Notesale: Turn your study into money

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w

w
ap
eP

m

e
tr

...
It shows the basis on which Examiners were instructed to award marks
...

Mark schemes must be read in conjunction with the question papers and the report on the
examination
...


CIE is publishing the mark schemes for the May/June 2009 question papers for most IGCSE, GCE
Advanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level syllabuses
...
c

MARK SCHEME for the May/June 2009 question paper

s
er

International General Certificate of Secondary Education

Page 2

Mark Scheme: Teachers’ version
IGCSE – May/June 2009

M marks are given for a correct method
...

B marks are given for a correct statement or step
...

P marks are given for accurate plotting of points
...

Abbreviations
cao
cso
ft
oe
soi
ww
www

correct answer only
correct solution only
follow through
or equivalent
seen or implied
without working
without wrong working

© UCLES 2009

Syllabus
0607

Paper
04

Page 3

1 (a)

(b)

Mark Scheme: Teachers’ version
IGCSE – May/June 2009
200 (or 2200) ÷ 20
10 (or 200) × 11

Syllabus
0607

M1
M1

57
...
50)
3

(c)

67
...
04 more than once
67
...
or 67
...
2 (or 37
...
21)

B1

(b)

37

B1

(c)

36

B1

(d)

36

B1

(e)

2

B1

2 (a)

[5]
3 (a)

( x + 2 y )(2 + p )

B2

B1 for 2( x + 2 y ) + p ( x + 2 y ) o
...


(b)
If using formula, M1 for
seen

2

2 − 4( 2)(−5)

p + (or −) q
then M1 for
r

and if form

p = –2 and r = 2 × 2
Reasonable sketch of parabola (U shape)
cutting x-axis either side of y-axis – dep
–2
...
16

(c)

M1
M1dep
A1, A1

y=k w

M1

4=k 9
( y) = 8

M1
www3

A1

 − 2 ± 44 




4



SC1 for –2
...
2 or
–2
...
158… with or without working
SC2 for –2
...
16 without working
If using

k=

4
3

y
4

=

36

9
implies M2

M2

[9]

© UCLES 2009

Page 4

Mark Scheme: Teachers’ version
IGCSE – May/June 2009

Syllabus
0607

Paper
04

B1

4 (a)
K

(b)

L

B2

B

SC1 for any 4 of the 5 parts shaded

B2

A

Allow B2 for embedded if clear
If B0, B1 for Venn diagram with universal
set containing 2 intersecting sets or
6 + 10 – (20 – 8) or better seen
or 10 – x + x + 6 – x = 20 – 8 oe
[5]

C

4

(c)

002

5 (a)

(i)
051
001
05
05
05
05
4

2

0
0

2-

Correct shape
Point of inflexion at origin

B1
B1dep

Correct shape
Correct position relative to axes

B1
B1dep

(b)

0, 4 cao

B1,B1

Do not allow any decimals in answers

(c)

(3, –27)

B1,B1

Do not allow any decimals in answers

(d)

–2
...
325…), 4
...
407 – 4
...
3 and 4
...
88 (9
...
6 ÷ 1
...
6 × 60 oe
47
...
61 – 47
...
21, 0
...
5) and (1, 1) 2 mm accuracy

B1
B1
B1dep

B1 ft
B1 ft

Correct shape
...
5 and 1
...


ft only if their graph is a reflection
correct or ft
[8]

© UCLES 2009

Page 6

Mark Scheme: Teachers’ version
IGCSE – May/June 2009
2

8 (a) (i)

2

3 +5 −7

2

M2

2
...
5

A1

120°

(ii) 0
...
5(0) (6
...
09 without working SC1
(For Hero’s formula s = 7
...
1 to 4
...
05…
...
236
...
2
or SC1 for both 3 sf (or more) numbers
seen
[4]

© UCLES 2009

Page 7

Mark Scheme: Teachers’ version
IGCSE – May/June 2009

Syllabus
0607

Paper
04

Throughout the question ratios score
zero
...
f
...
g
...

For method marks only accept
probabilities between 0 and 1

10

(a) (i)
(ii), (iii)
(b) (i)

(ii)

14
28

oe ,

× 14
28

14
28
196
784

5
2 × 14 × 28
28

(iii)

oe

(0
...
179)
5
28

9
9
1 − 28 × 28
703
784

9
28

(0
...
5
5

M1
A1
M1
A1

0
...
1786

M1

oe (0
...
8966 – 0
...
5, 0
...
1786, 0
...
2
cao
www2

sin X =

sin 26
...
5

21
...
82 – 21
...
5
e
...

=
2
...
9546
...
28 (6
...
284)

Syllabus
0607

www2

M1
A1

Accept 2 π

www2

M1
A1

Accept 12 π

(c)

their (b) × 3
113 (113
...
1
...
2 – 166
...
7 (37
...
70
...
9, 53
...
386h − 16
...
3855 – 0
...
16…
...
9

B2

If seen in correct form B1 for 0
...
2
...
39)
SC1 if in correct form and both terms
correct to 2 sf

(ii) Line through their (179
...
2) seen to be
plotted
...
2 – 3
...
6…if ft in (b)) or region T2 if (a)
correct (ans 2
...

ft their region in (b) if B1 scored
(ans 6 if ft in (b)) or region T2 if (a)
correct (ans 2)
...
Only full ft solutions and at
least 2 pairs score B2 ft
...
, y = …
...


360x + 2880 – 360x = 16x2 + 128x
16x2 + 128x – 2880 = 0
x2 + 8x – 180 = 0

(b) (i)

B1

E1

Dependent on M2 M1
...
Condone the absence of = 0
only once

B2

If B0, SC1 for ( x ± p )( x ± q ) with
values of 10 and 18 for p and q

x
x+8

360

–

360

(ii) (x + 18)(x – 10)

(iii) –18, 10 ft

B1 ft

Correct or ft SC1

(iv) 10

B1 ft

Can ft a positive root
[11]

© UCLES 2009



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