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Title: OCR A Chemistry F322 Module 2
Description: This is aimed for AS level students in the UK studying OCR A Chemistry F322 Module 2. It has an outlined style which makes it easy to study and revise from.
Description: This is aimed for AS level students in the UK studying OCR A Chemistry F322 Module 2. It has an outlined style which makes it easy to study and revise from.
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CHEMISTRY
2
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1 ALCOHOLS
HIGH MELTING AND BOILING POINTS OF ALCOHOLS
Because of the presence of hydrogen bonds between alcohol molecules
LOW VOLATILITY OF ALCOHOLS
Because of high boiling points
Harder to turn from a liquid into a gas
SOLUBILITY
Alcohols dissolve in water
Hydrogen bonds form between alcohol and water molecules
Solubility decreases as the chain length increases
A larger non-polar hydrocarbon chain doesn’t form hydrogen bonds with water
molecules
INDUSTRIAL PRODUCTION OF ETHANOL
Hydration of ethene
Fermentation
HYDRATION OF ETHENE
Reaction of ethene with steam
H2C=CH2 (g) + H2O (g) CH3CH2OH (l)
CONDITIONS FOR HYDRATION OF ETHENE
Carried out at high temperature and moderate pressure (300⁰C 60 atm)
In the presence of an acid catalyst (H3PO4)
PROCESS OF HYDRATION OF ETHENE
Reversible reaction
Only 5% of ethene is converted each time the reagents pass through the reactor
Unreacted gases pass through the reactor again
95% conversion, overall
100% atom economy
FERMANTATION FROM SUGARS
Carbohydrates (sugar or starch) are converted into ethanol and CO2 (g)
C6H12O6 (aq) 2CH3CH2OH (aq) + 2CO2 (g)
CONDITIONS FOR FERMENTATION
Low temperatures (below 37⁰C so enzyme doesn’t denature)
Catalysed by yeast (enzyme in yeast)
Absence of air – anaerobic (prevent oxidation of ethanol)
© SMARTBERG 2015
This work is shared under a Creative Commons Attribution-NonCommercial-NoDerivatives license
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g
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OXIDATION OF TERTIARY ALCOHOLS
Tertiary alcohols are resistant to oxidation
The oxidising agent remains orange in colour
ALDEHYDES
C=O double bond
C-H bond
CARBOXYLIC ACIDS
C=O double bond
C-O-H bond
KETONE
C=O double bond
OXIDATION EQUATIONS
[O] for primary alcohol to aldehyde and secondary alcohol to ketone
2[O] for primary alcohol to carboxylic acid
Products include either an aldehyde, carboxylic acid or ketone and H2O
ESTERIFICATION
An alcohol is warmed with a carboxylic acid
In the presence of an acid catalyst (concentrated H2SO4)
Produces an ester and water
ESTERIFICATION REACTION
E
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propanoic acid + methanol methyl propanoate + H2O
CH3CH2COOH + CH3OH CH3CH2COOCH3 + H2O
–OH taken from carboxylic acid and –H taken from alcohol to form H2O
DEHYDRATION OF AN ALCOHOL
Elimination reaction
1 molecule 2 molecules
Saturated unsaturated
Forms alkenes
CONDITIONS FOR DEHYDRATION OF AN ALCOHOL
Catalysts are concentrated phosphoric acid, H3PO4 or concentrated sulfuric acid, H2SO4
Heated under reflux
DEHYDRATION EQUATION
OH group from one carbon atom lost
H atom from adjacent carbon lost
Double bond forms between these two carbons
E
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ethanol ethene + H2O
2
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2
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GENERAL FORMULA OF HALOGENOALKANES
CnH2n+1X
HALOGEN PREFIXES
F is fluoroCl is chloroBr is bromoI is iodo-
REACTIVITY OF THE HALOGENOALKANES
Halogenoalkanes are polar (different electronegativities)
Electronegativity decreases down the group
Decrease in polarity down the group
Electron-deficient carbon atom attracts nucleophiles
HYDROLYSIS OF HALOGENOALKANES
Nucleophilic substitution reaction
Halogenoalkanes react with an aqueous solution of hot hydroxide ions
Usually aqueous sodium hydroxide
Product is an alcohol
Carried out under reflux
HYDROLYSIS EQUATION
E
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CH3CH2CH2Cl (aq) + OH- (aq) CH3CH2CH2OH (aq) + Cl- (aq)
HYDROLYSIS MECHANISM
During hydrolysis, the halogen atom is replaced by the hydroxide ion
Lone pair of electrons of hydroxide ion are donated to the electron-deficient carbon atom
Covalent bond formed between oxygen (of the hydroxide ion) and carbon atom
Carbon-halogen bond breaks by heterolytic fission
Halide ion is formed
DRAWING HYDROLYSIS MECHANISM
Show relevant dipoles
Show lone pair and negative charge
Curly arrow from lone pair to carbon atom
Curly arrow from bond to electronegative iodine atom
RATES OF HYDROLYSIS EXPERIMENT
Aqueous silver nitrate in ethanol
Heated with halogenoalkane
H2O in mixture is the nucleophile
HYDROLYSIS EQUATION
Halogenoalkane (aq) + H2O (l) alcohol (aq) + H+ (aq) + halide ion (aq)
AgNO3 (aq) reacts with halide ions
© SMARTBERG 2015
This work is shared under a Creative Commons Attribution-NonCommercial-NoDerivatives license
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2
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CALCULATING ATOM ECONOMY
Addition reactions have 100% atom economy
Substitution reactions are less efficient
BENEFITS OF HIGH ATOM ECONOMY
Reduction of waste
ABSORPTION OF INFRARED RADIATION
Covalent bonds vibrate with bending or stretching motion
FUNCTIONAL GROUPS IDENTIFIED WITH INFRARED SPECTROSCOPY
Hydroxyl (O-H) group in alcohols
Carbonyl (C=O) group in aldehydes and ketones
Carboxyl (COOH) group in carboxylic acids
INFRARED SPECTRUM OF ALCOHOLS
Peak in the first region only
O-H bond
INFRARED SPECTRUM OF ALDEHYDES AND KETONES
Peak in the second region only
C=O bond
INFRARED SPECTRUM OF CARBOXYLIC ACIDS
Peaks in both region
O-H bond
C=O bond
APPLICATIONS OF INFRARED SPECTROSCOPY
Breathalysers – measures ethanol in the breath
Drug analysis
Quality control in perfume manufacture
USES MASS SPECTROMETRY
Determination of relative isotopic masses
Method for identifying elements
Monitoring levels of pollution
CALCULATING RELATIVE ATOMIC MASS
Add relative abundances of isotopes
E
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79% Mg-24, 10% Mg-25, 11% Mg-26 – (24x79)+… divided by 100
MASS SPECTRUM
Shows mass to charge ratio (m/z)
Shows relative abundances of isotopes
Fingerprint for molecules
© SMARTBERG 2015
This work is shared under a Creative Commons Attribution-NonCommercial-NoDerivatives license
...
Title: OCR A Chemistry F322 Module 2
Description: This is aimed for AS level students in the UK studying OCR A Chemistry F322 Module 2. It has an outlined style which makes it easy to study and revise from.
Description: This is aimed for AS level students in the UK studying OCR A Chemistry F322 Module 2. It has an outlined style which makes it easy to study and revise from.