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Title: Algebra _ Multiplication and Division of Rational Expressions
Description: Algebra _ Multiplication and Division of Rational Expressions Multiplying and Dividing Rational Expressions Multiplication of rational expressions works the same way as multiplication of any other fractions. We multi ply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.

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Algebra
Multiplication and Division of Rational Expressions

I
...


11
5mn2

15mn

x

44

Solution:
11
5mn2

2
...


2x + 2y
x
5

x

10
x+y

Solution:
2x + 2y
5

4
...
If P =

x2 + 3
x2 – 1

and Q =

x–1
, find PQ
...


x3 – 8
x2 – 4

x

=

x2 + 3
(x + 1)(x 1)

=

x2 + 3
(x + 1) (2x)

x

x–1
2x

x 2 + 6x + 8
x2 – 2x + 1

Solution:
x3 – 8
x2 – 4

2
x x 2 + 6x + 8
x – 2x + 1

=

=

7
...


x2 – y 2

x

x2 + 2xy + y2

xy + y2
x2  xy

Solution:
x2 – y 2
x2 + 2xy + y2

(x + y) ( x  y)

xy + y2

x

=

x2  xy

(x + y)2

9
...


x (x – y)

y
x

=

x4 – 8x

y (x + y)
x

12x + 7x –12 x
9x2 + 6x – 8

x
x

= 1
2

12x – 13x – 4
12x2 – 25x + 12

Solution:
6x2 – x – 2

= 6x2 – 4x + 3x – 2
= 2x (3x  2) + 1 (3x – 2)

8x2 + 6x + 1

= 8x2 + 4x + 2x + 1
= 4x (2x + 1) + 1 (2x + 1)

12x2 – 7x – 12

= (3x + 4) (4x 3)

= 9x2 + 12x – 16x – 8
= 3x (3x + 4) 2 (3x + 4)

12x2 – 13x – 4

= (2x + 1) (4x + 1)

= 12x2 + 16x 9x –12
= 4x (3x + 4) 3 (3x + 4)

9x2 + 6x  8

= (3x – 2) (2x + 1)

= 12x2 – 16x+ 3x – 4

= (3x + 4) (3x 2)

= 4x (3x 4) + 1 (3x 4)
12x2 – 25x + 12

= (3x  4) (4x+ 1)

= 12x2 – 16x – 9x + 12
= (3x 4) (4x )

= 4x (3x  4) 3 (3x  4)
6x2 – x – 2

12x 2+ 7x – 12
x

8x2 + 6x + 1

9x2 + 6x – 8

12x 2 – 13x – 4
x

12x2 – 25x + 12

(3x – 2) (2x + 1) (3x + 4) (4x3) (3x  4) (4x+ 1)



(2x + 1) (4x + 1) (3x + 4) (3x 2) (3x  4) (4x)

= 1

II
...


Solution:



25x2
36y2

14x2
9y2

x

36y2
25x2

56
= 25

75m2
25mn

2
14n
49

2
...


t–2
4s

Solution:



49
25mn

=

21m
2n3

t2 – t – 6
12s2
t–2
4s

x

12 s2
=
t2 – t – 6

=

(t – 2)
12s2
x
4s
(t – 3) (t + 2)
3s (t – 2)
(t – 3) (t + 2)

4
...


x2 – 2xy + y2
x2 – xy



x2 – 5x + 6
x2 – x – 2

=

x+y
(x + y) (x – y)

x

(x– y)2
x (x – y)

1
x

x2 – 6x + 9
x2 – 4x + 4

Solution:

x2 – 6x + 9
x2 – 4x + 4

6
...
If P =

x2 – 36
x2 – 49

and Q =

Solution:

P
Q

x+6
find the value of
x+7
x2 – 36
x2 – 49

=

=

8
...


x+7
x+6

(x – 6) (x + 6)
(x + 7)
x
(x  7) (x + 7)
(x + 6)

x–6
x–7

=

x2 – 5x + 6
x2 – 3x + 2
and B = 2
find the value of A  B
...


2 x2 + 5x – 3
2 x2 + 7x + 6

(x  4) (x  5) (x  1) (x  2)

=

x3
x5

2x2 + 5x – 3
2x2 – x – 6



2
Solution: 2 x2 + 5x 3
2 x + 7x + 6

x

2x2  x – 6
2x2 + 5x – 3

2 x2 + 5x 3

-----(1)

= 2x2 + 6x  x – 3
= 2x (x + 3) –1 (x + 3) = (x + 3) (2x – 1)

2 x2 + 7x + 6

= 2x2 + 4x + 3x + 6
= 2x (x + 2) + 3 (x + 2) = (x + 2) (2x + 3)

2x2  x – 6

= 2x2  4x + 3x  6
= 2x (x 2) + 3 (x2) = (x  2) (2x + 3)

2

2x + 5x – 3

= 2x2 + 6x – x – 3
= 2x (x + 3) –1 ( x + 3) = (x+ 3) (2x – 1)

(1) 

(x+ 3) (2x – 1)
(x – 2) (2x + 3)
x–2
x
=
(x+ 2) (2x + 3)
(x+ 3) (2x – 1)
x+2

10
...
(1)

= 2x2 + 8x x – 4
= 2x (x + 4) – 1 (x + 4) = (x + 4) (2x – 1)

3x2  13x + 4

= 3x2  12x x + 4
= 3x (x – 4) –1 (x 4) = (x – 4) (3x – 1)

6x2 + x– 1

=

6x2 + 3x2x 

= 3x (2x + 1) –1 (2x + 1) = (2x + 1)(3x – 1)
4x2 – 1
(1)



= (2x + 1) (2x – 1)
(x + 4)(2x – 1)
(2x + 1)(3x – 1)
x
=
(x – 4)(3x – 1)
(2x + 1)(2x – 1)

x+4
x4


Title: Algebra _ Multiplication and Division of Rational Expressions
Description: Algebra _ Multiplication and Division of Rational Expressions Multiplying and Dividing Rational Expressions Multiplication of rational expressions works the same way as multiplication of any other fractions. We multi ply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.