Notesale: Turn your study into money

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A Guide to Motion in One Dimension
Teaching Approach
In this series we continue on from the series on vectors and scalars by investigating the
differences between distance and displacement, as well as between speed and velocity
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A simple ticker timer experiment is demonstrated
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Because this series sets the foundational understanding for future work on motion, it is
important to get learners to do simple practical activities related to motion
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They could use marbles on flat and inclined planes, or the teacher could get
each learner to run a finger along the edge of the desk to represent examples of motion
described by the teacher, such as 20 cm forward with constant velocity
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The distances
between the objects can be measured and analysed in the same way as done with the ticker
timer results
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Video Summaries
Some videos have a ‘PAUSE’ moment, at which point the teacher or learner can choose to
pause the video and try to answer the question posed or calculate the answer to the problem
under discussion
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Mindset suggests a number of ways to use the video lessons
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Then ask learners to
watch a video related to the lesson and to complete the worksheet or questions, either in
groups or individually
 Worksheets and questions based on video lessons can be used as short assessments or
exercises
 Ask learners to watch a particular video lesson for homework (in the school library or on
the website, depending on how the material is available) as preparation for the next days
lesson; if desired, learners can be given specific questions to answer in preparation for
the next day’s lesson

1
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We look at the linear movement of a ball being thrown straight up into the air
and then caught again
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2
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It is noted that this is a scalar quantity, and that the SI units are metres per
second
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Average Velocity and Unit Conversions
In this lesson average velocity is described as change in position (displacement) versus
time and is therefore a vector
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4
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It is shown in this
lesson that acceleration can be both negative and positive
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Resource Material

1
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Average Speed

3
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Acceleration

http://www
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ca/newnotes
/20/unit01_kinematicsdynamics/chp0
3_kinematics/lesson09
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http://physics
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http://www
...
com/watch?v=ZS
mz2XAjl1E

An explanation of reference frames
and relative speed
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http://physics
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com/que
stions/29/how-to-calculate-averagespeed

A question and answer site on
average speed
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batesville
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in
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html

A resource on average speed
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khanacademy
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http://www
...
com/cla
ss/1dkin/u1l1d
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https://www
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org/scienc
e/physics/one-dimensionalmotion/displacement-velocitytime/v/calculating-average-velocity-orspeed

An example of calculating speed and
velocity
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physicsforums
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php?t=200055

Converting km/hr to m/s
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mathsisfun
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html

How to safely convert from one unit
to another
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phyastr
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edu/hbase/acca
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http://physics
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Task
Question 1
1
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2 What distance has the ball moved through?

Question 2
John runs 10 metres forwards and walks 5 metres back, and takes 20 seconds to do this
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1 What is John’s average speed?
2
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3
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3
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Question 4
If a car travels along a straight road at 120 km∙h-1 for 15 minutes, how far in metres has it
travelled?

Question 5
If a car travels in a straight line at 80 km∙h-1 for 15 minutes, and then 100 km∙h-1 for 30
minutes, what is the average speed of the car in kilometres per hour?

Question 6
What is the acceleration of a car travelling west, if it goes from rest to a velocity of 50 km∙h -1
in 6s? Hint: Remember to convert the units to SI units

Question 7
A driver travels east at 100 km∙h-1 when she sees a speed trap ahead
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It takes her 4s to slow down to the correct speed
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1 Total displacement = 0 mm as it returns to where it starts
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2 Total distance = 2 x 300 mm = 600 mm

Question 2
2
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Therefore,
m∙s

Average Speed =

-1

2
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-1

m∙s forwards

Average velocity =

Question 3
3
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2 Speed = 100 x 1000 / 3600 = 27,78 m∙s

-1

Question 4
Velocity =
Therefore, displacement = velocity x time
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Therefore, displacement in kilometres = 120 x 0,25 = 30 kilometres
Therefore, the car travelled 30 x 1000 = 30 000 metres, forwards
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So, distance = speed x time (hrs) = 80 x 0,25 = 20 km in the first part
And the second part the distance = speed x time (hrs) = 100 x 0,5 = 50 kilometres
Therefore the total distance is 70 km
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-1
Velocity = 50 x 1000 / 3600 = 13,89 m∙s west
-2

Therefore acceleration =

m∙s west

Question 7
Acceleration =
We first need to convert the velocities to SI units
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Therefore, acceleration =

m∙s

-2

This means that the car was slowing down in the easterly direction
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Acknowledgements
Mindset Learn Executive Head
Content Manager Classroom Resources
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Graphics

Cezanne Scheepers
Belinda Renney
Alriette Gibbs
Nonhlanhla Nxumalo
Niki Montgomery
Abram Tjale
James Tselapedi
Wilson Mthembu
Wayne Sanderson

Credits

This resource is licensed under a Attribution-Share Alike 2
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When using
this resource please attribute Mindset as indicated at http://www
...
co

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