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Title: Differentiation
Description: Differentiation-Rules Exercise Questions and Answers
Description: Differentiation-Rules Exercise Questions and Answers
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1)
Derivative the basic rule:
Where the Function is π¦ = π₯ n
The Derivative ππ¦ /ππ₯ = n x π₯ (n-1)
Example:Function
π¦ =π₯ 2
Derivatives
ππ¦ / ππ₯ = 2 x π₯ (2-1) = 2π₯
Questions and Answers
I
...
π¦ =π₯ -2
ππ¦ / ππ₯ = -2 x π₯ (-2-1) = -2 π₯ -3
III
...
π¦ =8π₯ 4
ππ¦ / ππ₯ =4 x 8π₯ (4-1) = 32π₯ 3
II
...
π¦ =1/2π₯ 9
ππ¦ / ππ₯ =9 x 1/2π₯ (9-1) = 4
...
π¦ = 6π₯ 4+27
ππ¦ / ππ₯ = 4 x 6π₯ (4-1) = 24π₯ 3
II
...
π¦= 1/6π₯ 2 - 12π₯ 5
ππ¦ / ππ₯ = 2 x 1/6π₯ (2-1) - 5 x 12π₯ (5-1)
= 1/3π₯ - 60π₯ 4
II
...
ππ/ ππ₯
π2
= π₯ 2(21π₯ 2+1) β (7π₯ 3+π₯) 2π₯
(π₯ 2)2
= 21π₯ 4 + π₯2 -14π₯ 4 - 2π₯ 2
π₯4
= 7π₯ 4 - π₯ 2
π₯4
ππΌπΌ) π¦ = 4π₯ 2 + 3
π
2π₯ -1
π
ππ¦ / ππ₯ = π x ππ/ ππ₯ β π x ππ/ ππ₯
(2π₯ -1)2
= (2π₯-1)8π₯ β (4π₯ 2+3)2
4π₯ 2 - 4π₯ +1
= 16π₯ 2 - 8π₯ - 8π₯ 2 - 6
4π₯ 2 - 4π₯+1
= 8π₯ 2-8π₯-6
4π₯ 2-4π₯+1
ππΌπΌπΌ) π¦ = 4 - 5π₯
(2π₯-1) (3π₯+2)
π
π
ππ¦ / ππ₯ = n x ππ/ ππ₯ β m x ππ/ ππ₯
π2
= [(2π₯-1) (3π₯+2)]-5 β [(4-5π₯) (12π₯+1)]
[6π₯ 2 + π₯ -2]2
= (6π₯ 2+4π₯-3π₯-2)-5 - (48π₯ + 4 - 60π₯ 2 - 5π₯)
36π₯ 4 + 12π₯3 - 23π₯ 2 + 4
= (-30 π₯2 - 20π₯ + 15π₯+10) (-48π₯ β 4 + 60π₯ 2 + 5π₯)
36π₯ 4 + 12π₯3 - 23π₯ 2 + 4
= -30π₯ 2 - 5π₯ +10 - 43π₯ + 60π₯ 2 - 4
36π₯ 4 + 12π₯3 - 23π₯ 2 + 4
= 30π₯ 2 - 48π₯ + 6
36π₯ 4 + 12π₯3 - 23π₯ 2 + 4
7)
Derivation function of a function where π= (2π+6)3 and the expression in the
brackets is a derivatization functions say that is π = (2π+6) the code
expression can be written as π=π3
In that cases he rule for derivation is π π / π π = π π / π π x π π/ π π
Which is known as the chain rule
...
ππ/ ππ₯
= 4π₯ x 1/π₯ + π₯ x 4
= 4π₯ (1/π₯+1)
g)
π
π
π¦ = (1+ π₯2) πax
ππ¦ / ππ₯ = (1+π₯ 2) ππax + πax x 2x
πax (1+π₯ 2)x a +2π₯
h)
π π
π¦ = eπ₯ In π₯
ππ¦ / ππ₯ = eπ₯ x 1/π₯ + π₯ x πx
πx (1/π₯+π₯)
Title: Differentiation
Description: Differentiation-Rules Exercise Questions and Answers
Description: Differentiation-Rules Exercise Questions and Answers