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Title: LESSON NOTES ON EXPONENTS
Description: The lesson notes contain solved questions on exponents for 1st year beginner.
Description: The lesson notes contain solved questions on exponents for 1st year beginner.
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Mathematics (Algebra): Solved Questions on Exponents
Law of Exponents
(1) am ร an= am+n
(2) am รท an = am--n
(3) (am)n= amn
(4) (a1/n) n = a1/n รn = a
๐
๐
๐
(5) ( )m/n = ( โ )m
๐
๐
(6) a0 =1
(7)
1
๐
= aโ1
๐
๐
๐
๐
(8) ( )โ1 = ( )
Exercises
(1) 323/5
5
( โ32)3
23 = 8
(2)
2x = 0
...
5 = 2515/10 = 253/2
( 2โ25) 3 =
53 = 5x5x5=125
5
40
=
1
8
= 2--3
(4) 4/2x = 64x
22/2x = 28x
22-x =28x
2-x=8x
2= 8x+x
2= 9x
9x =2
๐
X=
๐
(5) 10X =
1
0
...
125)2/3 =(โ
125 2
)
1000
3
(โโ
5
1
10
2
(-- )2 = (-- )2
1
1
2
2
=-- X-=
๐
๐
(7) (0
...
32x= y2
y2 โ9=0
(y+3) (yโ3) =0
Y+3=0 or yโ3=0
Y=--3 or y=3
Y=--3, 3x=--3(no solution)
When y=3, then 3x=31
X=1
(10) 42xโ21x4x+80=0
Let 4x be y, then y2 โ21y+80=0
By factorization, (yโ16)(yโ5)=0
Y=16 0r y=5
When y=16, then 4x=16
4x=42
X=4
When y=5, 4x=5
Take the log of both sides, xlog4= log5
X=
๐๐๐5
๐๐๐4
Log5โlog4
= 0
...
6021
= 0
...
250
So, x= 2 and x= 1
...
32
5
(โโ
243 3
)
32
3
3
3
2
2
2
(โ )3 = -- ๐ฅ --
(11) 4โ4x =
๐ฅโ
3
2
= -- -
๐๐
๐
= -- 3-
๐
๐
1
256
4โ4x =256โ1
--4x=--4
X=
โ4
โ4
X= 1
1
(12) 16(4)2x = ( )x
2
24 x 2(2)2x = 2โx
24+4x =2โx
4+4x= --x
4x+x=--4
5x=--4
X=-- -
๐
๐
1
(13) ( )(2-y) = 1
4
4โ1(2--y) = 1
4โ2+y = 1
4yโ2= 40
4โ4x =4โ4
yโ2=0
y=2
(14) 21/2 x 81/2/4
21/2 x (23)1/2/22
21/2+3/2โ2/1
21+3โ2/2
24-2/2
22/2
21
=2
(15) 3(1โn)/9โ2n=1/9
3(1โn)/32(--2n) = 1/32
3(1--n)/3โ4n =1/32
31โn-- --- 4n =3โ2
31โn+4n =3โ2
31+3n = 3โ2
1+3n= --2
3n = --2โ1
3n= --3
n = --1
Title: LESSON NOTES ON EXPONENTS
Description: The lesson notes contain solved questions on exponents for 1st year beginner.
Description: The lesson notes contain solved questions on exponents for 1st year beginner.