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Title: Quadratic equations solutions and formula
Description: Well described formulas which can make an amature student understand properly
Description: Well described formulas which can make an amature student understand properly
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Methods for Solving Quadratic Equations
Quadratics equations are of the form ax 2 + bx + c = 0, where a ≠ 0
Quadratics may have two, one, or zero real solutions
...
FACTORING
Set the equation equal to zero
...
Example:
x 2 = −5 x − 6
Move all terms to one side
Factor
Set each factor to zero and solve
x2 + 5x + 6 = 0
( x + 3)( x + 2) = 0
x+3= 0
x+2=0
x = −3
x = −2
2
...
Then take the square root of both sides
...
)
Example 1:
x 2 − 16 = 0
Move the constant to the right side
x 2 = 16
Take the square root of both sides
x 2 = ± 16
x = ±4, which means x = 4 and x = −4
Example 2:
2( x + 3) 2 − 14 = 0
Move the constant to the other side
2( x + 3) 2 = 14
Isolate the square
( x + 3) 2 = 7
Take the square root of both sides
(divide both sides by 2)
( x + 3) 2 = ± 7
x+3= ± 7
Solve for x
x = −3 ± 7
This represents the exact answer
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3
...
x 2 + 6 x − 11 = 0
Example:
**Important: If a ≠ 1 , divide all terms by “a” before proceeding to the next steps
...
Decimal approximations can be found using a
calculator
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QUADRATIC FORMULA
Any quadratic equation of the form ax 2 + bx + c = 0, where a ≠ 0 can be solved for both real and
imaginary solutions using the quadratic formula:
x=
− b ± b 2 − 4ac
2a
x 2 + 6 x − 11 = 0
Example:
( a = 1,
b = 6,
c = −11)
Substitute values into the quadratic formula:
− 6 ± 62 − 4(1)(−11)
x=
2(1)
x=
−6±4 5
2
→
→
x=
− 6 ± 36 + 44
2
→
x=
− 6 ± 80
2
simplify the radical
x = −3 ± 2 5 This is the final simplified EXACT answer
Title: Quadratic equations solutions and formula
Description: Well described formulas which can make an amature student understand properly
Description: Well described formulas which can make an amature student understand properly