loss
(π)π
of βk%β, then thereβs always a loss of πππ %
2
...
If an article is Marked Up by βM%β, available at a Discount of βD%β and yields a Profit of βP%β then
π΄π«
P = (M + D + πππ) (Use negative sign for D as it is a decrease)
π
4
...
If πΆ
...
If a shopkeeper uses a false weight of βx kgβ instead of βy kgβ (where x < y) and professes to sell the
πβπ
article at the C
...
If a shopkeeper uses a false weight of βx kgβ instead of βy kgβ (where x is βk%β less than y) and
(π + π)
professes to sell the article at βp%β profit, then his Actual Profit% = (πππ β π) x 100
Simple Interest & Compound Interest:
Principal (P): Money lent or borrowed
Rate of Interest (R): Percentage of Principal paid as interest
...
e
...
Amount (A): Total money paid to clear the principal as well as interest
...
I): When the interest is calculated only over the principal
...
S
...
A = P + S
...
If an amount becomes βkβ times of itself when given at βR%β rate of interest, then
R = (k-1) x
πππ
π
Compound Interest (C
...
1
...
C
...
If the amount for the nth year and the (n+k)th year be βxβ and βyβ respectively, then
π π
R = [(π)π - 1] x 100
Hence, if the amount for two consecutive years be βpβ and βqβ then R =
Difference between C
...
I:
1
...
πΌ)2 π¦π = π(100)2
π
π
3