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Title: DIFFERENTIATION EXAM LECTURE NOTES 101
Description: differentiation lecture notes for engineering, yale university

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DIFFERENTION
Is the Process of finding derivative
Is used to determine the rate of change with respect to time
...

dy/dx = y2-y1/x2-x1 =gradient of the graph note that
dy/dx is the derivative of y with respect to x
DIFFERENTIATION FROM THE FIRST PRINCIPLE
Consider the function f(x) that depend on a variable x
F(x)=3x2

then f(x)=6x

DIFFERENTIAL TABLE
y

dy/dx

constant

0

Sin x

Cos x

Cos x

-sin x

ex

ex

ekx

K ekx

Tan x

Sec2x

In |x|

1/x

Sin ax

a cos ax

Cos ax

-a sinax

METHODS OF DIFFERENTIATION
1
...
Product rule
3
...

Y=f[g(x)]
Let u be g(x)
Example
Y=f(x)= (3 + x2)3
Solution: let u be ((3 + x2)3
Y=u3

dy/du=3u2

du/dx=2x dy/dx

= dy/du × du/dx
3u2 × 2x but u = 3 + x2
= 6x (3 + x2 )2

PRODUCT RULE

We consider finding derivative of f(x) that can be written as a product of two
functions
...

Let y be f(x) = u(x)/v(x)
=u/v
(u/v)’= u(1/v) ‘ + 1/v(u)’
= (vu’ – uv’)/v2

Example
Y= sin x/x Solution:
U=sin x

v= x

U’= cos x

v’= 1

(X (cos x ) – sin x)/x2

Example 2
Y= cos x/x2 Solution:
U= cos x
U’= -sin x

v = x2
v’= 2x

(Vu’ – uv’)/v2
(X2(-sin x) – cos x (2x))/x4
(-x2sin x – 2x(cos x))/x4
= [ sin x/x2 – 2 cos x/x3]

DIFFERENTIAL TABLE
y

dy/dx

constant

0

Sin x

Cos x

Cos x

-sin x

ex

ex

ekx

K ekx

Tan x

Sec2x

In |x|

1/x

Sin ax

a cos ax

Cos ax

-a sinax

METHODS OF DIFFERENTIATION
1
...
Product rule
3
...

Y=f[g(x)]
Let u be g(x)
Example
Y=f(x)= (3 + x2)3
Solution: let u be ((3 + x2)3
Y=u3

dy/du=3u2

du/dx=2x dy/dx

= dy/du × du/dx
3u2 × 2x but u = 3 + x2

= 6x (3 + x2 )2

PRODUCT RULE

We consider finding derivative of f(x) that can be written as a product of two
functions
...

Let y be f(x) = u(x)/v(x)
=u/v
(u/v)’= u(1/v) ‘ + 1/v(u)’
= (vu’ – uv’)/v2

Example

Y= sin x/x Solution:
U=sin x

v= x

U’= cos x

v’= 1

(X (cos x ) – sin x)/x2

Example 2
Y= cos x/x2 Solution:
U= cos x
U’= -sin x

v = x2
v’= 2x

(Vu’ – uv’)/v2
(X2(-sin x) – cos x (2x))/x4
(-x2sin x – 2x(cos x))/x4
= [ sin x/x2 – 2 cos x/x3]


Title: DIFFERENTIATION EXAM LECTURE NOTES 101
Description: differentiation lecture notes for engineering, yale university