Notesale: Turn your study into money

Document Preview

Extracts from the notes are below, to see the PDF you'll receive please use the links above

---

SET-1

àíZ-nÌ H$moS>

Series HFG1E/C

Q
...
Code

amob Z§
...


Candidates must write the Q
...
Code
on the title page of the answer-book
...
15 ~Oo {H$`m OmEJm & 10
...
30 ~Oo VH$ N>mÌ Ho$db àíZ-nÌ H$mo
-nwpñVH$m na H$moB© CÎma Zht {bI|Jo &

*

Please check that this question paper contains 23 printed pages
...
P
...

Please check that this question paper contains 35 questions
...

15 minute time has been allotted to read this question paper
...
15 a
...
From 10
...
m
...
30 a
...
,
the students will read the question paper only and will not write any
answer on the answer-book during this period
...
T
...


:
:
35

(i)
(ii)
(iii)

1

(iv)

19

(v)

26

(vi)

31

(vii)

33

18
25
30
32
35

(viii)

2
2

2

2

(ix)

IÊS> H$
1

18

18 1=18

1
...


{ZåZ{b{IV A{^{H«$`mAm| _| go H$m¡Z-gr h¡bmoOZ {d{Z_` A{^{H«$`m h¡

?

(a)

C=C

+ HX

(b)

R

X + NaI

(c)

R

OH + HCl

C
|
H

ewîH$ EogrQmoZ
ZnCl2

C
|
X
R

R

Cl + H2O

(d)

56/C/1

I + NaX

2

General Instructions :
Read the following instructions carefully and strictly follow them :
(i)

This question paper contains 35 questions
...


(ii)

This question paper is divided into five Sections

(iii)

In Section A
Questions no
...


(iv)

In Section B Questions no
...


(v)

In Section C Questions no
...


(vi)

In Section D
4 marks each
...
33 to 35 are Long Answer (LA) type questions
carrying 5 marks each
...


Questions no
...
However, an internal choice has been provided in
2 questions in Section B, 2 questions in Section C, 2 questions in Section D and
2 questions in Section E
...

SECTION A
Questions no
...

18 1=18
1
...


Which of the following reactions is a halogenated exchange reaction :
(a)

C=C

+ HX

(b)

R

X + NaI

(c)

R

OH + HCl

C
|
H
Dry acetone

ZnCl2

C
|
X
R

R

I + NaX

Cl + H2O

(d)

56/C/1

3

P
...
O
...


4
...


X Am¡a Y
25

6
...


Xmo d¡ÚwV-AnKQ>çm| Ho$ {db`Zm| H$m VZwH$aU {H$`m J`m & X H$s _moba MmbH$Vm
Y H$s 1·5 JwZm & H$m¡Z-gm à~bVa d¡ÚwV-AnKQ>ç h¡ ?

(a)

X

(b)

Y

(c)

X Am¡a Y XmoZm|

(d)

Cn`w©º$ _| go H$moB© Zht

eyÝ` H$mo{Q> A{^{H«$`m Ho$ {bE doJ pñWam§H$ H$s BH$mB© h¡
(a)

s 1

(b)

mol 1 L s 1

(c)

mol 2 L2 s 1

(d)

mol L 1 s 1

ZrMo VrZ `m¡{JH$ {XE JE h¢

:

CZH$s jmaH$s` gm_Ï`© H$m ghr KQ>Vm hþAm H«$_ h¡

56/C/1

:

:

(a)

II > III > I

(b)

III > II > I

(c)

III > I > II

(d)

I > III > II

4

3
...


The most common oxidation state for all lanthanoids is :
(a)

+5

(b)

+2

(c)

+3

(d)

+4

A reaction follows second order kinetics
...


four times
1
of the original value
4

(b)

eight times

(d)

three times

Solutions of two electrolytes X and Y are diluted
...
Which one is a
stronger electrolyte ?

6
...


(a)

X

(b)

Y

(c)

Both X and Y

(d)

None of the above

Unit of rate constant for the zero order reaction is :
(a)

s 1

(b)

mol 1 L s 1

(c)

mol 2 L2 s 1

(d)

mol L 1 s 1

Three compounds are given below :

The correct decreasing order of their basic strength is :

56/C/1

(a)

II > III > I

(b)

III > II > I

(c)

III > I > II

(d)

I > III > II

5

P
...
O
...


g§Hw$b
h¢ ?
(a)
(c)

[Co(NH3)5Br]SO4

Am¡a

[Co(NH3)5SO4]Br

~§YZr
Y«wdU

(b)
(d)

moJm

9
...


noÝQ>oZ-2-AmoZ Am¡a noÝQ>oZ-3-AmoZ _| {ZåZ{b{IV _| go {H$gHo$ Ûmam {d^oX {H$`m Om gH$Vm
h¡ ?
(a)
\o$qbJ narjU
(b)
gmo{S>`_ ~mBH$m~m}ZoQ> narjU
(c)
Q>m°b|g narjU
(d)
Am`moS>mo\$m°_© narjU

11
...


Which type of isomerism is shown by the complexes [Co(NH3)5Br]SO4
and [Co(NH3)5SO4]Br ?

9
...


C = O + CH3MgI

(a)

Ethanal

(b)

Propanol

(c)

Ethanol

(d)

Propanal

H2O

Pentan-2-one and Pentan-3-one can be distinguished by :
(a)
(b)

Sodium bicarbonate test

(c)
(d)
11
...
T
...


12
...


14
...


Given below is the decomposition of hydrogen peroxide in alkaline
medium, which is catalysed by iodide ions :
2H2O2

I
alkaline medium

2H2O + O2

The above reaction takes place in two steps :
Step I : H2O2 + I
Step II : H2O2 + IO

H2O + IO (slow)
H2O + I + O2

Molecularity of Step I and Step II is :
(a)
(b)
(c)
(d)
13
...


Oxidation state of central metal atom in the given complex is :
[Co(NH3)4(H2O)2]Cl3
(a)

+2

(b)

+3

(c)

+1

(d)

+4

A galvanic cell can behave as an electrolytic cell when :
(a)
Ecell = Eext
(b)
Ecell > Eext
(c)

Ecell = 0

(d)

Eext > Ecell

For Questions number 15 to 18, two statements are given

one labelled as

Assertion (A) and the other labelled as Reason (R)
...


56/C/1

(a)

Both Assertion (A) and Reason (R) are true and Reason (R) is the
correct explanation of the Assertion (A)
...


(c)

Assertion (A) is true, but Reason (R) is false
...

9

P
...
O
...


(A) :
(R) :

µ\$sZm°b, gm§Ð HNO3 Am¡a gm§Ð H2SO4 Ho$ gmW A{^{H«${`V {H$E OmZo
na 2,4,6-Q´>mBZmBQ´>moµ\$sZm°b XoVr h¡ &
µ\$sZm°b _| OH g_yh m-{ZX}eH$ hmoVm h¡ &

(A) : D (+)-½byH$mog

16
...


(R) :

18
...


Vmn _| 293 K go 313 K VH$ d¥{Õ H$aZo na {H$gr A{^{H«$`m H$m doJ Mma JwZm hmo OmVm
h¡ & Bg A{^{H«$`m Ho$ {bE g{H«$`U D$Om© H$s JUZm `h _mZVo hþE H$s{OE {H$ BgH$m _mZ
Vmn Ho$ gmW n[ad{V©V Zht hmoVm &

2

(log 2 = 0·30, log 4 = 0·60) [R = 8·314 J K 1 mol 1]
20
...


Assertion (A) : Phenol gives 2,4,6-trinitrophenol on treatment
concentrated HNO3 and concentrated H2SO4
...


Reason (R) :
16
...

Reason (R) :

17
...

Reason (R) :

Zn, Cd and Hg do not have partially filled d-orbitals in
their ground state or in any one of their common
oxidation states
...


Assertion (A) : Benzene diazonium salt is stable and can be easily stored
...

SECTION B

19
...
Calculate the energy of activation of the reaction,
assuming that it does not change with temperature
...


(a)

(i)

Name any two bases which are common to both DNA and
RNA
...
T
...


21
...


{ZåZ{b{IV H$mo CZHo$ WZm§H$m| Ho$ Amamohr H«$_ _| ì`dpñWV H$s{OE
1, 2, 1? EH$ CXmhaU Xr{OE &

(a)

[Ti(H2O)6]3+

(b)

{XE JE g§H$w b H$m AmB©
...
nr
...
gr
...


(a)
(b)

24
...


2

bmoho Ho$ nmBn gm_mÝ`V:
H$s dmoëQ>Vm BgH$s g§nyU© H$m`©-

?

h¡

?

2

(b)

eyÝ` H$mo{Q> A{^{H«$`m Ho$ {bE doJ pñWam§H$ Am¡a AY©-Am`w Ho$ _Ü` J{UVr` g§~§Y
{b{IE &
EH$ CXmhaU Ho$ gmW N>X²_ àW_ H$mo{Q> A{^{H«$`m H$s n[a^mfm Xr{OE &

(a)

CH3COOH Ho$ pKa _mZ

(b)

hmoVm h¡ ?
hob-\$mobmS>©-µOoqbñH$s A{^{H«$`m Ho$ {bE amgm`{ZH$ g_rH$aU {b{IE &

(a)

H$s Anojm

2

ClCH2COOH H$m pKa
2

IÊS> J
26
...


(a)

(i)

Write the structure of 1-chloro-4-ethylcyclohexane
...


What is an ambident nucleophile ? Give one example
...


24
...


2

(a)

Why are iron pipes usually coated with zinc ?

(b)

Why does mercury cell give a constant voltage throughout its life ?

(a)

Write the mathematical relation between rate constant and
half-life period of a zero order reaction
...


(a)

Why is pKa of ClCH2COOH lower than the pKa value of CH3COOH ?

(b)

Write the chemical equation for Hell-Volhard-Zelinsky reaction
...


56/C/1

Write the chemical equation for the following :
(a)

Hydration of propene in presence of an acid
...


(c)

Reaction between Dimethyl ether and Hydrogen iodide
...
T
...


27
...


:

(CH3COOH)2

EH$ 0·05 L {db`Z _| 3·5 g àmoQ>rZ Kwbr hþB© h¡ & 310 K na Bg {db`Z H$m
namgaU Xm~ 0·035 atm h¡ & àmoQ>rZ Ho$ _moba Ðì`_mZ H$m n[aH$bZ H$s{OE &

1+2

(R = 0·0821 L atm K 1 mol 1)
29
...


(a)

(i)
(ii)

V¥Vr¶H$ EopëH$b h¡bmBS>|
à{Vq~~ ê$n (EZopÝQ>

SN1 A{^{H«$¶m

(iii)

?

?

AWdm
56/C/1

Vrd« doJ go ³¶m| XoVo h¢

14

1+1+1

27
...


(b)

Its shape and magnetic behaviour
...


1+1+1

[Atomic number : Co = 27]
28
...


factor for acetic acid in benzene as per

(CH3COOH)2, assuming its complete association
...
Calculate the molar
mass of the protein
...


(a)

Reduction with iron scrap and HCl is preferred for the preparation
of amines from nitro compounds
...


(c)

Pyridine is used in the acylation reaction of amines
...


(a)

(i)

Why do tertiary alkyl halides undergo SN1 reaction at a
faster rate ?

(ii)

Define Enantiomers
...
T
...


(b)

(i)

2-

(ii)

CH3

(iii)

Vrd«Vm go XoJm Am¡a ³¶m| ?
Zm{^H$amJr à{VñWmnZ A{^{H«$¶m Ho$ à{V ³bmoamo~oݵOrZ
³¶m| h¡

B

2

Br

VWm

CH3

SN2 A{^{H«$¶m

Br

?

1+(

1
2

IÊS> K
:
31
...


(ii)

Which would undergo SN2 reaction at a faster rate and
why ?

CH3

(iii)

2

be

formed

by

Br and CH3

Why is chlorobenzene less reactive towards nucleophilic
substitution reaction ?

1+(

1
2

1

+ )+1
2

SECTION D
The following questions are case-based questions
...


Carbohydrates are the major components of all living organisms
...
The major types of sugars include monosaccharides
and disaccharides
...

Monosaccharides are single sugar molecules which act as the building
blocks of disaccharides and polysaccharides
...
Disaccharides are classified into two groups according to their
reducing strength : Reducing and Non-reducing sugars
...
Starch, glycogen and cellulose
are examples of polysaccharides
...
Glycogen is the major
carbohydrate storage product found in humans
...

Cellulose is the most abundant organic molecule on Earth
...


56/C/1

17

P
...
O
...


:

dmînerb Ðd

, O~{H$ Admînerb {dbo¶ Ho$ {bE {db¶Z H$m

-

hmoVm h¡ &

, {db`Z H$s dmîn àmdñWm
,

A Am¡a B Xm

Vmo Hw$b dmîn
B H$mo KmobH$a
h¡ & ¶{X {dbm¶H$ A
{db¶Z ~Zm¶m OmE, Vmo ewÕ {dbm¶H$ H$s Anojm {db¶Z H$m dmîn Xm~ {ZåZVa hmoJm &
, AmXe© {db¶Z H$hbmVo
h¢, O~{H$ Eogo {db¶Z {OZH$m dmîn Xm~
, AZmXe© {db¶Z H$hbmVo h¢ & {H$gr {deof {db¶Z
-AmpÊdH$ ~bm| Ho$
m|
H$s nhMmZ H$s OmVr h¡ & do ¶m Vmo amCëQ> H
Xem© gH$Vo h¢,
Am¡a
Aݶmoݶ{H«$¶mAm| H$s
Anojm
Aݶmoݶ{H«$¶mE± à~bVa h¢ AWdm Xþ~©b h¢ &

{ZåZ{b{IV àíZm| Ho$ CÎma Xr{OE
(a)

56/C/1

:

Ðd A Ho$ 20 mL H$mo Ðd
H$m Am¶VZ 40 mL
{ZH$mbVo h¢ ?

B

Ho$

20 mL

o Amn ³¶m {ZîH$f©
18

Answer the following questions :
(a)

Name the linkage which connects monosaccharide units in
polysaccharides
...
Write the hydrolysis products of sucrose
...


(c)

32
...
Why ?
1+1+2

s states that the partial vapour pressure of
each component in the solution is directly proportional to its mole fraction,
whereas for a non-volatile solute, it states that the vapour pressure of a
solution of a non-volatile solute is equal to the vapour pressure of the pure
solvent at that temperature multiplied by its mole fraction
...
Once the components in the
solution have reached equilibrium, the total vapour pressure of the
solution can be determined by combining Ra
law with
partial pressures
...
The solutions which obey
over the
entire range of concentration are ideal solutions, whereas the solutions for
which vapour pressure is either higher or lower than that predicted by
R
alled non-ideal solutions
...
They can
either show positive or negative deviation from
depending
on whether the A B interactions in solution are stronger or weaker than
and
interactions
...
The volume
of resulting solution was found to be less than 40 mL
...
T
...


(b)

(c)

{ZåZ{b
H$m~©Z S>mB

?

µ\$sZm°b Am¡a Eo{ZbrZ; EWoZm°b Am¡a EogrQ>moZ

100 C

750 mm Hg

h¡ & {dbo¶ Ho$

(373 K na
(c)

O~

1

Ob H$m dmîn Xm~ = 760 mm Hg)
AWdm
, Vmo {db¶Z H$m
NaCl H$m 1
H$m 1
KQ> OmVm h¡ & Cn`w©º$ àojUm| H$s ì¶m»¶m H$s{OE &

WZm§H$
1+1+2

IÊS> L>
33
...
dm
...
dm
...

H¡$WmoS> na hmoZo dmbr AnM¶Z AY©-A{^{H«$¶m {b{IE &
(ii)
(iii)

{H$gr A{^{H«$
D$Om©, gmå¶ pñWam§H$ go H¡$go g§~§{YV h¡
{XE JE gob H$m {d
...
~b (emf) n[aH${bV H$s{OE :
Mg (s) Mg2+ (0·1 M) Cu2+ (1·0

{X¶m J¶m h¡

: E

Cu 2 / Cu

= + 0·34 V, E

10 3 M) Cu (s)
Mg 2 / Mg

=

?

1+1+3

2·37 V

(log 100 = 2)

AWdm
(b)

(i)
(ii)

Am
J{bV

D$
Al2O3

go

40 g Al
?

(iii)

({X¶m J¶m h¡ : Al
298 K na {ZåZ{b{IV A{^{H«$¶m Ho$ {bE
Zn (s) + Cu2+ (aq)

{X¶m J¶m h¡
56/C/1

: E

Zn 2 / Zn

=
20

= 27 u)
log Kc n[aH${bV

H$s{OE

Zn2+ (aq) + Cu (s)
0·76 V, E

Cu 2 / Cu

= + 0·34 V

:
1+1+3

(b)

Which of the following show positive deviation from
Carbon disulphide and Acetone; Phenol and Aniline; Ethanol and
Acetone

(c)

The vapour pressure of a solution of glucose in water is 750 mm Hg
at 100 C
...

(Vapour pressure of water at 373 K = 760 mm Hg)
OR
The boiling point of solution increases when 1 mol of NaCl is added
to 1 litre of water while addition of 1 mol of methanol to one litre of
water decreases its boiling point
...
1+1+2

(c)

SECTION E
33
...

Write the reduction half-reaction at cathode
...
T
...


34
...


¶m¡{JH$ A {OgH$m AmpÊdH$ gyÌ (C2H6O) h¡, PCC Ûmam Am°³grH$aU go ¶m¡{JH$
XoVm h¡, Omo VZw jma go A{^{H«${¶V hmoH$a ¶m¡{JH$ C
-hmBS´>m°³gr EopëS>hmBS> h¡ & B nmoQ>¡
m Am°³grH¥$V hmoH$a C
H$aVm h¡ & A, B, C Am¡a D
g_rH$aU {b{IE &

{ZåZ{b{IV àíZm| Ho$ CÎma Xr{OE

:

5

1+1+1+1+1

(a)

b¢WoZm°¶S>m|

H$s agm¶Z A{YH$ O{Q>b hmoVr h¡ & ³¶m|

(b)

Mn3+/Mn2+

E

?
?

(c)

56/C/1

B

?
Fe2+

(d)

AåbrH¥$V nmoQ>¡

(e)

M Ho$ {Ûg§¶moOr Am¶Z Ho$ {bE àMH«$UO
AmKyU© H$s JUZm H$s{OE & YmVw M
25 h¡ &

22

Am¶Zm| go A{^{H«$¶m H$aVm h¡

?

Mw§~H$s`

34
...
Compound B does not give
Fehling s test but reacts with conc
...

Identify A, B, C and D and write all the reactions involved
...


5
OR

(b)

Compound A with molecular formula (C2H6O) on oxidation by PCC
gives compound B, which on treatment with dilute alkali forms
compound C which is a

-hydroxy aldehyde
...
Identify A, B, C and D and
write all the chemical equations involved
...


Answer the following questions :
(a)

5
1+1+1+1+1

The chemistry of the actinoids is more complex as compared to
lanthanoids
...


(e)

Calculate the
metal M in aqueous solution
...


56/C/1

23

P
...
O

---