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Title: Edexcel a level biology question paper 1 june 2024 salters Nuffield + mark scheme
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel Advanced Level In Biology A Salters – Nuffield (9BN0) Paper 01: The Natural Environment and Species Survive

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Edexcel a level biology
question paper 1 june
2024 salters Nuffield +
mark scheme

Please check the examination details below before entering your candidate information
Candidate surname

Centre Number

Other names

Candidate Number

Pearson Edexcel Level 3 GCE

Wednesday 5 June 2024
Afternoon (Time: 2 hours)

Paper
reference

9BN0/01

Biology A (Salters Nuffield)

 

Advanced

PAPER 1: The Natural Environment and Species

Survival

You must have:
Calculator, HB pencil, ruler

Total Marks

Instructions

Use black ink or ball-point pen
...

Answer all questions
...


the questions in the spaces provided
• Answer
– there may be more space than you need
...


marks for each question are shown in brackets
• The
– use this as a guide as to how much time to spend on each question
...


• In questions marked with an asterisk (*), marks will be awarded for your ability to

structure your answer logically showing how the points that you make are related or
follow on from each other where appropriate
...


Try to answer every question
...

Turn over

P74456A

©2024 Pearson Education Ltd
...



Energy flow through this ecosystem has been studied
...




The gross primary productivity (GPP) for this ecosystem is 87 069 kJ m–2 yr–1
...




(a) (i) Which of the following is the correct value for the net primary productivity
(NPP) in this ecosystem?

(1)

A
7 025 731 kJ m  yr
–2

–1

B
697 036 kJ m–2 yr–1
C
142 264 kJ m–2 yr–1
D
31 874 kJ m–2 yr–1


(ii) The table shows some information on trophic levels in this ecosystem
...
If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross
...
Write your answers in the spaces provided
...

Give your answer to two significant figures
...




(b) Describe the role of mineral ions in the production of plant biomass
...



...



...



...



...



...



...




(a) Describe how carbon dioxide is used in photosynthesis
...



...



...



...



...



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(b) The effect of increasing carbon dioxide concentration on photosynthesis in soya
bean plants was investigated
...




Carbon dioxide concentration / ppm

Mean dry mass of leaves / g m–2

160

20
...
1

220

20
...
7

280

21
...
4

330

21
...
4

660

26
...
2

990

30
...
2

(i) Which of the following describes the relationship between the increase in
carbon dioxide concentration and the change in dry mass?

(1)

A
exponential
B
negative correlation
C
positive correlation
D
no correlation


(ii) The measurements were repeated at each concentration to calculate the
mean and standard deviation
...


(3)


...



...



...



...



...



...


(Total for Question 2 = 9 marks)

6

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Explain why an increase in carbon dioxide concentration above 1000 ppm may
not increase the rate of photosynthesis
...



One of the first people to isolate and test a drug was William Withering
...


(1)


...


Procedure



(2)

Type of trial
William Withering

Contemporary drug trial

Use of a placebo

ü

Testing of dose

ü

Tested on healthy volunteers

ü

Double blind trial

ü

*P74456A0728*

7

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(c) Paclitaxel is a drug used in the treatment of cancer
...

Deduce why Paclitaxel prevents cell division in cancer cells
...



...



...



...



...



...



...


(Total for Question 3 = 6 marks)

8

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Cancer involves cells dividing repeatedly in an uncontrolled manner
...



It is caused by mutations in the gene coding for the cystic fibrosis transmembrane
conductance regulator (CFTR) protein
...




(a) Describe how a mutation can change the primary structure of a protein
...



...



...



...



...




(b) (i) The CFTR protein is produced in cells of the lung and is involved in the
transport of chloride ions
...


(2)


...



...



...




*P74456A0928*

9

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(ii) Describe how the CFTR protein is transported from the ribosome to the
cell membrane
...



...



...



...



...




(c) The most common mutation in the CFTR gene produces a protein that has the
incorrect shape
...


(3)


...



...



...



...



...


(Total for Question 4 = 11 marks)

10

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(3)

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5 Photosynthesis takes place in the chloroplast
...

L

J

N
(Source: © Kazakova Maryia / Shutterstock)



(i) Which part of the chloroplast is labelled L?
A
a plasmid containing chloroplast DNA

(1)

B
the matrix where the Krebs cycle takes place
C
the stroma where the Calvin cycle takes place
D
the thylakoid where the light‑dependent reactions take place


(ii) The part labelled J is

(1)

A
the matrix where the light‑dependent reactions take place
B
the matrix where the light‑independent reactions take place
C
the stroma where the light‑dependent reactions take place
D
the stroma where the light‑independent reactions take place
(iii) Which of the following is stored in the structure labelled N?

(1)

A
chlorophyll
B
glucose
C
lipid
D
starch



*P74456A01128*

11

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...




(ii) The rate of light‑dependent reactions can be measured in
isolated chloroplasts
...

Describe how DCPIP can be used to measure the effect of temperature on the
rate of the light‑dependent reactions in isolated chloroplasts
...



...



...



...



...



...



...


(Total for Question 5 = 8 marks)

12

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(1)

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(b) (i) Give the names of two products of the light‑dependent reactions
of photosynthesis
...



This is leading to changes in the germination of plant seeds
...




(a) Describe the structure of starch
...



...



...



...



...



...


The percentage germination of these seeds at the mean spring temperature for
these woodlands was compared with an increase of 5 °C
...


(3)


...



...



...



...



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(ii) Global warming can result in climate change
...


(2)


...



...



...




(c) To conserve plant species, seeds may be stored in seed banks
...


(3)


...



...



...



...



...




(a) (i) A population is a group of individuals
A
of different species living in the same habitat

(1)

B
of one species living in different communities
C
of one species living in different ecosystems
D
of one species living in the same habitat


(ii) In the wild, several species of deer can live in the same area
...


(2)


...



...



...




(b) In one species of deer, a mutation has led to the occurrence of white deer
...


The results of a study of one of these reserves are shown in the table
...
Several species of deer can be found
in the UK
...


The allele for brown coats is dominant and the allele for white coats
is recessive
...

p2 + 2pq + q2 = 1
...



(ii) It may be beneficial for a population to contain a higher percentage of
heterozygote individuals
...
Heterozygotes may have an allele which allows for adaptation if
conditions change
...
Heterozygotes reduce genetic diversity
...
A beneficial allele could be recessive and heterozygotes breeding together
may produce a homozygous recessive offspring
...


Devise a procedure that could be used to measure plant biodiversity in these
two areas
...



...



...



...



...



...



...



...


(Total for Question 7 = 11 marks)

18

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An area with a large population of deer was compared with an area from which
deer were excluded
...



One of the genes studied was the gene for the enzyme lactase
...




(a) (i) Which of the following statements about the action of lactase is correct?

(1)

A
lactase changes the products of the reaction
B
lactase increases the activation energy of the reaction
C
lactase is used up in the reaction
D
lactase reduces the activation energy of the reaction


(ii) Describe the role of ribosomes in the synthesis of lactase
...



...



...



...



...


The study recorded changes in the frequency of this mutation over the past
4000 years
...
096

0
...
280

0
...
680

0
...
770

0
...
740

0
...


Calculate the percentage increase in the frequency of this mutation in the UK
in the last 4000 years
...


20

*P74456A02028*

%

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In Europe, a single mutation resulted in the continued production of lactase
enzyme by children and adults
...


Many children and adults in Europe have a mutation that allows continued
production of lactase enzyme
...


(4)


...



...



...



...



...


(Total for Question 8 = 10 marks)



*P74456A02128*

21

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In some children, hepatitis C can cause serious liver damage
...




(i) Explain the role of a fever in the immune response
...



...



...



...



...


Describe how the activation of T helper cells leads to the production
of antibodies
...



...



...



...



...


22

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9 Hepatitis C is a virus that can infect the liver
...


The virus causing hepatitis C has a similar structure to HIV
...

Deduce how the hepatitis C virus is able to enter liver cells
...



...



...



...



...

Infection with hepatitis B can be treated with drugs and a vaccine is available
...



...



...



...



...



...



...



...



...



...



...


(Total for Question 9 = 15 marks)

24

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10 Resistance of bacteria to antibiotics is an increasing problem
...




Researchers have developed new antibiotics that are effective against a number of
strains of bacteria
...




(a) Which of the following statements describes a bactericidal antibiotic?

(1)

A
a substance that can only be used on the skin
B
a substance that kills bacteria
C
a substance that prevents reproduction of bacteria
D
a substance that prevents reproduction of viruses


(b) Two new antibiotics have been developed: antibiotic A and antibiotic B
...


Each species of bacteria (P and Q) was grown in cultures containing:


antibiotic A



antibiotic B



ciprofloxacin



no antibiotic

Each culture was sampled at 0, 1, 2, 4, 6 and 24 hours and the number of viable
cells was recorded
...




*P74456A02528*

25

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no antibiotic
antibiotic A
antibiotic B
ciprofloxacin

10
8
Log10 viable
cells per cm3 6
4
2
0
0

5

10

15

20

25

20

25

Time / hours
Bacteria species Q

12
10
8
Log10 viable
cells per cm3 6
4
2
0
0

5

10

15

Time / hours


(i) Calculate the mean rate of decrease in the number of cells in the first
four hours for species P for antibiotic B
...

26

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Key:

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Bacteria species P

12

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(ii) Comment on the effectiveness of antibiotics A and B against both species
of bacteria
...



...



...



...



...


*(iii) A further investigation found the optimum concentration needed to kill
bacteria for each of the new antibiotics using cultures on agar plates
...


(6)


...



...



...



...



...



...




*P74456A02728*

27

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...



...



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...



...



...


(Total for Question 10 = 13 marks)
TOTAL FOR PAPER = 100 MARKS

28

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Examiners
must mark the first candidate in exactly the same way as they
mark the last
...
Candidates must be
rewarded for what they have shown they can do rather than
penalised for omissions
...




There is no ceiling on achievement
...




All the marks on the mark scheme are designed to be awarded
...
e
...
Examiners should also be
prepared to award zero marks if the candidate’s response is not
worthy of credit according to the mark scheme
...




When examiners are in doubt regarding the application of the
mark scheme to a candidate’s response, the team leader must
be consulted
...


Question
Number
1(a)(i)

Answer

Mark

The only correct answer is D 31874 kJm-2yr-1
...
065%
ALLOW one mark if 4615
divided by incorrect value
and used to calculate
percentage
Correct answer with no
working gains full marks
(2)

Question
Number
1(b)

Answer

Additional guidance

Mark

A description that makes reference to three of the following


nitrates are needed for amino acid synthesis (1)



magnesium (ions) are needed to make chlorophyll (1)



calcium (ions) are needed for {calcium pectate / middle
lamella} (1)



chlorophyll is needed for photosynthesis and the
production of { organic molecules / biomass } (1)



phosphates are needed for { membranes / phospholipids /
nucleic acids / ATP / NADP } (1)

ALLOW nucleotides / (nitrogenous)
bases / DNA / RNA / nucleic acids /
ATP / protein
IGNORE nitrogen ions

(3)

Question
Number
2(a)

Answer

Additional Guidance

Mark

A description that makes reference to the following


( carbon dioxide is ) needed for { light-independent stage / Calvin ALLOW carbon fixation
cycle } (1)



it combines with RuBP / ribulose bisphosphate (1)



catalysed by RUBISCO (1)

ALLOW involves the enzyme
RUBISCO



for the synthesis of named organic molecules (1)

e
...
GP, GALP, glucose
(4)

Question
Number
2(b)(i)

Answer

Mark

The only correct answer is C positive correlation
A is incorrect because the relationship is not exponential
B is incorrect because the relationship is not a negative correlation
D is incorrect because there is a correlation

(1)

Question
Number
2(b)(ii)

Answer

Mark

The only correct answer is B to determine the repeatability of the data
A is not correct because a chi-squared test- does not require repeats
C is incorrect because this does not improve the accuracy
D is not correct because this does not increase validity

(1)

Question
Number
2(c)

Answer

Additional guidance

Mark

An explanation that makes reference to three of the following


all the active sites (of the enzymes) are occupied (1)



enzyme concentration is limiting / no more
enzyme-substrate complexes can be formed (1)



RUBISCO cannot fix carbon dioxide any faster (1)



(therefore) limiting the rate (of photosynthesis) (1)

ALLOW named enzyme e
...

RUBISCO

ALLOW reference to other named
limiting factors such as light {
intensity / wavelength },
temperature or water availability
(3)

Question
Number
3(a)

Answer


Additional guidance

digitalin / digitalis / digitalis soup (1)

Mark

ALLOW extract of foxglove
plants / foxglove extract
IGNORE ‘foxglove’ alone
IGNORE digoxin
(1)

Question
Number
3(b)

Answer

Additional guidance

Mark

Table completed correctly- one mark for each two correct x or ✓
Methods used

William
Withering

All correct- full
marks

Use of a placebo

x

2 or 3 correct-1 mark

Testing of dose



Tested on healthy volunteers

x
x

Double blind trial

(2)

Question
Number
3(c)

Question
Number
4(a)

Answer

Additional guidance

Mark

An answer that makes reference to the following


shortening of the spindle (fibres) separates the chromatids (1)



if spindle fibres cannot shorten, the { chromatids /
chromosomes } cannot be pulled to opposite poles of the cell /
cell remains in metaphase stage (1)



(if the spindle cannot shorten) the cell cannot enter { anaphase
/ telophase } / mitosis cannot be completed (1)

Answer

ALLOW pull chromatids apart

Additional guidance

(3)

Mark

A description that makes reference to the following


there is a change in the { base sequence / triplet code }
in the { DNA / gene } (1)



this changes the sequence of bases in mRNA (during
transcription) (1)

ALLOW different (mRNA) codons



causing a change in the amino acid sequence (at
translation) (1)

ALLOW fewer amino acids in
chain (because of earlier STOP
codon)

(3)

Question
Number
4(b)(i)

Answer

Additional guidance

Mark

A description that makes reference to the following


(CFTR) is in the phospholipid bilayer (1)



it extends through both layers (of the bilayer) (1)

ALLOW intrinsic / integral /
transmembrane
IGNORE ref to basal and apical
membrane
(2)

Question
Number
4(b)(ii)

Answer

Additional guidance

Mark

An answer that makes reference to the following


(from ribosome) moves to rER where it is { folded / takes
tertiary structure } (1)



transported to Golgi apparatus where it is { modified /
packaged into vesicles } (1)



vesicles fuse with { plasma / cell } membrane (inserting
protein into membrane) (1)

ALLOW 3D shape

IGNORE binds
IGNORE exocytosis
(3)

Question
number
4(c)

Answer

Additional Guidance

Mark

An explanation that makes reference to three of the following



the amino acids (in the protein) are changed (1)



(therefore) there will be different R groups (1)



this will change bonds formed between { amino acids / R
groups } (1)



(polypeptide) folds differently / different tertiary structure
(of protein) (1)

ALLOW correctly named bonds such as
ionic, disulfide, hydrogen

(3)

Question
Number
5(a)(i)

Answer

Mark

The only correct answer is D the thylakoid where the light dependent reaction takes place




A is incorrect because L is not the plasmid
B is incorrect because Krebs cycle does not take place in the
chloroplast
C is incorrect because L is not the stroma
(1)

Question
Number
5(a)(ii)

Answer

Mark

The only correct answer is D the stroma where the light-independent reaction takes place




A is incorrect because it is not the matrix
B is incorrect because it is not the matrix
C is incorrect because it is not the site of the light- dependent reaction
(1)

Question
Number
5(a)(iii)

Answer
The only correct answer is D starch




Question
Number
5(b)(i)

Mark

A is incorrect because it does not store chlorophyll
B is incorrect because it does not store glucose
C is incorrect because it does not store lipid

Answer

(1)

Additional guidance

Mark

An answer that makes reference to any two the following
oxygen, ATP, reduced NADP

ALLOW O2, NADPH, NADPH +
H+, NADPH2
(1)

Question
Number
5(b)(ii)

Answer

Additional guidance

Mark

An answer that makes reference to four of the following

e
...
values between 0°C and 50°C



suitable range of temperatures given (1)



light intensity constant for duration of investigation (1)



one other abiotic variable controlled (1)

e
...
concentration or volume of
DCPIP, pH



biotic variable controlled (1)

e
...
plant species / mass of plant
material used / concentration or
volume of chloroplast extract



measure time taken for DCPIP to { decolourise / change
colour } (at each temperature) (1)

DO NOT ALLOW the solution goes
colourless
ALLOW use of colorimeter to
measure the change in absorbance
over time

(4)

Question
Number
6(a)

Answer

Additional guidance

Mark

A description that makes reference to three of the following


{polymer / polysaccharide} of alpha glucose (1)



made up of amylose and amylopectin (1)



amylose is unbranched and amylopectin is branched (1)



amylose has 1,4-glycosidic bonds and amylopectin has 1,6
and 1,4 glycosidic bonds (1)

DO NOT ALLOW beta glucose

ALLOW amylose is {linear /
straight-chained}

(3)
Question
Number
6(b)(i)

Answer

Additional guidance

Mark

An explanation that makes reference to three of the following


increase in (spring) temperature increased germination for
all three species (1)



(because) there is more (kinetic) energy and more
(frequent) collisions between substrate and enzyme (1)



(therefore) starch is { broken down / hydrolysed } faster (1)



greater supply of glucose increases the rate of respiration
(1)

ALLOW { lipids/proteins } broken
down faster

(3)

Question
Number
6(b)(ii)

Question
Number
6 (c)

Answer

Additional guidance

Mark

An explanation that makes reference to the following



increase in temperature may lead to { earlier
germination / plants will grow further north } (1)



change in rainfall patterns may lead to { an increase in
drought resistant plants /a change in the distribution
of plants } (1)

Answer

ALLOW increase in temperature may lead to
{plants growing in different areas / more
germination}

(2)

Additional guidance

Mark

An answer that makes reference to the following



{ reduces / prevents } enzyme activity / inhibits
metabolic reactions (1)



prevents germination (1)



prevents { bacteria growth / fungal growth /
decomposition } (1)

ALLOW {stops / slows} respiration
DO NOT ALLOW photosynthesis

ALLOW prevents growth of pathogens
(3)

Question
Number
7(a)(i)

Answer

Mark

The only correct answer is D A group of individuals of one species living in the same habitat
A is incorrect because they are not different species
B is incorrect because they are not in different communities
C is incorrect because they are not in different ecosystems
(1)

Question
Number
7(a)(ii)

Question
Number
7(b)(i)

Answer

Additional guidance

Mark

An explanation that makes reference to the following


(each species) occupies a different niche (1)



therefore there is no competition (between species
of deer) for { food /space /territory } (1)

Answer
An answer that makes reference to the following

ALLOW no competition for resources
(2)
Additional guidance

Mark

Example of calculation



correct calculation of the frequency of both alleles (1)

q2 =250 ÷ 800 = 0
...
56 / 0
...
44 /
0
...
493 / 0
...
g 0
...
5m, 1mx1m
IGNORE grid, frame, pin

ALLOW comparison of species
richness using { a t-test / diversity
index values }

(4)

Question
Number
8(a)(i)

Answer

Mark

The only correct answer is D lactase reduces the activation energy of the reaction
A is incorrect because enzymes do not change the products of a reaction
B is incorrect because enzymes do not increase the activation energy of a reaction
C is incorrect because enzymes are not used up in the reaction
(1)

Question
Number
8(a)(ii)

Answer

Additional guidance

Mark

A description that makes reference to three of the following


the ribosomes receive mRNA (from the nucleus) / mRNA
binds to the ribosome (1)



(at the ribosome) an anticodon on tRNA pairs with the
(complementary) codon on the mRNA (1)



ribosome moves along the mRNA (1)



peptide bonds form between the amino acids (held at the
ribosome) (1)

ALLOW ribosome is the site of mRNA
translation

ALLOW mRNA moves along the
ribosome

(3)

Question
Number
8(b)(i)

Answer

Additional guidance

Mark

Example of calculation


difference in frequency of mutation calculated from figures in
table (1)



percentage increase correctly calculated (1)

0
...
096 = 0
...
644 ÷ 0
...
83 / 670
...

The indicative content below is not prescriptive and candidates are not required to include all the material which
is indicated as relevant
...

Indicative content
Basic information
• drugs such as Entecavir and Interferon treat infection
• antibodies and vaccine protects against infection
• reference to ease of application e
...
vaccine of 3 doses needed / drugs need taking daily or weekly
• vaccination leads to production of memory cells
Linkages








vaccine provides long lasting protection
drugs provide short term protection
antibodies provide artificial passive immunity
vaccination provides artificial active immunity
vaccination produces memory cells whereas antibodies will not
entecavir prevents virus replicating and spreading to other cells
interferon inhibits protein synthesis / formation of new virus particles

Sustained line of scientific reasoning







drugs reduce viral load
vaccine and antibodies lead to destruction of the virus by agglutination
drugs useful if people have potentially been infected / exposed to the virus
vaccine useful for people working in high-risk environment
interferon an option for the 5% not protected by vaccine
antibodies useful for new-born babies whose immunity is limited

(6)

Level
0
1

2

Marks
0
No awardable content
1-2
Demonstrates isolated elements of biological knowledge
and understanding to the given context with generalised
comments made
...

The discussion will contain basic information with some
attempt made to link knowledge and understanding to the
given context
...

Consequences are discussed which are occasionally
supported through linkage to a range of scientific ideas,
processes, techniques and procedures
...


Additional Guidance
Basic information referred to –
e
...
which treatments are for active infection or
protecting against infection
reference to comparative ease of application
basic reference to memory cells from vaccines
Linkages made:
e
...
mode of action discussed for the two drugs
how the vaccination or antibodies protect against
infection
type of immunity from antibodies and vaccine
relevant discussion of a drug and vaccination /
antibodies

3

5-6

Demonstrates comprehensive knowledge and
understanding by selecting and applying relevant
knowledge of biological facts/concepts
...

The discussion shows a well-developed and sustained line
of scientific reasoning which is clear and logically
structured
...
g
...
8 log 10 = 6
...
3 million ÷ 4 = 1
...
577 million
ALLOW 1 mark for 6
...
7
IGNORE - sign
Correct answer with no working gains
full marks

(2)

Question
Number
10(b)(ii)

Answer

Additional guidance

Mark

An answer that makes reference to the following


(overall) A is more effective against bacteria Q (1)



(overall) B more effective against bacteria P (1)



initially antibiotics A and B are more effective against
bacteria Q than bacteria P (1)



the bacteria are not resistant to the antibiotics / presence
of low numbers of bacteria Q in antibiotic B (at 25 hours)
not enough to indicate resistance (1)
(4)

Question
Number
*10b(iii)

Answer

Mark

Answers will be credited according to candidate’s deployment of knowledge and understanding of the
material in relation to the qualities and skills outlined in the generic mark scheme
...
Additional content included in the response must be scientific and relevant
...
g
...
g
...
g
...
Generalised
comments made
...

An explanation of how the investigation should be modified will
be given with occasional evidence of analysis, interpretation
and/or evaluation of the scientific information
...


3

5-6

An explanation of how the investigation should be modified is
given which is supported throughout by evidence from the
analysis, interpretation and/or evaluation of the scientific
information
...


The explanation shows a well-developed and sustained line of
scientific reasoning which is clear, coherent and logically
structured
...
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Title: Edexcel a level biology question paper 1 june 2024 salters Nuffield + mark scheme
Description: Mark Scheme (Results) Summer 2024 Pearson Edexcel Advanced Level In Biology A Salters – Nuffield (9BN0) Paper 01: The Natural Environment and Species Survive