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Title: class 8
Description: This note provides a detailed explanation of the method of elimination, offering step-by-step guidance to help you grasp the concept with ease. By studying this, you'll gain a clear understanding of how to effectively apply the method of elimination in problem-solving..
Description: This note provides a detailed explanation of the method of elimination, offering step-by-step guidance to help you grasp the concept with ease. By studying this, you'll gain a clear understanding of how to effectively apply the method of elimination in problem-solving..
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Class Eight
Unit # 2
Q: Find the solution of the following question by using the method of
elimination
...
(2x – 3y = 6) ------ 1)
( 3x + 5y = 0) ------ 2)
To eliminate x or y we have to make them same in both eq 1 and eq 2
...
3(2x – 3y = 6)
6x – 9y = 18 ----- 3)
Now multiply eq 2 with 2
2(3x + 5y = 0)
6x + 10y = 0------- 4)
Now subtract eq no 3 and 4
Keep in mind that when we subtract 2 equations then the sign of lower
equation changes (if it is + then it will change to _ and if it is _ then it
will change to +)
6x – 9y = 18
+6x + 10y = 0
0x – 19y = 18
Now we will have to find the value of y
0x -19y = 18
To find the value of y divide -19 on both sides
0𝑥
−19
Y=
19𝑦
-
−19
=
18
−19
−18
19
We found the equation of y now to find the equation of x put value of y
in equation 1 which is
2x - 3y = 6
−18
2x - 3
2x +
19
54
19
=6
( - * - = +)
=6
Now taking L
...
M
(2𝑥∗19)+(54∗1)
19
38𝑥+54
19
=6
=6
Now multiply 19 on both sides
38𝑥+54
19
x 19 = 6 x 19
On left hand sides 19 will cancel out with 19
So,
38x + 54 = 114
Now subtract 54 on both sides of equation
38x + 54 - 54 = 114 – 54
38x = 60
( +54 – 54 = 0)
Now to find value of x divide 38 on both sides)
38𝑥
38
X=
=
60
38
60
(
38
38
38
= 1)
Cancel 60 and 38 with 2
As ( 60 ÷ 2 = 30 and 38 ÷ 2 = 19 ) so
X=
30
19
S0
X=
30
19
Y=
−18
19
Answer
Title: class 8
Description: This note provides a detailed explanation of the method of elimination, offering step-by-step guidance to help you grasp the concept with ease. By studying this, you'll gain a clear understanding of how to effectively apply the method of elimination in problem-solving..
Description: This note provides a detailed explanation of the method of elimination, offering step-by-step guidance to help you grasp the concept with ease. By studying this, you'll gain a clear understanding of how to effectively apply the method of elimination in problem-solving..