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Question Series

Subject : Biology
1
...


Adventitious roots are observed in all of the
following except:
1) Grass

2) Banyan tree

3) Monstera

4) Mustard

Select the incorrect statement1) Majority of monocots possess adventitious
roots
...

3) Majority of dicots possess tap roots
...


3
...


Pneumatophores are found in :
1) Rhizophora

2) Potato

3) Ginger

4) Both (1) and (3)

In which set of plants, stem is modified to store
food 1) Colocasia and turnip
2) Ginger and Zaminkand
3) Carrot and sweet potato
4) Turmeric and maize

5
...


Adventitious roots are modified for storage in1) Turnip

2) Carrot

3) Sweet potato

4) All of the above

Axillary bud on stem develops into tendrils
for support in
1) Cucumber

2) Pumpkins

3) Watermelon

4) All of the above

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

SANJIVANI

Topic – Morphology of Flowering Plants
7
...


Select the incorrect match 1) Alternate phyllotaxy - China rose
2) Pinnately compound leaf - Neem
3) Actinomorphic flower - Chilli
4) Fleshy leaves for storage - Pea

9
...
Which of the following is not correctly
matched ?
1) Simple leaf - Peepal
2) Apocarpous - Lotus
3) Zygomorphic flowers - Pea
4) Diadelphous - China rose
11
...

1) Primary root is short lived in monocots
2) Root cap is well developed in aquatic plants
3) Prop roots in banyan tree are meant for
support
4) Root hairs are found in region of maturation
...
Motegaonkar S
...
, M
...
Chem
...

3) 3 - Petiole, it may be terminal or axillary in
position
...

13
...


14
...


15
...
Select
the option with correct information :

1) A - Tap root system, found in Maize
2) A - Adventitious root system, found in
Mustard
3) B - Fibrous root system, found in cereals
4) B - Adventitious root system, found in grass
...
Tap root originate from :
1) Radicle

2) Stem

3) Leaves

4) Adventitious roots
...
Select the option with either incorrect
identification or incorrect feature / function
...
In aquatic plants, root cap is :
1) Well developed and single in number
2) Poorly developed or absent
3) Well developed and multiple in number
4) Lignified
...
Match the column A (type of root) with column
B [example of plants) :
Column A

Column B

I
...
Maize

II
...
Mustard
3
...
Sugarcane
5
...
Stilt roots originate from1) Primary roots
2) Secondary roots
3) Lower node of stem
4) Axillary bud of leaf
...
Out of the following plants, how many
possess stilt roots? [Banyan, Neem, Carrot,
Maize, Mustard, Monstera, Sugarcane]
1) 2

2) 3

3) 4

4) 5

21
...


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Page: 2

1) A - Region of cell elongation, most distant to
root cap
...

3) A - Region of meristematic activity,
metabolically active region as root hairs are
present
...

23
...

Such roots are known as
...
and are
found in
...

1) (i) - Prop roots, (ii) - Banyan
2) (i) - Stilt roots, (ii) - Sugarcane
3) (i) - Pneumatophores, (ii) - Rhizophora
4) (i) - Mechanical roots, (ii) - Maize
...
Which pair is having different types of roots?
1) Bean, Mustard

2) Wheat, Jowar

3) Maize, Mustard

4) Grass, Monstera
...
Which plant is not correctly matched with its
type of root?
1) Wheat - fibrous roots
2) Grass - adventitious roots
3) Rhizophora - pneumatophores
4) Banyan - stilt roots
...
A, B and C are three anatomical regions of
root
...
Select the wrong statement
1) In Ginger, stem is modified for storage
...

3) Stilt roots in sugarcane provide mechanical
support
...

27
...

28
...

Reason : Parts of flower in hypogynous condition
arises above ovary
...
Which part or zone of root is not correctly
matched with its function?
1) Root cap - protection of root apex
...

3) Region of meristematic activity - give rise to
root hair
...

30
...
Motegaonkar S
...
, M
...
Chem
...

32
...

Select the option with its correct function and
example of plant in which it is found?
1) Gaseous exchange, Rhizophora
2) Mechanical support Sugarcane
3) Storage, Maize
4) Storage, Banyan
...
Woody and pointed thorns may develop form
axillary buds of stem in 1) Bougainvillea, Citrus
2) Turmeric, Ginger
3) Opuntia, Euphorbia
4) Mustard, Monstera
...
Among the following, in how many plants
stem is modified for storage? [Ginger,
Pumpkin, Sweet potato, Zaminkand,
Monstera, Turmeric, Colocasia, Potato, Citrus,
Opuntia, Bougainvillea, Euphorbia]
1) 2

2) 3

3) 5

4) 7

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

31
...
Identify the correct
statement:

35
...

These are roots which are known as_____and
are meant for__________e
...
in_______
...

2) Prop roots, mechanical support, Banyan
...

4) Pneumatophores,
Rhizophora
...
In which of the following plant, stem can be
observed as fleshy, cylindrical and
photosynthetic?
1) Opuntia

2) Euphorbia

3) Bougainvillea

4) Aloe
...
In which set of plants, stems is modified for
storage?
1) Turmeric and Zaminkand
2) Potato and sweet potato
3) Turnip and carrot
4) Potato and Gourds
...
A, B, C and D are parts of plants modified for
storage
...


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Page: 4

1) Opuntia

2) Gourds

3) Euphorbia

4) Potato
...
In grass, when older parts die, new parts may
develop from underground stem
...


41
...

This is observed in case of1) Grapevines and gourds
2) Turmeric and ginger
3) Bougainvillea and citrus
4) Mint and jasmine
...
In the given diagram, if A (spine) and B
(tendril) structures are modifications of stem
...
Lateral branches with short internodes giving
rise to roots below and leaves above at nodes
are observed in1) Pea, Citrus
2) Mustard, Salvia
3) Chrysanthemum, Banana
4) Eichhornia, Pistia
...
Flattened and photosynthetic stem can be
observed in -

44
...


45
...


46
...

Reason : In China rose fusion of filament of
stamen form a single group
...
Typical leaf structure is shown in the
diagram
...


1) 3 - Stipule, 4 - Petiole
2) 1 - Lamina, 4 - Petiole
3) 2 - Leaf base, 5 - Axillary bud
4) 2 - Stipule, 3 - Petiole
...
Midrib is observed in which part of leaf1) Leafbase

2) Lamina

3) Petiole

4) Stipule
...
Motegaonkar S
...
, M
...
Chem
...
Select the option in which the plants are
incorrectly matched with the type of leaf:
1) Neem - compound leaf
2) Peepal - palmately compound leaf
3) Cyccis - pinnately compound leaf
4) Silk cotton - palmately compound leaf
...
Two types of venation are shown in leaves - P
and Q
...

2) Leaf P shows parallel venation, which can be
observed in wheat are maize
...

4) Leaf Q shows parallel venation, which can be
observed in sugarcane and maize
...
In which of the following plant, tendril is
modification of leaf ?
1) Pea

2) Grapevines

3) Pumpkins

4) Cucumber
...
Leaves become fleshy to store food in 1) Calotropis, Guava
2) Onion, Garlic
3) Turnip, Carrot
4) Colocasia, Zaminkand
...
If leaflets are attached to a common point, leaf
is said to be -

54
...


55
...

1) Pinnately compound, Peepal
2) Pinnately com'pound, Neem
3) Palmately compound, Banana
4) Palmately compound, Silk cotton
...
Leaf base if becomes swollen, is termed
as
...

1) Peduncle, cereals

2) Peduncle, legumes

3) Pulvinus, cereals

4) Pulvinus, legumes
...
Which of the following is not commonly
applicable to dicots?
1) Venation - Reticulate mostly
2) Roots - Tap roots usually
3) Number of cotyledons in seed - Two
4) Seeds - Endospermic only
...
Multiple leaves originating from each node of
stem can be observed in
1) Alstonia

2) Calotropis

3) China rose

4) Neem

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Page: 6

1) Silk cotton

2) Banyan

3) Banana

4) Mustard
...
Which of the pair of plants possess similar
phyllotaxy?
1) Mustard, China rose
2) Clematis, Alstonia
3) Sunflower, Guava
4) Pea, Alstonia
...
Phyllotaxy of mustard is similar to that of 1) China rose

2) Calotropis

3) Guava

4) Alstonia
...
Match the structure /part (column A) with the
plant (column B) and modification of part
(columnC)
...
Pedicel is 1) Basal part of leaf
2) Stalk of leaf
3) Stalk of flower
4) Axis of inflorescence
...
A compound leaf is given in the diagram in
which of the following plants such type of leaf
is found?

64
...


1) Sunflower, Guava
2) Mustard, China rose
3) Alstonia, Guava
4) Calotropis, China rose
...
In which of the following insectivorous
plants, insect catching apparatus is not the
modification of leaves?
1) Venus fly trap (Dionea]
2) Pitcher plant (Nepenthes]
3) Bladderwort (Utricularia)
4) None of these
...
Photosynthetic enlarged petioles can be
observed in 1) Australian Acacia

2) Venus fly trap

3) Clematis

4) Legumes
...
P and Q are two types of phyllotaxy given in
diagrams
...
Motegaonkar S
...
, M
...
Chem
...

69
...


70
...


71
...

72
...


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68
...
Monoadelphous condition is found in 1) Lily

2) China rose

3) Pea

4) Brinjal
...
Normally the anthers are 1) Monolobed

2) Bilobed

3) Tetralobed

4) Pentalobed
...
In the given section of onion, labelled fleshy
structure A is modification of -

1) Leaves

2) Stem

3) Root

4) Inflorescense
...
Assertion : Old root hairs are replced by new
one
...

1) Both the assertion and reason are true and the
reason is a correct explanation of the assertion
2) Both the assertion and reason are true but the
reason is not a correct explanation of the
assertion
3) The assertion is true but reason is false
4) The assertion and reason are false
77
...
Various types of arrangements of stamens are
found among angiosperms
...

1) Monoadelphous - Lily
2) Epiphyllous - Citrus
3) Polyadelphous - Pea
4) Epipetalous - Brinjal
...
Motegaonkar S
...
, M
...
Chem
...


80
...
These are ______
and are modification of__________
...


81
...


82
...


83
...
Assertion : The plemule enclosed in a sheath
are called coleoptile
...

1) Both the assertion and reason are true and the
reason is a correct explanation of the assertion
2) Both the assertion and reason are true but the
reason is not a correct explanation of the
assertion
3) The assertion is true but reason is false
4) The assertion and reason are false

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

79
...
stamens are present
...
Identify the diagram and select the correct
option indicating them :

1) A - Racemose inflorescence, D - Hypogynous
condition
2) B - Racemose inflorescence, D - Epigynous
condition
3) A - Cymose inflorescence, C - Perigynous
condition
4) B - Cymose inflorescence, D - Perigynous
condition
...
Symmetry of Datura flowers is similar to that
of 1) Chilli

2) Pea

3) Canna

4) Gulmohar
...
In Canna, flowers are 1) Actinomorphic

2) Zygomorphic

3) Asymmetric

4) Absent
...
Which pair of angiosperms possess similar
symmetry in flowers?
1) Bean, Pea
2) Cassia, chilli
3) Mustard, Gulmohar
4) Datura, Bean
...
Leafy structure that develops at the base of
flower or inflorescence :
1) Pedicel

2) Bract

3) Tepals

4) Perianth
...
Fate of ovary wall after fertilization
1) Fruit wall or pericarp
2) Seeds
3) Endosperm
4) Degenerate

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...
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Page: 9

1) P - Hypogynous condition, Brinjal
2) Q - Epigynous condition, Peach
3) Q - Perigynous condition, China rose
4) R - Hypogynous condition, Guava
...
Which structure is responsible for protection
of flower in bud stage ?
1) Bract

2) Sepals

3) Pedicel

4) Thalamus
...
Thalamus or receptacle is part of :
1) Pedicel

2) Calyx

3) Perianth

4) Peduncle
...
In silk cotton :
1) Lamina of leaves remain intact
2) Leaflets are arranged on a common axis
3) Leaflets are attached to a common point
4) Leaves are attached to a common point
...
Phyllotaxy in mustard and Calotropis is
respectively 1) Whorled, Opposite
2) Opposite, Alternate
3) Alternate, Opposite
4) Alternate, Whorled
...
Which set of plants are having flowers with
half inferior ovary?
1) Plum, Peach

2) Cucumber, Mustard

3) Brinjal, Mustard

4) Plum, Brinjal
...
Three diagrams of flowers indicating various
positions of ovary with respect to other floral
whorls are given
...
Identify the position of ovary in flower in the
given diagram
...


98
...
Which statement is correct regarding position
of ovary in flowering plants?
1) Perigynous flowers possess inferior ovary
2) Epigynous flowers possess superior ovary
3) In hypogynous flowers, other whorls are
placed below gynoecium
4) In perigynous flowers, whorls are situated
below the rim of thalamus
...
Observe the given diagram and identify the
position of ovary :

1) Superior ovary

2) Half inferior ovary

3) Half superior ovary 4) Inferior ovary
...
Ovary is enclosed by thalamus completely in:
1) China rose

2) Rose

3) Guava

4) Plum
...
Motegaonkar S
...
, M
...
Chem
...
Which set of angiosperms are having flowers
at same position of ovary with respect to other
whorls?
1) Peach, Rose

2) Brinjal, China rose

3) China rose, Rose

4) Cucumber, Mustard
...
Whorls 1 - 4 of a typical flower are shown
...


1) 1 - Androecium, 3 - Corolla
2) 2 - Androecium, 4 - crynoecium
3) 1 - Gynoecium, 2 - Androecium
4) 3 - Calyx, 4 - Corolla
...
Among the following [Cucumber, Rose, China
rose, Brinjal, Mustard]
How many plants possess such flowers in
which ovary is completely enclosed by
thalamus?
1) one

2) two

3) three

4) four
...
On the basis of position of ovary in flower,
which angiosperm is having similarity with
guava?
1) Peach
2) Ray florets of sunflower
3) Plum
4) China rose
...
In perigynousflowers :

107
...

108
...
Select
the correct statement :

1) A and D are reproductive whorls
2) Unit of C is tepal
3) When units of C and D are indistinguishable,
condition is perianth
4) E is peduncle
...
Aestivation is :
1) Arrangement of flowers on floral axis
2) Arrangement of leaves on stem
3) Arrangement petals and sepals with respect
to each other
4) Arrangement of petals or sepals within a
whorl
...
Flowers with five petals - 1 largest, two
medium sized, lateral and two smallest can
be observed in :
1) Calotropis

2) Bean

3) Cotton

4) Cassia
...
Cassia is having aestivation similar to that of:
1) Gulmohar

2) Calotropis

3) Lady's finger

4) Pea
...
In a flower, within a whorl, sepals or petals
touch each other at margins without
overlapping, such flower is of:
1) Cassia

2) Lady's finger

3) Pea

4) Calotropis
...
Motegaonkar S
...
, M
...
Chem
...

114
...

115
...

Reason : Flower are arranged in different type
of infloresence
...
Which set of angiosperms possess similar
aestivation ?
1) Cotton, Gulmohar
2) Calotropis, Pea
3) Cassia, Bean
4) Lady's finger, China rose
...
A and B are representing reproductive parts
of a typical flower
...


117
...
Select" the option with correct
identification of at least two of them (A-D)
...

118
...


119
...

120
...

121
...


Select the option with correct identification
and appropriate example
...


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...
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Page: 12

1) Axile

Lemon

2) Basal

Mustard

3) Free central

Pea

4) Parietal

Primrose

123
...

124
...

1) Marginal

2) Axile

3) Free central

4) Basal
...
Identify the aestivation given in diagram with
suitable example :

1) Imbricate, Bean
2) Imbricate, Cassia
3) Vexillary, Gulmohar
4) Vexillary, Pea
...
Assertion : In mango and coconut, the fruit is
known as drupe
...

1) Both the assertion and reason are true and the
reason is a correct explanation of the assertion
2) Both the assertion and reason are true but the
reason is not a correct explanation of the
assertion
3) The assertion is true but reason is false
4) The assertion and reason are false

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

122
...
Identify the angiosperm in which ovary is
monoloculated initially but because of
development of a false septum it becomes
biloculated later on
...

1) Dianthus

2) Argemone

3) Pea

4) Tomato
...
Placentation in tomato :
1) Axile

2) Marginal

3) Basal

4) Free central
...
Select the option in which placentation in
ovary is correctly matched with examples :
1) Basal - Marigold, Sunflower
2) Marginal - China rose, Pea
3) Free central - Mtistard, Argemone
4) Parietal - Lemon, Primrose
...
A and B are two types of placentations shown
in diagram :

Select the option with correct identification of
them
A

B

1) Parietal

Axile

2) Axile

Free central

3) Parietal

Free central

4) Marginal

Axile

131
...


132
...


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Page: 13

1) Q = Axile, R = Parietal
2) P = Marginal, R = Free central
3) Q = Parietal, S = Basal
4) R = Axile, S = Basal
...
Solid edible part in coconut is :
1) Epicarp

2) Endocarp

3) Mesocarp

4) Endosperm
...
Identify the correct statement:
1) Cotyledons are part of embryo
2) Seeds of Castor are non-endospermic
3) Jowar and maize are dicots
4) Fruit of mango is berry
...
In cereals like wheat, rice, etc, seeds are
________with_______cotyledons
...

137
...


138
...


RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

133
...
Identify the option with correct
identification of at least two of them (P to S) :

139
...

Reason : Pneumatophores help to get oxygen
for respiration
...
Select the option giving incorrect information
about endospermic seeds :
1) Perisperm - absent
2) Cotyledons - fleshy and developed
3) Occurrence - most of monocots
4) Food mainly provided to embryo byendosperm
...
Identify a monocot with non-endospermic
seeds?
1) Bean

2) Maize

3) Orchids

4) Rice
...
Identify the placentation and select the options
with suitable examples in which it is found :

1) Primrose, Dianthus
2) Marigold, Sunflower
3) Tomato, Primrose
4) Pea, China rose
...
In which set of angiosperms seeds lack
perisperm?
1) Gram

2) Orchids

3) Castor

4) Pea
...
Motegaonkar S
...
, M
...
Chem
...


145
...

146
...
Select
the option with correct identification :

1) 1 = Testa, 2 = Tegmen, 3 = Endosperm,
4 = Endosperm
2) 1 = Testa, 2 = Tegmen, 3 = Seed,
4 = Endosperm
3) 1 = Epicarp, 2 = Mesocarp, 3 = Seed,
4 = Endocarp
4) 1 = Pericarp, 2 = Mesocarp, 3 = Seed,
4 = Endocarp
...
Incorrect about of typical monocot seed :
1) Lack endosperm
2) Lack food in cotyledon
3) Possess coleoptile and coleorrhiza
4) Possess aleurone layer
...
Sheath enclosing plumule in a typical
monocot seed is termed as :
1) Coleorrhiza

2) Coleoptile

3) Bract

4) Scutellum
...
Perianth with valvate aestivation is observed
in a family of angiosperms
...


RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

144
...
Diagrams are indicating the structure of a
dicot seed
...
1
151
...

152
...

Reason : Petals attract inect for pollination
...
Among the following how many plants are
members of family Solanaceae ? [Chilli,
Muliathi, Sesbania,Colchicum, Groundnut,
Ashwagandha, Gloriosa, Tobacco, Gram,
Brinjal, Sem, Potato ]
1) Three

2) Four

3) Five

4) Seven

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Page: 15

1) Potato family  

+

K(5) C(5)A5G(2)

2) Lily family Br 

+

P3+3A3+3G1

3) Fabaceae family %

+

K(5)C1+2+(2)A(5)G1

4) Malvaceae family Br  + Epi K(5) C(5)A (  ) G2
155
...

156
...


157
...


158
...


159
...
Which angiosperm family is correctly matched
with its floral formula?

160
...

Features
1)

2)
3)
4)

No
...
Select the option with incorrect information
about the given angiospermicfamilies :
1) Fabaceae family : Polypetalous condition
2) Fabaceae family : Zygomorphic flowers
3) Solanaceae family : Cymose inflorescence
4) Liliaceae family : 5 stamens, monoadelphous
...
Assertion : Leaves are modified into spine in
cacti
...

1) Both the assertion and reason are true and the
reason is a correct explanation of the assertion
2) Both the assertion and reason are true but the
reason is not a correct explanation of the
assertion
3) The assertion is true but reason is false
4) The assertion and reason are false
163
...

1) Solanaceae, few, endospermic
2) Solanaceae, many, endospermic
3) Fabaceae, few, endospermic
4) Fabaceae, many, non-endospermic
164
...
It belongs to the family:
1) Ranunculacea

2) Fabaceae

3) Lilaceae

4) Cruciferae
...
Motegaonkar S
...
, M
...
Chem
...

166
...


167
...
Which set of angiospermic
plants belongto same angiospermic family to
which Indigoferabelongs ?
1) Soyabean, Sesbania
2) Belladona, Petunia
3) Tulip, Aloe
4) Sunflower, Dahlia
...
Assertion : The ovary is biloculers in family
brassicacae
...

1) Both the assertion and reason are true and the
reason is a correct explanation of the assertion
2) Both the assertion and reason are true but the
reason is not a correct explanation of the
assertion
3) The assertion is true but reason is false
4) The assertion and reason are false

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

165
...
Observe the floral diagram and identify the
option with correct identification of
angiospermic family:

1) Fabaecae

2) Liliaceae

3) Solanaceae

4) Astraceae
...
Which set of angiosperms belong to same
angiospermicfamily ?
1) Chilli, Petunia, Aloe
2) Aloe, Gloriosa, Colchicum
3) Lupin, Indigofera, Potato
4) Soyabean, Moong, Brinjal
...
Which feature in incorrect regarding the
angiospermic family Liliaceae?
1) Seeds - endospermic
2) Androecium - 6 stamens
3) Perianth - 6 tepals
4) Flowers - Zygomorphic
...
Atropine, used for dilating pupil is obtained
from Atropabelladona, which is member of
angiospermicfamily:
1) Cruciiferae

2) Solanaceae

3) Ranunculaceae

4) Fabaceae
...
Observe the given floral diagram
...


1) Pea, Gram

2) Tomato, Brinjal

3) Sunflower, Bean

4) Onion, Tulip
...
Motegaonkar S
...
, M
...
Chem
...
Which of the following plants are having half
inferior ovary ?
1) Plums and rose
2) Plums and China rose
3) Peach and guava
4) Rose and mustard
176
...
Rearrange the following zones as seen in the
root in vertical section and choose the correct
option
...
Root hair zone

B
...
Root cap zone

D
...
Zone of elongation
1) C, B, E, A, D

2) A, B, C, D, E

3) D, E, A, C, B

4) E, D, C, B, A

178
...
The mature seeds of plants such as gram and
peas, possess no endosperm, because
1) These plants are not angiosperms
2) There is no double fertilization in them
3) Endosperm is not formed in them
4) Endosperm gets used up by the developing
embryo during seed development

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

174
...
Roots developed from parts of the plant other
than radicle are called
1) Tap roots

2) Fibrous roots

3) Adventitious roots 4) Nodular roots
181
...
Endosperm, a product of double fertilization
in angiosperms is absent in the seeds of
1) Coconut

2) Orchids

3) Maize

4) Castor

183
...
The placenta is attached to the developing seed
near the
1) Testa

2) Hilum

3) Micropyle

4) Chalaza

185
...
Match the followings and choose correct
option
Group A

Group B

A
...
Without fertilization

B
...
Nutrition

fruit
C
...
Double fertilization

D
...
Seed

1) A - i, B - ii, C - iii, D - iv
2) A - ii, B - i, C - iv, D - iii
3) A - iv, B - ii, C - i, D - iii
4) A - ii, B - iv, C - i, D - iii

Prof
...
R
...
Sc
...
,Gold Medalist, SET/NET-JRF,GATE, DRDO,TIFR Qualified

Page: 18

187
...
The scutellum observed in a grain of wheat
or maize is comparable to which part of the
seed in other monocotyledons?
[AIPMT (Prelims)-2010]
1) Plumule

2) Cotyledon

3) Endosperm

4) Aleurone layer

189
...
In unilocular ovary with a single ovule the
placentation is
[AIPMT (Prelims)-2010]
1) Axile

2) Marginal

3) Basal

4) Free central

191
...
Which one of the following is a xerophytic
plant in which the stem is modified into the
flat, green and succulent structure?
[AIPMT (Mains)-2010]
1) Opuntia

2) Casuarina

3) Hydrilla

4) Acacia

193
...
Vegetative propagation is Pistia occurs by
[AIPMT (Mains)-2010]
1) Stolen

2) Offset

3) Runner

4) Sucker

195
...
The correct floral formula of chilli is
[AIPMT (Prelims)-2011]

K (5)C5A (5) G(2)

1)

C A G 2)
+ K 5 4 (5) (2)

+

3)

+ K (5)C(5)A5 G(2) 4)

+ K (5)C(5)A(5)G(2)

197
...
Flowers are Zygomorphic in
[AIPMT (Prelims)-2011]
1) Datura

2) Mustard

3) Gulmohur

4) Tomato

199
...
Whorled simple leaves with reticulate
venation are present in
[AIPMT (Mains)2011]
1) China Rose

2) Alstonia

3) Calotropis

4) Neem

201
...
Motegaonkar S
...
, M
...
Chem
...
Which one of the following diagrams
represent the placentation in Dianthusl
[AIPMT (Mains)-2011 ]

1)

3)

2)

4)

204
...
How many plants in the list given have
composite fruits that develop from an
inflorescence:
[Walnut, Poppy, Radish, Fig, Pineapple, Apple,
Tomato; Mulberry] [AIPMT (Prelims)-2012]
1) Four

2) Five

3) Two

4) Three

206
...
Placentation in tomato and lemon is
[AIPMT (Prelims)-2012]
1) Marginal

2) Axile

3) Parietal

4) Free central

208
...
Sweet potato is homologous to
[AIPMT (Mains)-2011]

209
...
How many plants in the list given below have
marginal placentation?
Mustard, Gram, Tulip, Asparagus, Arhar, Sun
hemp, ChiTli, Colchicine, Onion, Moong, Pea,
Tobacco, Lupin
[AIPMT (Mains)-2012]
1) Four

2) Five

3) Six

4) Three

211
...
Among bitter gourd, mustard, brinjal,
pumpkin, china rose, lupin, cucumber,
sunnhemp, gram, guava, bean, chilli, plum,
Petunia, tomato, rose, Withania, potato, onion,
Aloe and Tulip, how many plants have
hypogynous flower? [NEET-2013]
1) Ten

2) Fifteen

3) Eighteen

4) Six

213
...
Motegaonkar S
...
, M
...
Chem
...
An example of edible underground stem is
[AIPMT-2014]
1) Potato

2) Carrot

3) Groundnut

4) Sweet potato

216
...
Which one of the following statements is
correct?
[AIPMT-2014]
1) A sterile pistil is called a staminode
...

3) Mango is a parthenocarpic fruit
...

218
...
Non-albuminous seed is produced in
[AIPMT-2014]
1) Maize

2) Castor

3) Wheat

4) Pea

220
...
Placenta and pericarp are both edible portions
in [AIPMT-2014]

221
...


1) Aloe

2) Tomato

3) Tulip

4) Indigofera

+ K (5)C(5)A5 G(2) is the floral formula of
[AIPMT-2015]
1) Petunia

2) Brassica

3) Allium

4) Sesbania

223
...
Among China rose, mustard, brinjal, potato,
guava, cucumber, onion and tulip, how many
plants have superior ovary? [Re-AIPMT-2015]
1) Six

2) Three

3) Four

4) Five

225
...
Stems modified into flat green organs
performing the functions of leaves are known
as [NEET-2016]
1) Scales

2) Cladodes

3) Phyllodes

4) Phylloclades

227
...
Tricarpellary, syncarpous gynoecium is found
in flowers of
[NEET-2016 Phase II]
1) Liliaceae

2) Solanaceae

3) Fabaceae

4) Poaceae

Prof
...
R
...
Sc
...
,Gold Medalist, SET/NET-JRF,GATE, DRDO,TIFR Qualified

Page: 21

1) Pitcher of Nepenthes
2) Thorns of Citrus
3) Tendrils of cucumber
4) Flattened structures of Opuntia
230
...
Match Column-I with Column-II and select
the correct option using the codes given below
[NEET-2016 Phase II]
Column-I

Column-II

a
...
Formation of

(ii) Pistillate

gametes
c
...
Unisexual female

(iv) Dikaryotic

flower Ascomycetes
1) a-(iv), b-(iii), c-(i), d-(ii)
2) a-(ii), b-(i), c-(iv), d-(iii)
3) a-(i), b-(ii), c-(iv), d-(iii)
4) a-(iii), b-(i), c-(iv), d-(ii)
232
...
How many plants among Indigofera, Sesbania,
Salvia, Allium, Aloe, mustard, groundnut,
radish, gram and turnip have stamens with
different lengths in their flowers?
[NEET-2016 Phase II]
1) Five

2) Six

3) Three

4) Four

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

229
...
Radial symmetry is found in the flowers of
[NEET-2016 Phase II]
1) Pisum

2) Cassia

3) Brassica

4) Trifolium

235
...
Coconut fruit is a

[NEET-2017]

1) Berry

2) Nut

3) Capsule

4) Drupe

237
...
Root hairs develop from the region of
[NEET-2017]
1) Elongation
2) Root cap
3) Meristematic activity
4) Maturation
239
...
Pneumatophores occur in
[NEET-2018]
1) Halophytes
2) Free-floating hydrophytes
3) Carnivorous plants
4) Submerged hydrophytes
241
...
Motegaonkar S
...
, M
...
Chem
...
Ray florets have
1) Inferior ovary

[NEET-2020]
2) Superior ovary

3) Hypogynous ovary 4) Half inferior ovary
244
...
The ovary is half inferior in [NEET-2020]
1) Brinjal

2) Mustard

3) Sunflower

4) Plum

246
...
Match Column -I with Column - II
...

(a)

(b)

(c)

(d)

1) (i)

(ii)

(iii)

(iv)

2) (ii)

(iii)

(iv)

(i)

3) (iv)

(ii)

(i)

(iii)

4) (iii)

(iv)

(ii)

(i)

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

242
...
Which one of the following plants shows
vexillary aestivation and diadelphous
stamens? [NEET-2022]
1) Colchicum autumnale
2) Pisum sativum
3) Allium cepa
4) Solarium nigrum
249
...
Identify the correct set of statements:

[NEET-2022]
(a) The leaflets are modified into pointed hard
thorns in Citrus and Bougainvillea
(b) Axillary buds form slender and spirally coiled
tendrils in cucumber and pumpkin
(c) Stem is flattened and fleshy in Opuntia and
modified to perform the function of leaves
(d) Rhizophora shows vertically upward growing
roots that help to get oxygen for respiration
(e) Subaerially growing stems in grasses and
strawberry help in vegetative propagation
Choose the correct answer from the options
given below:
1) (b) and (c) Only
2) (a) and (d) Only
3) (b), (c),(d) and (e) Only
4) (a), (b), (d) and (e) Only

Prof
...
R
...
Sc
...
,Gold Medalist, SET/NET-JRF,GATE, DRDO,TIFR Qualified

Page: 23

RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC**

Answer Key
1

4

36

2

71

3

106

2

2

1

37

1

72

3

107

2

3

1

38

3

73

2

108

3

4

2

39

1

74

2

109

4

5

3

40

1

75

1

110

2

6

4

41

4

76

2

111

1

7

3

42

4

77

1

112

4

8

4

43

4

78

4

113

4

9

1

44

3

79

1

114

1

10

4

45

3

80

4

115

2

11

2

46

1

81

1

116

4

12

3

47

3

82

2

117

3

13

2

48

2

83

2

118

2

14

4

49

4

84

2

119

3

15

3

50

2

85

4

120

3

16

1

51

4

86

1

121

4

17

2

52

1

87

3

122

1

18

2

53

2

88

1

123

4

19

3

54

4

89

2

124

3

20

1

55

2

90

1

125

2

21

2

56

4

91

1

126

2

22

2

57

4

92

2

127

2

23

3

58

1

93

1

128

1

24

3

59

1

94

3

129

1

25

4

60

1

95

3

130

4

26

4

61

1

96

1

131

3

27

3

62

1

97

2

132

2

28

4

63

3

98

2

133

1

29

3

64

2

99

3

134

4

30

2

65

4

100

4

135

1

31

2

66

1

101

3

136

1

32

2

67

3

102

2

137

4

33

1

68

4

103

1

138

2

34

3

69

4

104

1

139

1

35

4

70

1

105

1

140

2

141

3

176

1

211

1

246

2

142

1

177

1

212

2

247

4

143

3

178

2

213

4

248

2

144

3

179

4

214

4

249

2

145

2

180

3

215

1

250

3

146

3

181

3

216

3

147

1

182

2

217

4

148

2

183

2

218

3

149

1

184

2

219

4

150

2

185

2

220

3

151

3

186

2

221

4

152

1

187

4

222

1

153

3

188

2

223

2

154

1

189

1

224

1

155

2

190

3

225

3

156

3

191

3

226

4

157

2

192

1

227

3

158

2

193

4

228

1

159

1

194

2

229

1

160

4

195

1

230

4

161

4

196

3

231

4

162

1

197

2

232

4

163

2

198

3

233

4

164

2

199

2

234

3

165

3

200

2

235

3

166

3

201

4

236

4

167

1

202

2

237

2

168

3

203

4

238

4

169

3

204

1

239

2

170

2

205

4

240

1

171

4

206

1

241

2

172

2

207

2

242

2

173

4

208

1

243

1

174

2

209

2

244

1

175

1

210

3

245

4

Prof
...
R
...
Sc
...
,Gold Medalist, SET/NET-JRF,GATE, DRDO,TIFR Qualified

Page: 24



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