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Solution Exercice 1
Pour calculer le courant qui circule dans R3, on calcule la tension aux bornes de R3
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Eth = UAB = E x R3 / ( R1 + R2 + R3) = 18 x 100 / (100 + 100 + 100) = 6V
Rth = RAB = R5 + R3 // (R2 + R1) = 100k + 100k x 200k / 300k = 166,67k
2
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I = Eth / (Rth + R) = 18,95μA
b
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on calcule Eth = UAB
R6 = R2 + R3 // R4 = 50k +100k //100k = 100k
Eth = UAB = E x (R5 // R6) / [R1 + (R5 // R6)] = 15V x 50k / 100k = 7,5V
2
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on calcule Eth = UAB et Rth = RAB
Eth = UAB = UA - UB
UA = E x R2 / (R1 +R2) = 10V x 100 / 200 = 5V
UB = E x R5 / ( R3 + R4 + R5)
UB = 10V x 25 / 100 = 2,5V
Eth = UAB = UA - UB = 5V – 2,5V = 2,5V
Rth = RAB = (R1 // R2) + [R5 // (R3+R4)] = 100k // 100k + 25k // 75k = 50k + 18,75k = 68,75k
2
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on calcule Eth = UAB et Rth = RAB
Eth = UAB = UA - UB
UA = E1 x R2 / (R1 +R2) = 12V x 100 / 200 = 6V
UB = E2 x R4 / (R3 + R4) = 5V x 100 / 200 = 2,5V
Eth = UAB = UA - UB = 6V – 2,5V = 3,5V
Rth = RAB = (R1 //R2) + (R3 // R4) = 100k // 100k +100k // 100k = 100k
2
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on calcule Eth = UAB
On utilise la transformation triangle-étoile
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on calcule Rth = RAB
Rth = RAB = [(R1 + RA) // RB] + RC = 33k // 11k + 11k = 19,25k
3