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Title: Algebra _ Relation between roots and coefficients
Description: Algebra _ Relation between roots and coefficients Solution: Let α and β be the roots of the given equation. Sometimes the relation between roots of a quadratic equation is given and we are asked to find the condition i.e., relation between the coefficients a, b and c of quadratic equation. This is easily done using the formula α + β = -ba and αβ = ca.

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Algebra
Relation between roots and coefficients
1
...


Form the equation whose roots are
(a)

3, 4

Solution:
The roots are 3 and 4
Sum of the roots

= 7

Product of the roots

= 12

 The required equation isx2 – 7x + 12
(b)

= 0

3 + –7 , 3 – –7

Solution:

The roots are 3 +– 7 and 3 – – 7
Sum of the roots
Product of the roots

= 6

= 9–7 = 2

The required equation is x2 – 6x + 2 = 0
(c)

4 + –2 ,
2

4 – –2
2

Solution:
The roots are 4 + –2
2

and

Sum of the roots

=

Product of the roots

=

4 – –2
2

4 + –2
4 – –2
+
2
2

4 +–2
2

The required equation is x2 – 4x + 7 = 0
2



2x2 – 8x + 7 = 0

4 ––2
2

8
2

=

=

= 4

7
16 – 2
=
2
4

3
...


Solution:
+

2 + 2

6
3

= 

=

= 2

4
3

= ( + )2  2  
4
3

= (2)2 – 2

4
...



+ =

Solution:




+



=
=

5
2
12
2

= 6

2 + 2


5
2


= 4  8 =
3









=

2

+ 2 (6)

=
 6

=

73
24

( + )2 – 2 


25
+ 12
4
=
6

5
...

Find the quadratic equation
...


= 16



= 8

The equation is x2 8x + 0
x2  8x

= 0
= 0

Hence  = 0

 = 0

Form the equation one of whose roots is – 5 and sum of the roots is –2
...


If  and  are the roots of the equation x2 – 3x – 4 = 0 form the equation
whose roots are

1
1
2 , 2



(b)

x2 – 3x – 4

= 0

(a)

Solution:

+


(a)

Sum =

 
,

...




x



4

x+1 = 0

4x2 + 17x + 4

= 0

If  and  are the roots of the equation x2 x =  15 form the equation whose
roots are ( + ) and 3  
...


= 0

If  and  are the roots of the equation x2 2x + 7 = 0 form the equation whose
roots are 2 ,  2
...
 2

= 3 3
= ( )3 = (7)3
= 343

The equation is x2 – 14x + 343

= 0

10
...

Solution:

Let the roots be  and 2
 + 2

=

a
a
a
 3 = 2   = 6
2

Also 
...


= 4 x 6 =  24

If one root of the equation 3x2 + kx – 81 = 0 is the square of the other, find k
...
2

k


3
s
 81
=
3 =  27

3

=  27

 + 2




= 0
= 

Substitute in (1)
3+9

=

k
3

6

=

k
3





 = 3

 k = 18





12
...

Solution:

Adding

p
5

+

=



= 

2

=

p
+ 1
5



=

p+5
10

&  =

  = p + 5 1 =
10
Hence

p+5
10

 =

p2  25
100

=

p2 – 25
p2
p

1
5

= 20
= 45
=  3 5

=

p–5
10
p–5
10

=

1
5

1
5


Title: Algebra _ Relation between roots and coefficients
Description: Algebra _ Relation between roots and coefficients Solution: Let α and β be the roots of the given equation. Sometimes the relation between roots of a quadratic equation is given and we are asked to find the condition i.e., relation between the coefficients a, b and c of quadratic equation. This is easily done using the formula α + β = -ba and αβ = ca.