Search for notes by fellow students, in your own course and all over the country.
Browse our notes for titles which look like what you need, you can preview any of the notes via a sample of the contents. After you're happy these are the notes you're after simply pop them into your shopping cart.
Title: Edexcel as level biology question paper 2 june 2024 salters Nuffield + mark scheme
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE Biology Spec A (8BN0) Paper 02: Development, Plants and the Environment
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE Biology Spec A (8BN0) Paper 02: Development, Plants and the Environment
Document Preview
Extracts from the notes are below, to see the PDF you'll receive please use the links above
Edexcel as level biology
question paper 2 june
2024 salters Nuffield +
mark scheme
Please check the examination details below before entering your candidate information
Candidate surname
Centre Number
Other names
Candidate Number
Pearson Edexcel Level 3 GCE
Thursday 23 May 2024
Morning (Time: 1 hour 30 minutes)
Paper
reference
8BN0/02
Biology A (Salters Nuffield)
Advanced Subsidiary
PAPER 2: Development, Plants and the Environment
You must have:
Calculator, HB pencil, ruler
Total Marks
Instructions
Use black ink or ball-point pen
...
Answer all questions
...
the questions in the spaces provided
• Answer
– there may be more space than you need
...
•
marks for each question are shown in brackets
• The
– use this as a guide as to how much time to spend on each question
...
• You
questions marked with an asterisk (*), marks will be awarded for your ability to
• Instructure
your answer logically showing how the points that you make are related or
follow on from each other where appropriate
...
•
Try to answer every question
...
P74473A
©2024 Pearson Education Ltd
...
(a) The photograph shows a cross section through part of a plant stem
...
If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross
...
Write your answers in the spaces provided
...
Explain the importance of calcium ions to plants
...
...
...
...
...
(Total for Question 1 = 6 marks)
*P74473A0328*
3
Turn over
These cells also contain structures involved in protein synthesis
...
(i) Draw and label a nucleolus on the diagram
...
(1)
(1)
...
(2)
...
...
...
4
*P74473A0428*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
2 Prokaryotic and eukaryotic cells contain genetic material
...
The photograph shows a Golgi apparatus found in eukaryotic cells
...
(3)
...
...
...
...
...
...
...
...
...
...
...
This deficiency occurs because some of the cells in the eyes, called cone cells, are
either missing or do not work properly
...
(1)
...
The allele for normal colour vision is dominant (B)
...
(3)
...
...
...
...
...
(2)
...
...
...
00
B
0
...
50
D
0
...
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
4 (a) Eukaryotic and prokaryotic cells share some common features, although there are
differences in the structures of the two types of cell
...
The diagram shows the structure of a bacterium
...
(i) State what is meant by the term totipotent stem cell
...
...
...
...
(4)
...
...
...
...
...
...
(Total for Question 4 = 8 marks)
10
*P74473A01028*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
They contain stem cells that can give rise to specialised cells
...
A reintroduction project released 20 of these birds into the wild
...
This was used to determine the genetic diversity of this group of birds
...
The frequency of the dominant allele for
this gene was found to be 0
...
(3)
p2 + 2pq + q2 = 1
Answer
...
How many of the following statements could cause a change in
this equilibrium?
•
alleles will mutate due to selection pressure
•
some alleles may be lost over generations
•
some alleles may be introduced by migration of birds
(1)
A
0
B
1
C
2
D
3
*P74473A01128*
11
Turn over
(b) Reintroduction programmes must ensure that the proposed site is a
suitable environment
...
(1)
...
(3)
...
...
...
...
...
(3)
...
...
...
...
...
There are similarities and differences between the
structures of cellulose and starch
...
(4)
...
...
...
...
...
...
14
*P74473A01428*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
6 Fibres can be extracted from tissues of some plants
...
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
(b) Jute fibres can be used on their own or mixed with other materials to form
a composite
...
The table shows the results of this investigation
...
(3)
...
...
...
...
...
40
30
Tensile strength / MPa
20
10
0
0
5
10
15
Concentration of sodium hydroxide (%)
Devise an investigation to determine the concentration of sodium hydroxide that
produces the highest tensile strength in plant fibres
...
...
...
...
...
...
...
...
16
*P74473A01628*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
The results of this investigation are shown in the graph
...
...
...
...
...
(Total for Question 6 = 12 marks)
*P74473A01728*
17
Turn over
This forms recombinant chromosomes
...
The graph shows the effect of MSH4 gene activity on the percentage of
recombinant chromosomes formed during meiosis
...
45
40
35
30
Percentage of
recombinants (%)
25
Key
inactive MSH4
20
active MSH4
15
10
5
0
1
2
3
4
5
6
7
8
9
Chromosome number
(i) Calculate the ratio of the percentage of the recombinants for chromosome 2
when the MSH4 gene is inactive and active
...
18
*P74473A01828*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
7 Chromosomes are able to transfer sections of DNA between homologous pairs
during meiosis
...
(3)
...
...
...
...
...
Deduce how this can cause problems at fertilisation
...
...
...
...
...
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
(c) A mitotic index can be calculated to show the proportion of cells in a tissue
undergoing mitosis
...
(Source: STEVE GSCHMEISSNER / SCIENCE PHOTO LIBRARY)
Calculate the mitotic index for the intact cells in the photograph using
this formula
...
*P74473A02128*
21
Turn over
(d) Some plants grown for fruit have extra sets of chromosomes
...
(5)
...
...
...
...
...
...
...
...
(Total for Question 7 = 13 marks)
22
*P74473A02228*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
The table shows the chromosome number for three different species of
strawberry plant
...
Monoculture involves growing a single crop with no other species of plant
...
(2)
1
...
2
...
(b) Monoculture can result in an increase in pest species that damage crops
...
(Source: HEATH MCDONALD / SCIENCE PHOTO LIBRARY)
Which one of the following adaptations of aphids is a physiological adaptation?
(1)
A
dropping from plant stems when approached by predator species
B
long, thin mouthparts that are pushed into the phloem of the plant
C
mature individuals are green in colour
D
they can reproduce sexually or asexually
*P74473A02328*
23
Turn over
(c) Cotton is an example of a crop grown as a monoculture
...
...
...
...
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
(d) Cattle farming in Brazil has made use of monoculture pasture
...
This has resulted in a loss of biodiversity
...
These aim to provide
food for cattle and restore biodiversity
...
Scientists monitored the biodiversity of insect species in an area of monocultural
pasture and an area of agroforest
...
Total number of insects
Group of insects
Number of species
Agroforest
Monocultural
pasture
Agroforest
Monocultural
pasture
Hemiptera (bugs)
23 133
18 571
111
89
Hymenoptera
(bees and wasps)
12 503
7 075
348
270
Diptera (flies)
8 184
15 470
219
203
Coleoptera
(beetles)
2 772
171
348
306
Mantodea
(mantids)
13
10
3
1
(i) Calculate the percentage change in the total number of Diptera insects found
in agroforest compared with the monocultural pasture
...
(2)
...
Rodents
Bats
Key
Agroforest
Carnivores
Conventional
farming
Monkeys
Other large mammals
0
10
20
30
40
50
60
70
80
90
100
Percentage of farms (%)
The boxplot graphs show the number of plant species found in these two
types of farm
...
Agroforestry
Number of
plant species
26
Conventional farming
14
14
12
12
10
10
8
6
Number of
plant species
8
6
4
4
2
2
0
0
*P74473A02628*
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
The study involved 75 farms using agroforestry and 64 farms using
conventional farming methods such as monoculture pasture
...
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
Explain how a change from monocultural pasture to agroforestry can
increase biodiversity
...
...
...
...
...
...
...
...
...
...
...
...
We provide
a wide range of qualifications including academic, vocational, occupational and specific programmes
for employers
...
edexcel
...
btec
...
uk
...
edexcel
...
Pearson: helping people progress, everywhere
Pearson aspires to be the world’s leading learning company
...
We believe in every kind of learning, for all kinds of people, wherever
they are in the world
...
Find out more about how we
can help you and your students at: www
...
com/uk
Summer 2024
Question Paper Log Number P74473A
Publications Code 8BN0_02_2406_MS
All the material in this publication is copyright
© Pearson Education Ltd 2024
General Marking Guidance
•
All candidates must receive the same treatment
...
•
Mark schemes should be applied positively
...
•
Examiners should mark according to the mark scheme not
according to their perception of where the grade boundaries
may lie
...
All marks on the mark
scheme should be used appropriately
...
Examiners should always award full marks if deserved, i
...
if
the answer matches the mark scheme
...
•
Where some judgement is required, mark schemes will
provide the principles by which marks will be awarded and
exemplification may be limited
...
•
Crossed out work should be marked UNLESS the candidate has
replaced it with an alternative response
...
• C is incorrect because organic solutes are not transported through xylem vessels
...
Question
number
1(a)(iii)
Answer
Mark
The only correct answer is – B
•
A is incorrect because sieve tubes are not found in epidermal tissue
•
C is incorrect because sieve tubes are not found in sclerenchyma tissue
•
D is incorrect because sieve tubes are not found in xylem tissue
(1)
Question
number
1(b)
Answer
Additional guidance
Mark
An explanation that makes reference to three of the following:
•
used in calcium pectate (1)
•
found in the middle lamella (1)
•
needed to connect cell walls of neighbouring cells (1)
•
supports cellulose microfibrils in cell wall (1)
ALLOW pectin
ALLOW holds cells together
(3)
Question
number
2(a)(i)
Answer
•
Additional guidance
Mark
discrete ovoid drawn within boundary of nucleus and
labelled ‘nucleolus’
(1)
Question
number
2(a)(ii)
Answer
•
mitochondrion / mitochondria/ chloroplast
Additional guidance
Mark
(1)
Question
number
2(a)(iii)
Question
number
2(b)(i)
Answer
Additional guidance
Mark
An answer that makes reference to the following:
•
in chromosomes / as chromatin (1)
•
wrapped around histone (proteins) (1)
(2)
Answer
Additional guidance
An answer that makes reference to three of the following:
For full marks must have at least one
similarity
Mark
Similarity
•
both are composed of (flattened) stacks of membranes /
both are composed of {cisternae / membrane bound
sacs } (1)
•
both have vesicles (1)
ALLOW both are made of flattened
sacs
Difference
•
only the rER has ribosomes attached (1)
•
rER has interconnected sacs whereas these are
separated in the Golgi apparatus (1)
•
the membranes of the rER are connected to the
nuclear membrane (1)
(3)
Question
number
2(b)(ii)
Answer
Additional guidance
Mark
An answer that makes reference to the following:
•
proteins are folded in the rER (1)
•
proteins are modified within the Golgi apparatus (1)
•
proteins are packaged into {transport vesicles by rER /
secretory vesicles by Golgi apparatus } (1)
ALLOW {secondary / tertiary} structure
of proteins
ALLOW description of transport or
secretory function of vesicle
IGNORE proteins forming vesicles
(3)
Question
number
3(a)
Question
number
3(b)(i)
Answer
•
Additional guidance
locus / loci
(1)
Answer
Additional guidance
An explanation that makes reference to three of the following:
Marks can be awarded from correct
genetic cross diagrams
•
mother is {heterozygous / XB Xb} (1)
•
(to pass on red green colour deficiency) the child must
inherit the recessive allele from its mother (1)
•
if father has {recessive allele / genotype Xb Y} can
produce a daughter with { red green colour deficiency
/ genotype Xb Xb} (1)
•
a son (with red green colour deficiency) would have
the genotype Xb Y (1)
Mark
Mark
ALLOW mother has a dominant allele
and a recessive allele/ mother is a
carrier
(3)
Question
number
3(b)(ii)
Answer
Additional guidance
Mark
An answer that makes reference to two of the following:
•
the mother has one dominant allele / recessive allele not
expressed due to presence of dominant allele (1)
•
the dominant allele is expressed (1)
•
therefore the correct protein is produced (1)
(2)
Question
number
3(b)(iii)
Answer
Mark
The only correct answer is – B 0
...
00
•
C is incorrect because the answer is not 0
...
75
(1)
Question
number
4(a)(i)
Question
number
4(a)(ii)
Answer
Mark
The only correct answer is – A capsule
•
B is incorrect because Y is not labelling a mesosome
•
C is incorrect because Y is not labelling a plasmid
•
D is incorrect because Y is not labelling a ribosome
Answer
(1)
Mark
The only correct answer is – B smaller than in eukaryotes
•
A is incorrect because ribosomes in bacteria are not larger than in eukaryotes
•
C is incorrect because ribosomes in bacteria are the same size as in eukaryotes
•
D is incorrect because ribosomes in bacteria are not variable in size
(1)
Question
number
4(b)(i)
Question
number
4(b)(ii)
Answer
Additional guidance
Mark
An answer that makes reference to the following:
•
a cell that can differentiate (1)
•
into any type of (specialised) cell (1)
Answer
ALLOW a cell that can specialise
(2)
Additional guidance
Mark
An explanation that makes reference to four of the following:
•
cell receives a stimulus (1)
•
some genes are activated / differential gene expression
(1)
•
leading to transcription of genes / production of mRNA
from genes (1)
•
translation to produce protein (1)
•
protein determines {structure / function} of the cell (1)
ALLOW reference to transcription
factors /regulator proteins
(4)
Question
number
5(a)(i)
Answer
Additional guidance
Mark
Example of calculation
•
correct value for p2 (1)
0
...
32
(ALLOW 2 marks for 0
...
g
...
9%
OR
Polypropylene reduces tensile strength
by 519 MPa/ 92%
(3)
Question
number
6(c)
Answer
Additional guidance
Mark
An answer that makes reference to the following:
•
treat fibres with a range of sodium hydroxide
concentrations (1)
•
control a variable concerning the plant fibre (1)
E
...
species of plant, age of fibre,
length and width of fibre
...
g
...
•
add masses to fibre in increments until fibre breaks (1)
•
calculate tensile strength as force divided by cross
sectional area (of fibre) (1)
e
...
between 0 and 10%
ALLOW use of forcemeter to measure
force needed to break fibre
(5)
Question
number
7(a)(i)
Question
number
7(a)(ii)
Answer
Additional guidance
•
1:4
...
0
47
...
8
12
54
...
1
50
...
1
56
...
2
14
63
...
9
58
...
g 5mm in length
e
...
toluidine blue, (acetic) orcein
(5)
Question
number
8(a)
Answer
Additional guidance
Mark
An answer that makes reference to the following:
•
species richness / index of biodiversity (1)
ALLOW counting of number of species
in an area
(2)
•
Question
number
8(b)
Question
number
8(c)
genetic diversity / heterozygosity index (1)
Answer
Mark
The only correct answer is – D – they can reproduce asexually
•
A is incorrect because A is a behavioural adaptation
•
B is incorrect because B is an anatomical adaptation
•
C is incorrect because C is an anatomical adaptation
Answer
(1)
Additional guidance
Mark
An explanation that makes reference to the following:
•
more cotton plants can be grown / cotton is renewable (1)
•
therefore { does not run out / is available to future
generations} (1)
(2)
Question
number
8(d)(i)
Answer
Additional guidance
Mark
Example of calculation
•
correct values used to calculate change (1)
15 470 - 8 184 = 7286
(7 286 ÷ 15 470) x 100 = 47
...
1 (%)
ALLOW 1 mark for 47 (%)
Correct answer with no working
scores full marks
(2)
Question
Number
* 8(d)(ii)
Indicative content
Answers will be credited according to candidate’s knowledge and understanding of the material in relation to the
qualities and skills outlined in the generic mark scheme
...
Additional content included in the response must be scientific and relevant
...
4 compared with
2
...
The explanation will contain basic information with some
attempt made to link knowledge and understanding to the
given context
...
The explanation shows some linkages and lines of scientific
reasoning with some structure
...
The explanation shows a well-developed and sustained line
of scientific reasoning which is clear and logically structured
...
g
...
Link made between: species richness of
plants with greater variety of habitats
/niches leading to more insect species /
greater percentage of farms with
mammals
...
Registered company number 872828
with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom
Title: Edexcel as level biology question paper 2 june 2024 salters Nuffield + mark scheme
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE Biology Spec A (8BN0) Paper 02: Development, Plants and the Environment
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE Biology Spec A (8BN0) Paper 02: Development, Plants and the Environment