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Title: cbse board
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SAMPLE QUESTION PAPER
CHEMISTRY
CLASS XII
Design of Question paper
Time: 3 hrs
...
Weightage to different forms of questions
S
...


Type of
question

Marks per
Question

Total number
of Questions

Total
marks

1

VSA

1

8

8

2

SA I

2

10

20

3

SA II/Value
Based
Question

3

9

27

4

LA

5

3

15

30

70

Total

B
...

No
...
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C
...
However, internal choice in any one question
of two marks, any one question of three marks and all the three questions of
five marks weightage has been provided
...
Difficulty level of questions
S
...


Estimated difficulty
level

Percentage of marks

1

Easy

15

2

Average

70

3

Difficult

15

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S
...
UNIT

Maximum Marks:70

SAII(3)/
Value
SAI
based
VSA
(2
question LA
(1 Mark) Marks) (3marks) (5 marks)

1
...


Solutions

3
...


Chemical Kinetics

1(1)

5
...


General Principles and Processes
of Isolation of Elements

7
...


d & f- Block Elements

9
...


Haloalkanes and Haloarenes

11
...


Aldehydes, Ketones & Carboxylic
Acids

1(1)

13
...


Biomolecules

15
...


4 (2)
5 (1)

2(1)

TOTAL

*3(1)

5 (1)
5(2)

4(2)

5(3)
3(1)
3(1)

3(1)

3(2)

1(2)

4(2)

8(4)
5(1)

1(1)

5(1)

2(1)

3(2)

2(2)

4(2)
3(1)

4(2)
5(1)

4(2)

4(2)
3(1)

4(2)

Polymers

3(1)

3(1)

Chemistry in Everyday Life

3(1)

3(1)

Total:
Key: Total marks (no
...

- It will carry 3-5 marks
...
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SAMPLE QUESTION PAPER
CHEMISTRY (043)
CLASS-XII – (2013-14)
Time Allotted: 3 Hrs

Maximum Marks: 70

General Instructions:
1
...

3
...

5
...


All questions are compulsory
...
1-8 are very short answer questions and carry 1 mark each
...
9-18 are short answer questions and carry 2 marks each
...
19-27 are also short answer questions and carry 3 marks each
...
28-30 are long answer questions and carry 5 marks each
...


Q
...
2 Give the IUPAC name of the following compound:

Q
...
5 Write the reaction when glucose is heated with excess of HI
...
6 Which Xe compound has distorted octahedral shape?
Q
...
8 An alkoxide is a stronger base than hydroxide ion
...

Q
...

(b) Calculate limiting molar conductivity of CaSO4 (limiting molar conductivity of
2
-1
calcium and sulphate ions are 119
...
0 S cm mol respectively)
...
10 Rate constant K for first order reaction has been found to be 2
...
Calculate its
three-fourth life
...
0x10 sec
...


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11

Do the following conversions:
(i)
(ii)

Q
...
13

Methyl bromide to acetone
...


Chloroform and carbon tetra chloride
...


For a chemical reaction variation in rate with conc
...
—→
What is the order of the reaction?
What are the units of rate constant K for the reaction?
Q
...

(At
...
Of Fe=26u)
Q
...

(ii) Tertiary amines do not undergo acetylation reaction
...
16

Write the following name reaction:
(i) Gabriel phthalimide reaction
...


Q
...
The length of unit cell is
-8
found to be 4
...
Calculate atomic radius and density of silver
...
02x10 mol )
Q
...


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19 Manu and his father went to a shop to purchase a battery for their inverter
...
The battery with cadmium plates was more
expensive than the lead battery
...


After reading the above passage, answer the following questions:
a) As a student of chemistry, why would you suggest to Manu and his father to
buy the expensive cadmium plate battery
...

b) Which two values will you be promoting through your suggestions?
Q
...
21

Rough surface of catalyst is more effective than smooth surface
...

Ne gets easily absorbed over charcoal than He
...
(ii) Haematite oxidises carbon to carbon monoxide
...
22

What role does cryolite play in Hall Haraoult process?
How can alumina be separated from silica in a bauxite ore associated
with silica? Give equations also
...

(a)
(b)
(c)

Hypophosphorous acid is added to AgNO3 solution
...

XeF2 undergoes hydrolysis
...
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Q
...

(ii) A sparkless current is passed through oxygen to prepare ozone
...
Comment
...
24

(i)
(ii)

(iii)
Q
...

Name two fat storing tissues in human body
...
26

Antiseptics
Antioxidants
Narcotic analgesics

(a)

Write the names of the monomers of polymer used for making
unbreakable crockery
...

write the reaction of preparation of neoprene
...


(b)
(c)

PVC, Nylon 66, Natural rubber
...
27

Write the mechanism for preparation of ethanol from ethene
...
28

(a)

What is the freezing point of 0
...
Freezing point of
-1
benzene is 278
...
042kj mol
...

A doctor advised a person suffering from high blood pressure to take
less quantity of common salt
...
29

Calculate the boiling point of a solution containing 0
...
Assuming 84% dimerisation of acid
...
2 C and 2
...


State Raoult's law for the solution containing non-volatile solute
...


Account for the following :

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Cu has positive electrode potential in the first transition series
...

Potassium dichromate is a good oxidising agent in acidic medium
...

OR

(a) Compare non transition and transition elements on the basis of their
(i)
(b)

Give chemical reactions for the following observations:
(i)
(ii)
(iii)

Q
...


(a)

Potassium permanganate is a good oxidising agent in basic
medium
...

Potassium permanganate is thermally unstable at 513K
...


Ethanoic acid to ethanol
Propane-1-ol to propanal
Pent-3-en-2-ol to pent-3-en-2-one
Sodium benzoate to benzene

Arrange the following in the uncreasing order of:
i)
ii)
iii)

Methanal,
Propanal,
Butanone,
Ethanal,
Propanone
(nucleophilic addition reaction)
Formaldehyde, Acetone, Acetaldehyde (reactivity towards HCN)
Acetophenone,
p-tolualdehyde,
p-nitrobenzaldehyde,
Benzaldehyde (nucleophilic addition reaction)
OR

(a)

Bring out the following conversions:
...

Ethylcyanide to 1- phenyl propanone
...

Carboxylic acids have higher boiling point than alcohols
...


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Relatively large electron-electron repulsion among the lone pairs of F 2 molecule but they are
much closer to each other in Cl2 molecule
...


3,3-Di methyl-2-oxobutanoic acid
...


Temperature and activation energy are inversely proportional to each other
...


K4[Fe(CN)6]

1

–———→

5
...


XeF6

1

7
...


1

8
...


1

9
...


1

(b)

0

Λ m (CaSO4)

=
=
=

+ HI (excess)

0

0

n-hexane (C6H14)

2-

λ Ca2 + + λ SO4
2
-1
2
-1
119
...
0 S cm mol
2
-1
225
...


½
½

10
...
303
a
——
log ——
t
a-x

2
...
303
——
log
3
2
...
9066 x 10 x 0
...
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t3/4 = 5
...
303
= —— log
t

K

a
——
a-x

2
...
0 x10 (sec ) = ——
900
-4

a
log ——
a-x

-1


...
0x10
a
log ——
a-x

1/2

1/2

x 900

= ————————
2
...
0781)

= 0
...
197

a = 1
...
197x

x

0
...
197

= 0
...
1645 x 100 = 16
...
e 16
...


OMgBr
|
+
H3O
Cu
11
...

1
(CH3)2CO
+
H3O

...


(a) On heating chloroform and carbon tetrachloride with aniline and ethanolic potassium
hydroxide separately chloroform forms pungent smelling isocyanide but carbon tetra
chloride does not form this compound
...


1

13
...


1
-1

(ii) units of rate constant is mol L

1

s-

1

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Oxidation state of Fe in K3[Fe(CN)6] is
3+
5
+3 Configuration of Fe is [Ar]3d
3d




↿⇃

↿⇃

4s






3d

4p

↿⇃

4s

4p



it has 5 unpaired electrons in 3d orbital which get paired leaving behind one unpaired electron only
...

3d
4s
4p










Because of the presence of different no
...

1
15
...

1
(ii) Due to the absence of replaceable hydrogen atom at nitrogen
...
(i) Gabriel phathalimide reaction

1
1

( b) Hoffmann bromamide degradation reaction
R-C-NH2 + Br2 + 4NaOH → R-NH2 + Na2CO3 + 2NaBr + 2H2O

O
-8
-1
23
17
...
077 x 10 cm, Z = 4 , M = 108 g mol NA =6
...
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19
...
(i) Rough surface of a catalyst provides more surface area for adsorption
...

1
(iii) Ne has higher critical temperature i
...
1

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1

(b) Concentration of ore is carried out by digesting the powdered ore with a concentrated solution of
NaOH at 473-523 K and 35 -36 bar pressure
...

+ 3H2O → 2Na[Al(OH)4] (aq)

Al2O3 (s) + 2 NaOH(aq)

1

The resulting solution is filtered, cooled and neutralised by passing CO2 gas through it
...

2Na[Al(OH)4] (aq)

+ CO2(g) — →Al2O3
...

1470K
Al2O3
...
(i) H3PO3 + 2AgNO3 + H2O —— → 2Ag + HNO 3+ 2 H3PO4
(ii) 3Cl2 +6 NaOH (conc
...
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23(i)

1

(ii) Since the formation of ozone from oxygen is endothermic reaction silent electric discharge
decomposition
...


24 (i) Amylose is a long unbranched chain polymer

-D(+) glucose
...


prevents its

1

1/2
1/2

(ii) Globular protein and its shape is spherical
...


½ +1/2

25
...
e
...

½ +1/2

of

(ii) Antioxidants are the compounds which retard the action of oxygen on food and reduces its rate of
decomposition by oxidation
...
g BHA
½+1/2

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e
...
1
26
...


½+1/2

polymerisation
(ii) n CH2=C-CH=CH2————— —→

—[ —CH2-C =CH-CH2 —]n—

|

|

Cl

1

Cl

(iii) Nylon66 > Natural rubber > PVC

27
...
4, Tf0 = 278
...
042 KJ mol-1

RTf2 M
Kf = ———

8
...
4)2 x 78
= ——————————— = 5
...
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1000 x∆Hfus

1000 x 10
...
85
1/2 -1
= i-1 = -0
...
575

∆Tf = I Kf m = 0
...
4 = 1
...
4 – 1
...
25 K

½ + 1/2

(b) i) This solution has lesser vapour pressure due to stronger interactions between chloroform and acetone
molecules
...
of sodium and chloride ions in the body fluid which can
increase the osmotic pressure of body fluid i
...

1

OR

2C6H5COOH ———→ (C6H5COOH)2

1

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84 = —————

1/n – 1

½ +1/2

½ -1

0
...
42 =0
...
Kb
...
58 x 2
...
1 = 0
...
2 + 0
...
3340C

(b)Raoult,s law: The relative lowering of vapour pressure of the solvent over a solution is equal to the mol
fraction of non-volatile solute present in the solution
...
(i) Because oxygen forms multiple bonds with transition metals but fluorine does not form multiple bonds
...

1

(iii) 4f electrons of lanthanides is less effectively shielded by nuclear charge than 5f electrons of actinides
...


1

(v) The actinides show more number of oxidation states than lanthanides because in actinides 5f,6d and7s
levels have comparable energies
...
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(i) Oxidation states of transition elements differ from each other by unity
...


½+1/2

(ii) In transition elements higher oxidation states are favoured by heavier elements whereas in non transition
elements lower oxidation state is favoured by transition elements
...
(a) (i) Li AlH4/H3O+

1

1/2

(ii) PCC

1/2

(iii) PCC

1/2

(iv) sodalime

1/2

(b) (i) Butanone < Propanone < Propanal < Ethanal < Methanal
...


1

(iii) Acetophenone< p- Tolualdehyde< Benzaldehyde ...
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1

NMgBr
Ether



H3O+

C6H5
|

(ii) CH3—CH2—CN + C6H5MgBr ———→ CH3CH2—C—C6H5 ——→C2H5—C=O 1

(b) (i) Because chloroacetate ion is more resonance stabilised than acetate ion due to the presence of electron
withdrawing chlorine atom (+I effect)
...

1
(iii) Because of –I effect of nitro group stability of benzoate ion increases in 4-nitro benzoic acid
...


1

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Title: cbse board
Description: this is for dclass 10 and 12 for preparing thier board exam and now they can easily get score high in their exam.please download it more and share it as you can.