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Title: OCR MEI B Mathematics Statistics
Description: OCR MEI B Mathematics Statistics
Description: OCR MEI B Mathematics Statistics
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MM Applied Cheat Sheet β AS Stats
Notations, Modelling, Rules and Reminders
Probability β(π); Expectation πΌ(π); Variance πππ(π)
π; = β―: definition not property
Ξ£: summation operator
Ξ : product operator
π β π: X and Y independent
π βΌ β―: X follows β¦
π: mean; πΜ: estimator (unknown)
π
βπ₯ =
π₯=1
π₯(π₯ + 1)
2
π
β π₯2 =
π₯=1
-
π₯(π₯ + 1)(2π₯ + 1)
6
Draw Venn diagram for set theory
...
π₯ β [π, π) means include a exclude b in range
1
β2π
π
β
π₯2
2
can be written as
1
β2π
π₯2
expβ‘{β }
2
MM Applied Cheat Sheet β AS Stats
1
...
β(π΄π ) = 1 β β(π΄)
2
...
β(π΄ βͺ π΅) = β(π΄) + β(π΅)
4
...
2 Independence
β(π΄ β© π΅) = β(π΄) Γ β(π΅)
A family of events π = {π΄πΌ , π β πΌ} independent: β(ππ΄π ) = β β (π΄π )
A family of events pairwise independent (all combos independent): β(π΄π β© π΄π ) = β‘β(π΄π )β‘β(π΄π )
1
...
4 Partition Theorem
{πΈπ }πβ₯1 is a partition of Ξ© s
...
any event cannot happen
together at the same time
...
πΈπ β© πΈπ = β
2
...
β(π΄ = 1|π΅ = 1) =
β(π΄
= 1|π΅ = 1)
β(π΅=1)
β(π΅ = 1|π΄ = 1)β‘β(π΄ = 1)
=
β(π΅ = 1|π΄ = 1)β‘β(π΄ = 1)
+β(π΅ = 1|πΆ = 1)β‘β(πΆ = 1)
β¦
MM Applied Cheat Sheet β AS Stats
2
...
Pre-image of an event, ie
...
If domain of X finite/countable subset of β, then RV is discrete
3
...
ie
...
Probability mass function of π pmf is a function to show the true probability of a random
variable, ie
...
2 Expectations
(Or the expected value π) is actually just the average
...
1
...
3
...
πΌ(β(π₯)) = βππ₯ β(π₯)β‘β(π = π₯)
πΌ(ππ + π) = πβ‘πΌ(π₯) + π
πΌ(π(π)) + πΌ(π(π)) = πΌ(π(π₯)) + πΌ(π(π₯))
πΌ(π(π)) β πβ‘πΌ(π)
2
...
4 Expectation and Variance of 2 RVs
1
...
πΌ(ππ + ππ) = πβ‘πΌ(π) + πβ‘πΌ(π)
3
...
πππ(π + π) = πππ(π) + πππ(π)
MM Applied Cheat Sheet β AS Stats
3
...
2 outcomes
2
...
2 Binomial
π~π΅ππ(π, π):
1
...
of exp
...
Each exp
...
Each exp
...
Independent
Just the Tipβ’: On calculator,
use Binomial PD for β(π =
π₯) and Binomial CD for
β(π β€ π₯)
β(π = π₯) = πππΆ β‘π π₯ β‘(1 β π)1βπ₯
πΌ(π) = ππ
πππ(π) = ππ(1 β π)
3
...
X = freq
...
Random and independent (events cannot happen at same time)
3
...
4 Uniform
1
β(π = π₯) { π β‘π₯ = 1β‘π‘πβ‘π
0
1+π
πΌ(π) =
2
π2 β 1
πππ(π) =
12
3
...
π~π΅ππ(π)
2
...
of trials until first success
β(π = π₯) = (1 β π)π₯β1 π
1
πΌ(π) =
π
1βπ
πππ(π) =
π2
MM Applied Cheat Sheet β AS Stats
4
...
State null and hypothesis testing (these are in probability)
2
...
Let π be β¦β
3
...
State significance level πΌ
5
...
Calculate the p-value (probability under H0 that test statistic is at least as extreme as observed
value) by subbing in the range of value (inclusive) of π₯ that falls under the probability (eg
...
Conclusion
a
...
If p-value > πΌ: βinsufficient evidence to reject H0β
4
...
Consider the probability under H0 and what H1 is (larger/smaller/not H0)
πΌ
6
...
List range of values from 0 to π
8
...
For two-tailed: each value, find β(π β π)using calculator where PD
has X for the value currently testing
9
...
1 Introduction to Continuous Random Variables
To find probability of RV which can take uncountably infinite possible values, area can be found by
definition each value not as a line on the graph (where β« π(π₯) = 1 as total prob ability has to =1)
but as a strip of width πΏπ₯
...
c
...
f
...
ππ (π₯) β₯ 0
βπ₯ β β
β
2
...
t
...
d
...
d
...
(probability density function) [equation of curve]
- Not a probability
- Is equation of curve
- Find c
...
f
...
d
...
at range b to a where π₯ β [π, π)
π
ππ (π₯) =
πΉ (π₯)
ππ₯ π
At any point for which ππ (π₯) is continuous
N
...
: for a point, p
...
f
...
equation of curve is always true for any point), but the point
does not contribute to c
...
f
...
d
...
is easier to find as it is the equation of the line
N
...
: for c
...
f
...
d
...
ranges are π₯ β [π, π)
For continuous RV with p
...
f
...
t
...
2 Normal Distribution (Gaussian)
X: a continuous RV ~ standard normal distribution if p
...
f
...
d
...
satisfies:
π₯
πΉπ (π₯) = β(π β€ π₯) = β« ππ (π’) ππ’
ββ
Where ππ₯ (π₯) satisfies
1
...
β«ββ ππ₯ (π₯) ππ₯ = 1
π
s
...
ππ (π₯) = ππ₯ πΉπ (π₯) where πΉπ (π₯) is continuous
Thus modelled as π~π©(0, 1); β‘πΌ(π) = 0, πππ(π) = 1
2
π₯
β 1
Where β«ββ
πβ 2
β2π
=1
N
...
: πΌ(π) = 0 as symmetrical about π₯ = 0
1
...
(0,
) is a stationary point and a global maximum
β2π
3
...
Transformation ofππ (π₯) =
a
...
Scaling:
1
1
β2π
π
1
β2π
π
(π₯βπ)2
β 2
π₯2
β2
valid as integrating from -a to a still gives 1
π₯2
π β2π is not valid as enlarging it changes the area
...
Linear transformation:
1
β2π
π
(π₯βπ)2
β
2π
1
not valid
...
Ξ¦(βπ₯) = 1 β Ξ¦(π₯) if π₯ > 0 as it is symmetrical about π₯ = 0
β(π β€ π₯) = β(ππ + π β€ π₯)
π₯βπ
= β(π β€
)
π
π₯βπ
= Ξ¦(
)
π
5
...
The discrete distribution must be approximately normal
2
...
Provided continuity correction is done, where
a
...
5 β€ ππ < π + 0
...
B
...
β(π < ππ β€ π) β β(π + 0
...
5)
c
...
5 β€ ππ < π β 0
...
MM Applied Cheat Sheet β AS Stats
7
...
ππ are iid RVs (all follow
distribution as the population)
...
Sample mean: π; = π βππ=1 ππ
1
2
...
Sample variance: π 2 (ππβ‘π2 ); = πβ1 βππ=1(ππ β π) [Sample deviation: βπ 2]
Often written ππ₯π₯ ; = βππ=1(ππ β π)
2
1
4
...
2 Testing Sample Mean Using Normal Distribution
Let ππ , π = 1, 2, β¦ , π be a random sample from the population
...
β΅ mean less affected by
extreme values
β΄ variance less
1
...
If π 2 unknow -> use π 2 to replace π 2 provided π β₯ 50
1
π 2 = ππ₯π₯
π
Where ππ₯π₯ = βππ=1(π₯π β π₯)2
2
Or = βππ=1 π₯ 2 β ππ₯
Thenπ~π©(π,
π2
π
π
π₯π₯
= π(πβ1)
)
Hypothesis Testing
1
...
β
2
...
Layout H0, H1, πΌ
1
1
4
...
State the π under H0 which will be given by the question: βUnder H0: π~(β¦ , β¦ )β
6
...
Compare π₯ and ππ
...
If π₯ < ππ : βinsufficient evidence to reject H0β
c
...
Conclusion in context
π‘2
π 2 ( )under
βπ
H0:
Letβs say theβ‘π 2 in ππ is π‘ 2
...
1 Terminology of Bivariate Data
- Usually on scatter
- If both var are random and relationship linear, then association is βcorrelationβ
8
...
3 Measures of Correlation
Pearsonβs Product Moment Correlation Coefficient (pmcc)
ππ₯π¦
π=
βππ₯π₯ ππ¦π¦
2
π
π
2
2
Where ππ₯π₯ = βπ=1(π₯π β π₯) = βπ=1 π₯π β ππ₯ ;
2
ππ¦π¦ = βππ=1(π¦π β π¦)2 = βππ=1 π¦π2 β ππ¦ ;
ππ₯π¦ = βππ=1(π₯π β π₯)(π¦π β π¦) = βππ=1 π₯π π¦π β ππ₯π¦
...
When data cover whole population, population correlation coefficient denoted by π
2
...
r is only a sample from a parent bivariate distribution rather than whole population
4
...
3, s
...
n-2:
degrees of freedom denoted by π = π πππππβ‘π ππ§π β ππ
Title: OCR MEI B Mathematics Statistics
Description: OCR MEI B Mathematics Statistics
Description: OCR MEI B Mathematics Statistics