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Chapter 3
If-Else, While loop & Lots of Patterns
In this we will learn the syntax of conditional statements in CPP
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We will also be given a number "A"
and asked to print positive if "A" is positive, otherwise print not
positive
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For instance, if "A" is 5, then if "A" is -2 and if "A" is -5, then it
will print anything
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But if we add an "else"
block here, then this block will be executed
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get()" takes input in the form of characters and that it took "1" as a
character, but we are assigning this value to an integer so that's why it
printed its ASCII value
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Let's code to determine
which number is greater
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However, this information is not relevant to the
topic at hand
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We will use a
variable i to keep track of the row number, and then we will simply
print a star in each column
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In the next
video, we will do more pattern problems and also code a triangular
figure
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Data types are also used to test data
types and identify types of data types, such as C, D, E, dtype, and etype
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We will run a loop from 1 to n , ( for all rows ) We declared a variable i
to keep the track of the row number and then we are simply printing
star in each column Then we wrote this cout < endl , to come to a new
line , and after that this code will get executed for every row
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We will code this
triangular figure also in next video
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We will run a loop from 1 to n , ( for all rows ) Then we declared a
variable J for columns
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Then we incremented J inside the column loop
and Incrementing i inside the row loop after printing ENTER
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Also we can notice that number of stars in a
particular row is equal to the row number which is 'i' Now let 's take a
variable count=1 and we will print this count and then increment it
outside this loop
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Then after printing it inside col loop , we will keep on
incrementing it by 1 There is an another method for this question But
first let 's write the code for this one We can't simply print row and
increment it , because then our program will misbehave
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We have done 9 pattern questions
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Next pattern looks like this 1st obs row = n 2nd obs- A is mapped to 1 , B is mapping to 2 and so on
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We got our counting correct but just had to map 1 to ' A ' so to do so ,
we added ' A -1 on both sides , so to
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We just have to print ' A'+i 1 , but it will be typecasted to integer so to avoid that
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Bhaiya: We have to find a
relation for printing our answer
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We can see their dependence on
row number and col number
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Also 'A ' will be there for sure
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So this is our formula
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We just have to find the starting character
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Do
this one Now let 's try out this variant
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These are very easy questions if you have
understood previous questions
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If you are
able to do this one without my help, then it is very good for you
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I will tell it 's
solution and then give you one more question to try as your homework
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In next one , we will see operators , bitwise
operators , For loop , and many more interesting things