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Title: Laboratory Activity: COMBINED GAS LAWS
Description: This is my laboratory activity in chemistry for engineers subject. It is all about COMBINED GAS LAWS.
Description: This is my laboratory activity in chemistry for engineers subject. It is all about COMBINED GAS LAWS.
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COMBINED GAS LAWS
LABORATORY ACTIVITY #9
Solve: (SHOW YOUR SOLUTION)
1
...
00 ml at -23
...
0 torr
...
0˚C and 600
...
0 torr
V1 = 800
...
0˚C + 273˚ = 250˚K
P2 = 600
...
0 torr)(800
...
0 torr)(800
...
0 torr)
120,000,000 torr L ˚K
150,000˚K torr
800 ml
answer
2
...
0 L at 25˚C and 1
...
What temperature was it
initially, if it occupied 9
...
939 atm?
Solution:
P1V1
T1
P2V2
T2
Original Conditions
Final Conditions
P1 = 1
...
939 atm
V1 = 10
...
40 L
T2 = ?
(298˚K)
(1
...
0 L)
(0
...
40 L)(298˚K)
(10
...
00 atm)
2630
...
At what temperature will 0
...
30 liters at 1
...
95 atm) (12
...
654 moles)(0
...
n=?
P=2
...
00 cm3
T=750˚C
Solution:
n=
=
PV = nRT
(2,500
...
03 atm)
(0
...
Complete the table: (Show your solution)
P 1 V1
=
P 1 V2
n1 T1
n1
n2 T2
n2
T1
T2
P1
P2
V1
V2
1
...
3 moles
320˚K
430˚K
1
...
7 atm
4L
5L
2
...
7 moles
170˚K
270˚K
227 torr
210 torr
1
...
7L
2 moles
1
...
7L
2
...
5 atm)(4 L)
(1
...
7 atm) (V2)
(2
...
5 atm)(4 L) (2
...
7 atm) (1
...
5 L)
(2
...
7 L)
(2
...
3 moles)(170˚K) (210 torr)(3
...
5 L)(2
...
5 atm moles ˚K
=
(500 torr)(2
...
5L)
(1
...
5L) (1
...
7L)
950000 torr L moles ˚K
440640 ˚K torr L
2 moles
answer
Title: Laboratory Activity: COMBINED GAS LAWS
Description: This is my laboratory activity in chemistry for engineers subject. It is all about COMBINED GAS LAWS.
Description: This is my laboratory activity in chemistry for engineers subject. It is all about COMBINED GAS LAWS.