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Title: LESSON NOTES ON EXPONENTS
Description: The lesson notes contain solved questions on exponents for 1st year beginner.

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Mathematics (Algebra): Solved Questions on Exponents
Law of Exponents
(1) am ร— an= am+n
(2) am รท an = am--n
(3) (am)n= amn
(4) (a1/n) n = a1/n ร—n = a
๐‘Ž

๐‘›

๐‘Ž

(5) ( )m/n = ( โˆš )m
๐‘

๐‘

(6) a0 =1
(7)

1
๐‘Ž

= aโ€”1

๐‘Ž

๐‘

๐‘

๐‘Ž

(8) ( )โ€”1 = ( )

Exercises
(1) 323/5
5

( โˆš32)3
23 = 8

(2)

2x = 0
...
5 = 2515/10 = 253/2
( 2โˆš25) 3 =
53 = 5x5x5=125

5
40

=

1
8

= 2--3

(4) 4/2x = 64x
22/2x = 28x
22-x =28x
2-x=8x
2= 8x+x
2= 9x
9x =2
๐Ÿ

X=

๐Ÿ—

(5) 10X =

1
0
...
125)2/3 =(โˆ’
125 2
)
1000

3

(โˆšโˆ’
5

1

10

2

(-- )2 = (-- )2
1

1

2

2

=-- X-=

๐Ÿ
๐Ÿ’

(7) (0
...

32x= y2

y2 โ€“9=0
(y+3) (yโ€”3) =0
Y+3=0 or yโ€”3=0
Y=--3 or y=3
Y=--3, 3x=--3(no solution)
When y=3, then 3x=31
X=1

(10) 42xโ€”21x4x+80=0
Let 4x be y, then y2 โ€“21y+80=0
By factorization, (yโ€”16)(yโ€”5)=0
Y=16 0r y=5
When y=16, then 4x=16
4x=42
X=4
When y=5, 4x=5
Take the log of both sides, xlog4= log5
X=

๐‘™๐‘œ๐‘”5
๐‘™๐‘œ๐‘”4

Log5โ€”log4
= 0
...
6021
= 0
...
250
So, x= 2 and x= 1
...

32

5

(โˆšโˆ’

243 3
)
32

3

3

3

2

2

2

(โˆ’ )3 = -- ๐‘ฅ --

(11) 4โ€”4x =

๐‘ฅโˆ’

3
2

= -- -

๐Ÿ๐Ÿ•
๐Ÿ–

= -- 3-

๐Ÿ‘
๐Ÿ–

1

256

4โ€”4x =256โ€”1
--4x=--4
X=

โˆ’4
โˆ’4

X= 1

1

(12) 16(4)2x = ( )x
2

24 x 2(2)2x = 2โ€”x
24+4x =2โ€”x
4+4x= --x
4x+x=--4
5x=--4
X=-- -

๐Ÿ’
๐Ÿ“

1

(13) ( )(2-y) = 1
4

4โ€”1(2--y) = 1
4โ€”2+y = 1
4yโ€”2= 40

4โ€”4x =4โ€”4

yโ€”2=0
y=2

(14) 21/2 x 81/2/4
21/2 x (23)1/2/22
21/2+3/2โ€”2/1
21+3โ€”2/2
24-2/2
22/2
21
=2

(15) 3(1โ€”n)/9โ€”2n=1/9
3(1โ€”n)/32(--2n) = 1/32
3(1--n)/3โ€”4n =1/32
31โ€”n-- --- 4n =3โ€”2
31โ€”n+4n =3โ€”2
31+3n = 3โ€”2
1+3n= --2
3n = --2โ€”1
3n= --3
n = --1


Title: LESSON NOTES ON EXPONENTS
Description: The lesson notes contain solved questions on exponents for 1st year beginner.