Search for notes by fellow students, in your own course and all over the country.
Browse our notes for titles which look like what you need, you can preview any of the notes via a sample of the contents. After you're happy these are the notes you're after simply pop them into your shopping cart.
Title: Physics Sample Activity with Answer
Description: This file contains sample activity with answers about error analysis in physics. This note is very useful for Physics students and Science Students.
Description: This file contains sample activity with answers about error analysis in physics. This note is very useful for Physics students and Science Students.
Document Preview
Extracts from the notes are below, to see the PDF you'll receive please use the links above
Name: Magsalay, Rechie Sumbrana
Course: BS Physics
Student ID: 2018-03471
College: CSM
Subject: Advanced Laboratory
Schedule: TWF (10:00AM-1:00PM)
ACTIVITY 1
ERROR ANALYSIS
1
...
Which of these
uncertainties, if any, are not valid? Why?
a
...
3 ± 0
...
25
...
02 m c
...
36 ± 124 s
Answer:
The uncertainties that are not valid above are: a
...
3 ± 0
...
0
...
(a) Accordingly, the last significant figure of any value is the same to the decimal
position of the uncertainty such that the letter a should be 1
...
0004 N
...
2
...
0 ± 0
...
0 ± 0
...
Combined, they have a mass of _________±_________g
...
0 ± 0
...
0 ± 0
...
)
(b
...
0 + 75
...
05 + 0
...
1
Therefore, the combined mass of the two masses is
m1 + m2 = 125
...
1 grams
3
...
61 ± 0
...
The time that it
takes to travel this distance is 3
...
05 seconds
...
Given:
d = 5
...
005 m
t = 3
...
05 s
Unknown:
v=d/t
v=?
Solution:
(a
...
61/3
...
75
(b
...
005
0
...
75) = 0
...
61
3
...
75 ± 0
...
Type equation here
...
The coefficient of friction (mu) can be calculated from the following equation (mu) =
tan (phi)
...
0 ± 0
...
Given:
(phi) = 32
...
5 degrees
(mu) = tan (phi)
Unknown:
(mu) = ?
Solution:
(a
...
625
(b
...
5°) = 0
...
625 ± 0
...
Type equation here
...
Suppose you recorded the following 10 measurements of time
...
Trial #
1
2
3
4
5
6
7
8
9
10
Time (s)
8
...
36
8
...
91
8
...
48
8
...
64
8
...
49
Unknown:
Average time (X*) = ?
Solution:
(a
...
52 + 8
...
74 + 8
...
60 + 8
...
55 + 8
...
33 + 8
...
56 s
10
(b ) For uncertainty,
max
...
(t)
8
...
33
(delta) (X*) = ---------------------- = ------------------- = 0
...
3
2
2
Therefore, the average time is
X* = 8
...
3 s
...
(a) Construct a velocity vs
...
Remember to include a title, axis labels with units, and a trend line with the
equation displayed
...
0
3
...
5
3
...
4
5
...
Acceleration =_________________m/s2
...
Then use these to calculate
the uncertainty in the acceleration
...
(a
...
6357x + 0
...
744
4
3
Velocity
2
Linear (Velocity)
1
0
0
2
4
6
8
Time (s)
(b
...
6357x + 0
...
6357
...
6357 m/s² = 0
...
Minimum slope : Since, the lowest steep is at point (5,2
...
4)
Therefore, the slope is m=(2
...
48
...
5
...
– min
...
5-0
...
51=0
...
Therefore, the acceleration uncertainty is 0
...
(c
Title: Physics Sample Activity with Answer
Description: This file contains sample activity with answers about error analysis in physics. This note is very useful for Physics students and Science Students.
Description: This file contains sample activity with answers about error analysis in physics. This note is very useful for Physics students and Science Students.