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Title: Math Formulas
Description: exam questions with complete answer and explanation
Description: exam questions with complete answer and explanation
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ALGEBRA 1
Composition Analysis: Ax + By = Cz
WORK PROBLEMS
LOGARITHM
x = logb N → N =bx
Properties
log(xy) = log x + log
x
y
y log
Rate of doing work = 1/ time
Rate x time = 1 (for a complete job)
Combined rate = sum of individual
rates Man-hours (is always assumed
constant)
(Wor ker s1)(time1) (Wor ker s2 )(time2 )
=
quantity
...
work1
quantity
...
work2
= log x − log y
ALGEBRA 2
log xn = nlog x
logb x =
UNIFORM MOTION PROBLEMS
log
x logb
S =Vt
loga a =1
REMAINDER AND FACTOR THEOREMS
Traveling with the wind or downstream:
Given:
Vtotal = V1 +V2
f (x)
(x − r)
Traveling against the wind or upstream:
Vtotal = V1 −V2
Remainder Theorem: Remainder = f(r)
Factor Theorem: Remainder = zero
QUADRATIC EQUATIONS
Ax2 + Bx +C = 0
− B ± B 2 − 4AC
Root = 2A
Sum of the roots = - B/A
Products of roots = C/A
MIXTURE PROBLEMS
Quantity Analysis: A + B = C
DIGIT AND NUMBER PROBLEMS
100h +10t +u →
where:
2-digit number
h = hundred’s digit
t = ten’s
digit u =
unit’s digit
CLOCK PROBLEMS
an = a m r n−m
where:
x = distance traveled by the
minute hand in minutes x/12 = distance
traveled by the hour
hand in
minutes
PROGRESSION PROBLEMS
nth term
r=
a 2 a3
=
a1 a2
S=
a ( r n −1)
1
→ r >1
r −1
Sum of ALL
terms, r >1
a1 (1 −r n )
S=
→ r <1
1 −r
Sum of ALL
terms, r < 1
S=
a1 = first term an = nth term
a1
1 −r
ratio
→ r <1 & n = ∞
Sum of ALL
terms,
r<1,n=∞
am = any term before an d =
common difference
= sum of all “n” terms
S
HARMONIC PROGRESSION (HP)
-
ARITHMETIC PROGRESSION (AP)
difference of any 2 no
...
COIN PROBLEMS
d = a − a = a − a ,
...
ALGEBRA 3
Fundamental Principle:
“If one event can occur in m different ways, and
after it has occurred in any one of these ways, a
second event can occur in n different ways, and
then the number of ways the two events can occur
in succession is mn different ways”
PERMUTATION
Properties of a binomial expansion: (x +
y)n
Permutation of n objects taken r at a time nPr
1
...
The powers of x decreases by 1 in the
successive terms while the powers of y
increases by 1 in the successive terms
...
The sum of the powers in each term is always
equal to “n”
= n!
4
...
objects
are alike
P=
is equal to “n+1”
of the terms having a coefficient of 1
...
Permutation of n objects arrange in a circle
P = (n−1)!
r th term = nCr-1 (x)n-r+1 (y)r-1
term involving yr in the expansion (x +
y)n
COMBINATION
y r term = nCr (x)n-r (y)r
Combination of n objects taken r at a time
sum of coefficients of (x + y)n
nCr =
Sum = (coeff
...
of y) n
−nr!)!r!
sum of coefficients of (x + k)n
Sum = (coeff
...
The sets are drawn as
circles
...
PLANE
TRIGONOMETRY
FULL OR PERIGON
Measurement
θ = 0°
0° < θ < 90°
θ = 90°
90° < θ < 180°
θ =180°
180° < θ < 360°
θ = 360°
Pentagram – golden triangle (isosceles)
36 °
72° 72 °
TRIGONOMETRIC IDENTITIES
sin 2 A+ cos2 A = 1 1+
a
= =
cot2 A = csc2 A
1+ tan2 A = sec 2 A sin(A± B) = sin
AcosB ± cos Asin B cos(A± B) =
COSINE LAW
cosAcosB sin Asin B tan(A± B) =
tan A± tanB
1tan
b
c
sin A
sinB
sinC
a2 = b2 + c2 – 2 b c cos A b2 = a2 + c2
– 2 a c cos B c2 = a2 + b2 – 2 a b cos
AtanB
cot(A± B) =
C
cot AcotB 1 cot A± cotB
sin 2A = 2sin AcosB cos2A
= cos2 A−sin 2 A
AREAS OF TRIANGLES AND
QUADRILATERALS
tan2A =
TRIANGLES
2tan
2
A 1− tan A
cot2 A−1
1
...
Given two sides and included angle
Area = absinq
3
...
Quadrilateral circumscribing in a circle
Area = s(s − a)(s −b)(s − c)
Area = rs
Area = abcd
s=a+b+c
2
4
...
Triangle circumscribing a circle
Area=rs
6
...
Given diagonals and included angle
1
Area =
d1d2 sinq
2
2
...
Cyclic quadrilateral – is a quadrilateral inscribed in a
circle
Area = (s − a)(s −b)(s −c)(s − d)
s = a +b + c + d
2
(ab +cd)(ac +bd)(ad +bc)
r=
4(Area)
d1d 2= ac+bd →Ptolemy’s Theorem
q = (n − 2)(180°)
SIMILAR TRIANGLES
A1
C
A
2
2
B
n
2
2
H
Value of each exterior angle
A2
a
b
c
h
SOLID GEOMETRY
a =180°−q =
360°
n
Sum of exterior angles:
POLYGONS
3 sides – Triangle
4 sides –
Quadrilateral/Tetragon/Quadrangle
5 sides – Pentagon
6 sides – Hexagon
7 sides – Heptagon/Septagon
8 sides – Octagon
9 sides – Nonagon/Enneagon
10 sides – Decagon
11 sides – Undecagon
12 sides – Dodecagon
15 sides – Quidecagon/ Pentadecagon
16 sides – Hexadecagon
20 sides – Icosagon
1000 sides – Chillagon
Let: n = number of sides
θ = interior angle
α = exterior angle
Sum of interior angles:
S = n α = 360°
Number of diagonal lines (N):
N=
n
(n − 3)
2
Area of a regular polygon inscribed in a circle of
radius r
Area = 1 nr2 sin
360
2
n
Area of a regular polygon circumscribing a
circle of radius r
Area = nr2 tan
n
S = n θ = (n – 2) 180°
Value of each interior angle
180
Area of a regular polygon having each side
measuring x unit length
Area = 1 nx2 cot
180
4
1
A=
n
d1d2sinq
2
PLANE GEOMETRIC FIGURES
RHOMBUS
CIRCLES
pd 2 2 A =
=pr
1
A=
4
d1d2 = ah
2
Circumference =pd = 2pr
A = a2 sina
Sector of a Circle
SOLIDS WITH PLANE SURFACE
A = rs = r2q
Lateral Area = (No
...
The bounding
planes are referred to as the faces and the intersections of
the faces are called the edges
...
PRISM
V = Bh
A(lateral) = PL
A(surface) = A(lateral) + 2B
where: P = perimeter of the base L
= slant height
B = base area
Truncated Prism
V=B
number∑heightsof heights
PYRAMID
V
Bh
A(lateral) = ∑ Afaces
A(surface) =A(lateral) +B
Frustum of a Pyramid
V=
h
(A1 + A2 + A1A2 )
3
A1 = area of the lower base
A2 = area of the upper base
PRISMATOID
h
V = 6(A1 + A2 +4Am)
Where: x = length of one edge
Am = area of the middle section
SOLIDS WITH CURVED SURFACES
REGULAR POLYHEDRON
CYLINDER
a solid bounded by planes whose faces are congruent
regular polygons
...
B
...
D
...
Tetrahedron
Hexahedron (Cube)
Octahedron
Dodecahedron
Icosahedron
A(lateral) = PkL = 2 π r h
A(surface) = A(lateral) + 2B
Pk = perimeter of right section
K = area of the right section
B = base area
L= slant height
CONE
V
=Bh
A(lateral) =prL
V = 3 (3r − h)
FRUSTUM OF A CONE
V = h (A1 + A2 + A1 A2
3
p
V=
+h2 )
2
+3b2 + h2 )
(3a
p
h
V=
(3a
6
SPHERE
=pr3
V
2
6
A(lateral) =p(R + r)L
SPHERES AND ITS FAMILIES
h
SPHERICAL WEDGE
is that portion of a sphere bounded by a lune and the planes
of the half circles of the lune
...
2
A
V
=
V = 1 A(zone)r
3
° 90
SPHERICAL ZONE
is that portion of a spherical surface between two
parallel planes
...
A(surface) = A(zone) + A(lateralofcone)
SPHERICAL PYRAMID
is that portion of a sphere bounded by a spherical
3
polygon and the planes of its sides
...
ph 2
E = [(n-2)180°]
E = Sum of the angles E =
Spherical excess
n = Number of sides of the given spherical polygon
SOLIDS BY REVOLUTIONS
V12
AA12
2
3
V
TORUS (DOUGHNUT)
a solid formed by rotating a circle about an axis not
passing the circle
...
It is a special ellipsoid with
d = (x2 − x1)2 + (y2 − y1)2
c=a
V = pa2b
Slope of a line
PROLATE SPHEROID
m = tanq = yx22 −− xy11
a solid formed by rotating an ellipse about its major axis
...
x = x1rr12 ++rx2 r1
y=
y1rr12 ++ry22r1
V = pr2h
2
SIMILAR SOLIDS
V1
V2
A2
3
H
h
A1
r
H
h
Location of a midpoint
R
3
L
l
2
R
r
x1 +2 x2
3
l
2
L
2
x=
STRAIGHT LINES
y = y1 +
2
y2
d = Ax1 + By2 +1 B+2C
General Equation Ax + By + C
=0
±A
Point-slope form
Note: The denominator is given the sign of B
y – y1 = m(x – x1)
Two-point form
y − y1 = yx22 −−
Distance between two parallel lines d =
C1 −C2
xy11 (x − x1)
A2 + B2
Slope relations between parallel lines: m1 =
m2
Slope and y-intercept form
y = mx + b
Intercept form
x
Slope relations between perpendicular lines:
m1m2 = –1
y
+
a
=1
b
Slope of the line, Ax + By + C = 0 m
=−
Line 1 → Ax + By + C1 = 0 Line
2 → Ax + By + C2 = 0
Line 1 → Ax + By + C1 = 0
Line 2 → Bx – Ay + C2 = 0
PLANE AREAS BY COORDINATES
= 1 x1,x2,x3,
...
yn, y1
Angle between two lines
−1
m−1mm12
tan
1m+2
q=
Note: Angle θ is measured in a counterclockwise
direction
...
Distance of point (x1,y1) from the line
Ax + By + C = 0;
Note: The points must be arranged in a counter clockwise
order
Title: Math Formulas
Description: exam questions with complete answer and explanation
Description: exam questions with complete answer and explanation