Notesale: Turn your study into money

Document Preview

Extracts from the notes are below, to see the PDF you'll receive please use the links above

---

04 - 18 - 23

ALGEBRA:
Subtraction
of
Algebraic
Expressions (Sample Problems & Solutions) Part 004
1
...

4
2
3
7
2
5
− � − �2 − − �2 + � + 1
2
4
3

Applying distributive property, we have,

�
�
5
− � − �2 − − �� + � + �
�
4
�
5
7
2
− � − �2 + �2 − � − 1
4
2
3

Then, simplifying further, we have,

5
�
2
− � − �� + �� − � − 1
�
4
3
� � 5
2
−� + � − � − � − 1
�
4
3
−� + � � 5
2
� − �− �−1
�
4
3
� � 5
2
� − �− �−1
�
4
3

5 2 �
�
� − �− �−1
2
�
�
5 2
� �
� + − − �−1
2
� �
5 2
−�� − �
� +
�−1
2
��
5 2
−��
� +
�−1
2
��
Therefore, simplifying further the problem, the result is
��
��

� − �
...
What is the difference of the following:
4 2�2 − 1 − � + 2�2
...


3
...
6� + 7
...
1� + 4
...
2
...
6� + 7
...
1� + 4
...
2

Applying the distributive property, we have,

−0
...
2�2 − 1 − �
...
6� + 7
...
�

Simplifying further, we have,

−0
...
��� − 1 − 3
...
��� − 0
...
��� − 0
...
1� − 0
...
0�2 − �
...
�� − 0
...
0�2 − �
...
2
3
...
7� − � − �
...
0�2 − 3
...
�

Therefore, the difference is �
...
Simplify the following: − 3�4 − 8� +
2
3

�
...

�

1

3

5
...


x2 −

Solution:

− 4x2 −

1
3
− 8x2 + x − x2 − 1 − 7x − 1
4
4

First, simplify the expressions inside the bracket and
parenthesis,
1
3
− 8x2 + x − �� − � − �� − �
4
4
1
3
− 4x2 − − 8x2 + x − �� − � + �� − �
4
4

− 4x2 −

Applying the distributive property, we have,

�
�
− ��� + � − �� − � + 7x − 1
�
�
�
�
−��� + − ��� − � − �� + � + 7x − 1
�
�

− ��� −

Then, simplifying further, we have,

1
3
−��� + − ��� − x − �� + 1 + 7x − 1
4
4

−���� +

1 3
− x + 1 + 7x − 1
4 4

1 �
−13x2 + − � + 1 + �� − 1
4 �
�
1
−13x2 + − + � � + + 1 − 1
�
4
−�
+
��
1
−13x2 +
�+ +1−1
�
4
��
1
−13x2 +
�+ +1−1
�
4
25
�
x+ +�−�
4
�
25
�
−13x2 + x +
4
�

−13x2 +

Therefore, the result on simplifying the problem is −���� +

��
�

�

�+

---