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Title: solution for midterm for MECH 368
Description: these are the midterm solution for the MECH 368 (electronics for Mech. Engineers ). i have other midterms too in case someone wants to have.
Description: these are the midterm solution for the MECH 368 (electronics for Mech. Engineers ). i have other midterms too in case someone wants to have.
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Solution #1a
Page -1/4-
Solution #1b
For positive vS, current cannot flow clockwise because the diode is reverse-biased (see figure (a)
below)
...
During counter-clockwise current flow, the capacitor will charge to the maximum voltage of
−𝑣 𝑠 − 𝑉 𝐷𝐶 − 𝑉 𝐶 = 0
Since vS = 5 sin (ωt), at its counter-clockwise peak, vS = Vpeak = -5 V, and VDC = 2 V,
therefore,
𝑉 𝐶 = −𝑉 𝑝𝑒𝑎𝑘 − 𝑉 𝐷𝐶 = −(−5) − 2 = +3𝑉
The capacitor voltage and its polarity are shown in figure (a) below
...
From figure (a) above,
therefore,
𝑣 𝑜𝑢𝑡 = 𝑣 𝑆 (𝑡) + 𝑉 𝐶 = 5 sin(𝜔𝑡) + 3
Figure (b) above shows vout shifted up by 3V from vS(t)
...
D2 and D4 are forward-biased
...
7 = -4
...
2
0
...
2
0
...
When the output is taken at v02, the circuit represents a NAND gate
Title: solution for midterm for MECH 368
Description: these are the midterm solution for the MECH 368 (electronics for Mech. Engineers ). i have other midterms too in case someone wants to have.
Description: these are the midterm solution for the MECH 368 (electronics for Mech. Engineers ). i have other midterms too in case someone wants to have.