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Title: complete the table of elastic and inelastic collision
Description: exam questions with complete answer and explanation

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Answer
m1

m2

v2

Ptotal

1
...
20kg 1
...
80m/s

-0
...
8m/s

1
...
40kg 4
...
30m/s

0

3
...
8665 m/s

2
...
90kg

v1

3
...
850m/s 11
...
00kg 5
...
60m/s

Explanation
A
...
2*1
...
2*-1
...
8 - 2
...
36 kg m/s
B
...
36= (1
...
8)+(1
...
36 = -2
...
2 v'2
v'2= 1
...
2
v'2 = 1
...
90m/s

9
...
433

v'2

0
...
74
-1
...
11 m/s

C
...
4*1
...
8*0)
= 3
...
Ptotal = m1v'1 + m2v'2
3
...
4*-0
...
8*v'2)
3
...
0392 + 4
...
12+1
...
8
v'2 = 0
...
Ptotal = m1v1 + m2v2
11
...
5*v1)+(3
...
850)
11
...
315 = 2
...
185/2
...
274 m/s
F
...
5 = (2
...
9*2
...
5-10
...
5v'1
v'1 = 0
...
Ptotal = m1v1 + m2v2
= (1*4
...
1*0
...
6+4
...
19 kg m/s
H
...
19 = (1*-1
...
1*v'2)
9
...
59=5
...
78/5
...
11 m/s
5
...
It means that no energy is
transferred into other form such as heat


Title: complete the table of elastic and inelastic collision
Description: exam questions with complete answer and explanation