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Title: √2
Description: Ch 1 of maths

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Providing √2 irrational
That's a great proof! You've successfully shown that assuming √2 is rational leads to a
contradiction, thus proving that √2 is indeed irrational
...
Assume √2 is rational, so √2 = a/b (where a and b are integers with no common factors)
...
Square both sides: 2 = a^2/b^2
...
Clear the fraction: 2b^2 = a^2
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Analyze the equation: a^2 is even, so a is even (a = 2k)
...
Substitute a = 2k: 2b^2 = (2k)^2 => b^2 = 2k^2
...
Conclude b is even (since b^2 is even)
...
Reach a contradiction: Both a and b are even, so they have a common factor of 2,
contradicting the assumption of simplest form
...
Conclusion: √2 is irrational
...



Title: √2
Description: Ch 1 of maths